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Flashcards for JEE Chemistry - Solutions Class 12

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Solutions
Flash cards
Page 2


Solutions
Flash cards
Concentration Terms (Continued)
1) % Concentration :
= weight of solute/100 g of solution. 
·· It does not change on changing temperature.
Ex. 10% w/w urea solution
= 10 gm of urea is present in 100 gm of solution.
= 10 gm of urea is present in 90 gm of water.
Page 3


Solutions
Flash cards
Concentration Terms (Continued)
1) % Concentration :
= weight of solute/100 g of solution. 
·· It does not change on changing temperature.
Ex. 10% w/w urea solution
= 10 gm of urea is present in 100 gm of solution.
= 10 gm of urea is present in 90 gm of water.
Concentration Terms (Continued)
1) % Concentration:
• % wt/vol (w/v)
% w/v = wt. of solute/100 ml of solution
It changes on changing temperature.
Ex. 10% (w/v) urea solution = 10 gm of urea is present in 100 mL of solution. But
not 10 gm of urea present in 90 ml of water.
For dilute solution : vol. solution = vol. solvent.
Page 4


Solutions
Flash cards
Concentration Terms (Continued)
1) % Concentration :
= weight of solute/100 g of solution. 
·· It does not change on changing temperature.
Ex. 10% w/w urea solution
= 10 gm of urea is present in 100 gm of solution.
= 10 gm of urea is present in 90 gm of water.
Concentration Terms (Continued)
1) % Concentration:
• % wt/vol (w/v)
% w/v = wt. of solute/100 ml of solution
It changes on changing temperature.
Ex. 10% (w/v) urea solution = 10 gm of urea is present in 100 mL of solution. But
not 10 gm of urea present in 90 ml of water.
For dilute solution : vol. solution = vol. solvent.
Concentration Terms (Continued)
1) % Concentration :
• % v/v
If both solute & solvent are liquids = volume in (mL) of solute per 100 mL of 
solution.
Ex. 10% v/v alcohol ethanol aq solution = 10 ml of ethanol in 100 ml of solution.
?10 ml of C
2
H
5
OH in 90 ml of H
2
O
Page 5


Solutions
Flash cards
Concentration Terms (Continued)
1) % Concentration :
= weight of solute/100 g of solution. 
·· It does not change on changing temperature.
Ex. 10% w/w urea solution
= 10 gm of urea is present in 100 gm of solution.
= 10 gm of urea is present in 90 gm of water.
Concentration Terms (Continued)
1) % Concentration:
• % wt/vol (w/v)
% w/v = wt. of solute/100 ml of solution
It changes on changing temperature.
Ex. 10% (w/v) urea solution = 10 gm of urea is present in 100 mL of solution. But
not 10 gm of urea present in 90 ml of water.
For dilute solution : vol. solution = vol. solvent.
Concentration Terms (Continued)
1) % Concentration :
• % v/v
If both solute & solvent are liquids = volume in (mL) of solute per 100 mL of 
solution.
Ex. 10% v/v alcohol ethanol aq solution = 10 ml of ethanol in 100 ml of solution.
?10 ml of C
2
H
5
OH in 90 ml of H
2
O
Concentration Terms (Continued)
2) Strength of solution in g/L :
Weight of solute (in gram) per litre (1000mL) of solution.
Ex. 10% (w/v) sucrose solution then specify its conc. in gm/L
100 mL ……. 10 gm
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FAQs on Flashcards for JEE Chemistry - Solutions Class 12

1. What is the solution to the given problem?
Ans. The solution to the given problem can be found by carefully analyzing the information provided in the article and applying the necessary steps or methods mentioned.
2. How can I approach solving this problem effectively?
Ans. To approach solving this problem effectively, it is recommended to break it down into smaller, manageable tasks. This can help in identifying the core issues and developing a step-by-step plan to address them.
3. Are there any alternative solutions to consider?
Ans. Yes, there may be alternative solutions to consider depending on the specific problem and its context. It is always beneficial to explore multiple approaches and evaluate their potential effectiveness before settling on a particular solution.
4. What are some common challenges that may arise during the implementation of the solution?
Ans. Some common challenges that may arise during the implementation of the solution include resource constraints, resistance to change, lack of support or cooperation from stakeholders, and unforeseen obstacles. It is important to anticipate these challenges and develop strategies to overcome them.
5. How can I evaluate the success of the implemented solution?
Ans. The success of the implemented solution can be evaluated by measuring its impact on the problem it aimed to solve. This can be done through careful monitoring and analysis of relevant metrics or indicators. Additionally, gathering feedback from stakeholders and assessing their satisfaction or perceived improvement can also provide valuable insights into the success of the solution.
150 videos|378 docs|213 tests
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