Maharashtra: State Level Solutions (SAT) - 2015-16

 Page 1


 
NTSE SAT ANSWER 2015
1. 2 
2. 1 
3. 4 
4. 3 
5. 2 
6. 1 
7. 3 
8. 4 
9. No Solution 
10. 1 
11. 3  
12. 2 
13. 2 
14. 2 
15. 2 
16. 2 
17. 4 
18.  1 
19. 1 
20. 3 
21. 2 
22. 3 
23. 1  
24. 2 
25. 2 
26. 2 
27.      1    
28.   2  
29. 1   
30.   2  
 31.  3  
32.  2 
33.  1 
34. 4  
35.  3  
36.  3 
37.  1  
38.   2 
39.  1 
40.  2  
81. 1 
82. 2 
83. 2 
84. 4 
85. 2 
86. 3 
87. 4 
88. 2 
89. 4 
90. 1 
91. 1 
92. wrong que. 
93. 2 
94. 3 
95. 2 
96. 3 
97. 1 
98. 2 
99. 1 
100. 3
 
PHYSICS SOLUTIONS 
1. (2) 
Solution: 
 Phase 
  
2. (1) 
Solution. 
 Zero, avg of random velocity (motion) is zero here  
3. 4 
Solution. 
 Alternating current. 
 
4. 3 
Solution. 
 Rayleigh scattering has dependence on size of particle as well as  wavelength of light. 
 
5. 2 
Solution. 
 Let speed in air = V 
 In the medium = 0.6 V 
 ?refractive index of medium w.r.t. air 
15
0.6 3
1.67
= =
=
 
 
6. 1 
Solution. 
 Thicknening  of eye lens ? move stressed eye  
 Focal length decreases ? cilliary muscle contract 
 I – B – i 
 
7. 3 
Solution. 
 Hydrogen ion ? proton 
 net flow is 3 x 1 x 10
18
 electrons travelling left  
 
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×= 
 
8. 4 
Solution. 
 Tangent of field line gives local direction. 
 
9. No Solution 
Solution. 
 Tap key to keep circuit open  I – C – iv 
 Ammeter to be connected in series  II – A – i 
 Voltmeter to be connected in parallel. III – d – ii 
 Galvenometer detects presence of current  IV – b – iii 
Page 2


 
NTSE SAT ANSWER 2015
1. 2 
2. 1 
3. 4 
4. 3 
5. 2 
6. 1 
7. 3 
8. 4 
9. No Solution 
10. 1 
11. 3  
12. 2 
13. 2 
14. 2 
15. 2 
16. 2 
17. 4 
18.  1 
19. 1 
20. 3 
21. 2 
22. 3 
23. 1  
24. 2 
25. 2 
26. 2 
27.      1    
28.   2  
29. 1   
30.   2  
 31.  3  
32.  2 
33.  1 
34. 4  
35.  3  
36.  3 
37.  1  
38.   2 
39.  1 
40.  2  
81. 1 
82. 2 
83. 2 
84. 4 
85. 2 
86. 3 
87. 4 
88. 2 
89. 4 
90. 1 
91. 1 
92. wrong que. 
93. 2 
94. 3 
95. 2 
96. 3 
97. 1 
98. 2 
99. 1 
100. 3
 
PHYSICS SOLUTIONS 
1. (2) 
Solution: 
 Phase 
  
2. (1) 
Solution. 
 Zero, avg of random velocity (motion) is zero here  
3. 4 
Solution. 
 Alternating current. 
 
4. 3 
Solution. 
 Rayleigh scattering has dependence on size of particle as well as  wavelength of light. 
 
5. 2 
Solution. 
 Let speed in air = V 
 In the medium = 0.6 V 
 ?refractive index of medium w.r.t. air 
15
0.6 3
1.67
= =
=
 
 
6. 1 
Solution. 
 Thicknening  of eye lens ? move stressed eye  
 Focal length decreases ? cilliary muscle contract 
 I – B – i 
 
7. 3 
Solution. 
 Hydrogen ion ? proton 
 net flow is 3 x 1 x 10
18
 electrons travelling left  
 
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×= 
 
8. 4 
Solution. 
 Tangent of field line gives local direction. 
 
9. No Solution 
Solution. 
 Tap key to keep circuit open  I – C – iv 
 Ammeter to be connected in series  II – A – i 
 Voltmeter to be connected in parallel. III – d – ii 
 Galvenometer detects presence of current  IV – b – iii 
 No choice is correct 
 In option 4 ? ii & i is replaced, to be it correct. 
 
10. 1 
Solution. 
 Virtual image can be produced by other optical insinemt. 
 
11. 3.  
  
12. 2. 
 
Chemistry Solution  
14. NO of elements is 
 1
st
 period   -2    H-He     (1 – 2) 
 2
nd
 period   -8   Li-Ne     (3-10)  
 3
rd
 period   -8   Na-Ar    (11-18) 
 4
th
 period   -18  K-Kr     (19-36) 
 
 Answer – 2 
 
15. Antacids are used for indigestion 
 Ex - ( )
2
Mg OH 
 Answer – 2 
 
16. Mercury ore is cinnabar (Hg5) 
 Bauxite - 
23 2
Al O .2H O 
 Haematite - 
23
Fe O 
 Cinnabar – Hg5 
 Dolomite - 
33
MgCO .CaCO 
 
 Answer – 2 
 
17. 
32
KNO H O +
32
K NO H O
+-
??? + + 
 Temperature of solution falls endothermic reaction 
 
 Answer - 2 
 
18. Ammonium chloride is salt of weak base and strong acid 
 
4 42
NH OH HCl NH Cl H O + ??? + 
 
 Answer – 4 
 
19. 
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
 
 2-pentene or pent – 2-ene 
 Answer – 1 
 
20. Oxygen electron dot structure 
 
O
. .
. .
.
O
. .
.
.
.
.
.
 
 Oxygen – 8 - 
22 4
1s 2s 2p  ( 
0
6e s in valence shall) 
 
 Answer – 1 
 
21. Eka – Aluminium can form an oxide like 
 Aluminium  i e ( )
23 23
Ga O like Al O 
  
 Answer - 3 
  
 
22. Pure copper acts as cathode and impure copper acts as anode 
  
Page 3


 
NTSE SAT ANSWER 2015
1. 2 
2. 1 
3. 4 
4. 3 
5. 2 
6. 1 
7. 3 
8. 4 
9. No Solution 
10. 1 
11. 3  
12. 2 
13. 2 
14. 2 
15. 2 
16. 2 
17. 4 
18.  1 
19. 1 
20. 3 
21. 2 
22. 3 
23. 1  
24. 2 
25. 2 
26. 2 
27.      1    
28.   2  
29. 1   
30.   2  
 31.  3  
32.  2 
33.  1 
34. 4  
35.  3  
36.  3 
37.  1  
38.   2 
39.  1 
40.  2  
81. 1 
82. 2 
83. 2 
84. 4 
85. 2 
86. 3 
87. 4 
88. 2 
89. 4 
90. 1 
91. 1 
92. wrong que. 
93. 2 
94. 3 
95. 2 
96. 3 
97. 1 
98. 2 
99. 1 
100. 3
 
PHYSICS SOLUTIONS 
1. (2) 
Solution: 
 Phase 
  
2. (1) 
Solution. 
 Zero, avg of random velocity (motion) is zero here  
3. 4 
Solution. 
 Alternating current. 
 
4. 3 
Solution. 
 Rayleigh scattering has dependence on size of particle as well as  wavelength of light. 
 
5. 2 
Solution. 
 Let speed in air = V 
 In the medium = 0.6 V 
 ?refractive index of medium w.r.t. air 
15
0.6 3
1.67
= =
=
 
 
6. 1 
Solution. 
 Thicknening  of eye lens ? move stressed eye  
 Focal length decreases ? cilliary muscle contract 
 I – B – i 
 
7. 3 
Solution. 
 Hydrogen ion ? proton 
 net flow is 3 x 1 x 10
18
 electrons travelling left  
 
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×= 
 
8. 4 
Solution. 
 Tangent of field line gives local direction. 
 
9. No Solution 
Solution. 
 Tap key to keep circuit open  I – C – iv 
 Ammeter to be connected in series  II – A – i 
 Voltmeter to be connected in parallel. III – d – ii 
 Galvenometer detects presence of current  IV – b – iii 
 No choice is correct 
 In option 4 ? ii & i is replaced, to be it correct. 
 
10. 1 
Solution. 
 Virtual image can be produced by other optical insinemt. 
 
11. 3.  
  
12. 2. 
 
Chemistry Solution  
14. NO of elements is 
 1
st
 period   -2    H-He     (1 – 2) 
 2
nd
 period   -8   Li-Ne     (3-10)  
 3
rd
 period   -8   Na-Ar    (11-18) 
 4
th
 period   -18  K-Kr     (19-36) 
 
 Answer – 2 
 
15. Antacids are used for indigestion 
 Ex - ( )
2
Mg OH 
 Answer – 2 
 
16. Mercury ore is cinnabar (Hg5) 
 Bauxite - 
23 2
Al O .2H O 
 Haematite - 
23
Fe O 
 Cinnabar – Hg5 
 Dolomite - 
33
MgCO .CaCO 
 
 Answer – 2 
 
17. 
32
KNO H O +
32
K NO H O
+-
??? + + 
 Temperature of solution falls endothermic reaction 
 
 Answer - 2 
 
18. Ammonium chloride is salt of weak base and strong acid 
 
4 42
NH OH HCl NH Cl H O + ??? + 
 
 Answer – 4 
 
19. 
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
 
 2-pentene or pent – 2-ene 
 Answer – 1 
 
20. Oxygen electron dot structure 
 
O
. .
. .
.
O
. .
.
.
.
.
.
 
 Oxygen – 8 - 
22 4
1s 2s 2p  ( 
0
6e s in valence shall) 
 
 Answer – 1 
 
21. Eka – Aluminium can form an oxide like 
 Aluminium  i e ( )
23 23
Ga O like Al O 
  
 Answer - 3 
  
 
22. Pure copper acts as cathode and impure copper acts as anode 
  
 Answer - 2 
 
23. (1) 
2 2
CuO H H O Cu + ??? +  (single displacement) 
 (2) 
44
Zn CuSO ZnSO Cu + ??? +
 
(single displacement) 
 (3) 
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement) 
 (4) 
22
Zn 2HCl 2nCl H + ??? + (Single displacement) 
  
 Answer – 3 
 
24. 
2
HO
 
 2: 16 = 1:8
 
 Answer – 1  
 
25. In Black and white photography AgBr is involved. 
 2 AgBr 
Sunlight
2
2Ag Br ? ??? ? +
 
  
 Answer - 2 
 
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? + 
 (2) ( )
22
Cu 2HCl CuCl H Do not + ??? + 
 (3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? + 
 (4) 
22
Fe 2HCl FeCl H + ??? +
               (Occurs) 
  
 This is based on metal activity series 
 Answer – 2 
Biology : 
27.      (1)    
 Mushroom 
 Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,  
  Cuscuta exhibit parasitic mode of nutrition. 
28.   (2)  
 Right atrium 
 Explanation:  Right atrium receives deoxygenated blood 
 Left atrium receives oxygenated blood from the lungs 
 Right ventricle pumps blood to the lungs 
 Left ventricle pumps blood into aorta which supplies blood to the various regions of the body 
29.  (1)   
 Drosera          
  
30.   (2)  
 Hydra  
 Explanation Nerve net is primitive stage of development od nervous system  
 31.  (3)  
  Bryophyllum 
Page 4


 
NTSE SAT ANSWER 2015
1. 2 
2. 1 
3. 4 
4. 3 
5. 2 
6. 1 
7. 3 
8. 4 
9. No Solution 
10. 1 
11. 3  
12. 2 
13. 2 
14. 2 
15. 2 
16. 2 
17. 4 
18.  1 
19. 1 
20. 3 
21. 2 
22. 3 
23. 1  
24. 2 
25. 2 
26. 2 
27.      1    
28.   2  
29. 1   
30.   2  
 31.  3  
32.  2 
33.  1 
34. 4  
35.  3  
36.  3 
37.  1  
38.   2 
39.  1 
40.  2  
81. 1 
82. 2 
83. 2 
84. 4 
85. 2 
86. 3 
87. 4 
88. 2 
89. 4 
90. 1 
91. 1 
92. wrong que. 
93. 2 
94. 3 
95. 2 
96. 3 
97. 1 
98. 2 
99. 1 
100. 3
 
PHYSICS SOLUTIONS 
1. (2) 
Solution: 
 Phase 
  
2. (1) 
Solution. 
 Zero, avg of random velocity (motion) is zero here  
3. 4 
Solution. 
 Alternating current. 
 
4. 3 
Solution. 
 Rayleigh scattering has dependence on size of particle as well as  wavelength of light. 
 
5. 2 
Solution. 
 Let speed in air = V 
 In the medium = 0.6 V 
 ?refractive index of medium w.r.t. air 
15
0.6 3
1.67
= =
=
 
 
6. 1 
Solution. 
 Thicknening  of eye lens ? move stressed eye  
 Focal length decreases ? cilliary muscle contract 
 I – B – i 
 
7. 3 
Solution. 
 Hydrogen ion ? proton 
 net flow is 3 x 1 x 10
18
 electrons travelling left  
 
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×= 
 
8. 4 
Solution. 
 Tangent of field line gives local direction. 
 
9. No Solution 
Solution. 
 Tap key to keep circuit open  I – C – iv 
 Ammeter to be connected in series  II – A – i 
 Voltmeter to be connected in parallel. III – d – ii 
 Galvenometer detects presence of current  IV – b – iii 
 No choice is correct 
 In option 4 ? ii & i is replaced, to be it correct. 
 
10. 1 
Solution. 
 Virtual image can be produced by other optical insinemt. 
 
11. 3.  
  
12. 2. 
 
Chemistry Solution  
14. NO of elements is 
 1
st
 period   -2    H-He     (1 – 2) 
 2
nd
 period   -8   Li-Ne     (3-10)  
 3
rd
 period   -8   Na-Ar    (11-18) 
 4
th
 period   -18  K-Kr     (19-36) 
 
 Answer – 2 
 
15. Antacids are used for indigestion 
 Ex - ( )
2
Mg OH 
 Answer – 2 
 
16. Mercury ore is cinnabar (Hg5) 
 Bauxite - 
23 2
Al O .2H O 
 Haematite - 
23
Fe O 
 Cinnabar – Hg5 
 Dolomite - 
33
MgCO .CaCO 
 
 Answer – 2 
 
17. 
32
KNO H O +
32
K NO H O
+-
??? + + 
 Temperature of solution falls endothermic reaction 
 
 Answer - 2 
 
18. Ammonium chloride is salt of weak base and strong acid 
 
4 42
NH OH HCl NH Cl H O + ??? + 
 
 Answer – 4 
 
19. 
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
 
 2-pentene or pent – 2-ene 
 Answer – 1 
 
20. Oxygen electron dot structure 
 
O
. .
. .
.
O
. .
.
.
.
.
.
 
 Oxygen – 8 - 
22 4
1s 2s 2p  ( 
0
6e s in valence shall) 
 
 Answer – 1 
 
21. Eka – Aluminium can form an oxide like 
 Aluminium  i e ( )
23 23
Ga O like Al O 
  
 Answer - 3 
  
 
22. Pure copper acts as cathode and impure copper acts as anode 
  
 Answer - 2 
 
23. (1) 
2 2
CuO H H O Cu + ??? +  (single displacement) 
 (2) 
44
Zn CuSO ZnSO Cu + ??? +
 
(single displacement) 
 (3) 
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement) 
 (4) 
22
Zn 2HCl 2nCl H + ??? + (Single displacement) 
  
 Answer – 3 
 
24. 
2
HO
 
 2: 16 = 1:8
 
 Answer – 1  
 
25. In Black and white photography AgBr is involved. 
 2 AgBr 
Sunlight
2
2Ag Br ? ??? ? +
 
  
 Answer - 2 
 
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? + 
 (2) ( )
22
Cu 2HCl CuCl H Do not + ??? + 
 (3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? + 
 (4) 
22
Fe 2HCl FeCl H + ??? +
               (Occurs) 
  
 This is based on metal activity series 
 Answer – 2 
Biology : 
27.      (1)    
 Mushroom 
 Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,  
  Cuscuta exhibit parasitic mode of nutrition. 
28.   (2)  
 Right atrium 
 Explanation:  Right atrium receives deoxygenated blood 
 Left atrium receives oxygenated blood from the lungs 
 Right ventricle pumps blood to the lungs 
 Left ventricle pumps blood into aorta which supplies blood to the various regions of the body 
29.  (1)   
 Drosera          
  
30.   (2)  
 Hydra  
 Explanation Nerve net is primitive stage of development od nervous system  
 31.  (3)  
  Bryophyllum 
  
 
32.  (2) 
  two male gametes 
 Explanation :  The pollen tube contains 2 male gametes and one tube nucleus which generates the pollen  
tube 
33.  (1) 
 Four  
 Explanation: Considering a cross TtYy x TtYy , the groups of phenotypic characters are (TY, ty, Ty, tY ) 
34. (4)  
  
Fish                Amphibians         Reptiles        Birds           Mammals 
 According to origin, identify the secondary air pollutants 
35.  (3)  
 Smoke 
36.  (3) 45 
37.  (1) cuboidal epithelium  
38.  ( 2)  species 
39.  (1) estrogen 
40.  (2) bile juice   ( pancreas – pancreatic juice, stomach- gastric juice, bile juice – liver and intestine  – 
various digestive juice) 
 
 
MATHEMATICS  Solution 
81. (1) 
Hint. 
{ }
{ }
1 3 5 .....to365 terms
365
2 (364 2
2
365
2 728
2
365
730
2
365 365
133225
+++
= + ×
= +
= ×
= ×
=
 
82. (2) 
 
Let x price of one apple
y price of one guava
ATQ
19x 11y 482 0
11x 19y 418 0
by cross multiplicate
x y1
4598 9158 5302 7942 361 121
4560 2640
x 19 & y 11
240 270
Hence x y 8.
=
=
+- =
+- =
= =
- + -+ -
?= = = =
-=
 
83. (2) 
Page 5


 
NTSE SAT ANSWER 2015
1. 2 
2. 1 
3. 4 
4. 3 
5. 2 
6. 1 
7. 3 
8. 4 
9. No Solution 
10. 1 
11. 3  
12. 2 
13. 2 
14. 2 
15. 2 
16. 2 
17. 4 
18.  1 
19. 1 
20. 3 
21. 2 
22. 3 
23. 1  
24. 2 
25. 2 
26. 2 
27.      1    
28.   2  
29. 1   
30.   2  
 31.  3  
32.  2 
33.  1 
34. 4  
35.  3  
36.  3 
37.  1  
38.   2 
39.  1 
40.  2  
81. 1 
82. 2 
83. 2 
84. 4 
85. 2 
86. 3 
87. 4 
88. 2 
89. 4 
90. 1 
91. 1 
92. wrong que. 
93. 2 
94. 3 
95. 2 
96. 3 
97. 1 
98. 2 
99. 1 
100. 3
 
PHYSICS SOLUTIONS 
1. (2) 
Solution: 
 Phase 
  
2. (1) 
Solution. 
 Zero, avg of random velocity (motion) is zero here  
3. 4 
Solution. 
 Alternating current. 
 
4. 3 
Solution. 
 Rayleigh scattering has dependence on size of particle as well as  wavelength of light. 
 
5. 2 
Solution. 
 Let speed in air = V 
 In the medium = 0.6 V 
 ?refractive index of medium w.r.t. air 
15
0.6 3
1.67
= =
=
 
 
6. 1 
Solution. 
 Thicknening  of eye lens ? move stressed eye  
 Focal length decreases ? cilliary muscle contract 
 I – B – i 
 
7. 3 
Solution. 
 Hydrogen ion ? proton 
 net flow is 3 x 1 x 10
18
 electrons travelling left  
 
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×= 
 
8. 4 
Solution. 
 Tangent of field line gives local direction. 
 
9. No Solution 
Solution. 
 Tap key to keep circuit open  I – C – iv 
 Ammeter to be connected in series  II – A – i 
 Voltmeter to be connected in parallel. III – d – ii 
 Galvenometer detects presence of current  IV – b – iii 
 No choice is correct 
 In option 4 ? ii & i is replaced, to be it correct. 
 
10. 1 
Solution. 
 Virtual image can be produced by other optical insinemt. 
 
11. 3.  
  
12. 2. 
 
Chemistry Solution  
14. NO of elements is 
 1
st
 period   -2    H-He     (1 – 2) 
 2
nd
 period   -8   Li-Ne     (3-10)  
 3
rd
 period   -8   Na-Ar    (11-18) 
 4
th
 period   -18  K-Kr     (19-36) 
 
 Answer – 2 
 
15. Antacids are used for indigestion 
 Ex - ( )
2
Mg OH 
 Answer – 2 
 
16. Mercury ore is cinnabar (Hg5) 
 Bauxite - 
23 2
Al O .2H O 
 Haematite - 
23
Fe O 
 Cinnabar – Hg5 
 Dolomite - 
33
MgCO .CaCO 
 
 Answer – 2 
 
17. 
32
KNO H O +
32
K NO H O
+-
??? + + 
 Temperature of solution falls endothermic reaction 
 
 Answer - 2 
 
18. Ammonium chloride is salt of weak base and strong acid 
 
4 42
NH OH HCl NH Cl H O + ??? + 
 
 Answer – 4 
 
19. 
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
 
 2-pentene or pent – 2-ene 
 Answer – 1 
 
20. Oxygen electron dot structure 
 
O
. .
. .
.
O
. .
.
.
.
.
.
 
 Oxygen – 8 - 
22 4
1s 2s 2p  ( 
0
6e s in valence shall) 
 
 Answer – 1 
 
21. Eka – Aluminium can form an oxide like 
 Aluminium  i e ( )
23 23
Ga O like Al O 
  
 Answer - 3 
  
 
22. Pure copper acts as cathode and impure copper acts as anode 
  
 Answer - 2 
 
23. (1) 
2 2
CuO H H O Cu + ??? +  (single displacement) 
 (2) 
44
Zn CuSO ZnSO Cu + ??? +
 
(single displacement) 
 (3) 
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement) 
 (4) 
22
Zn 2HCl 2nCl H + ??? + (Single displacement) 
  
 Answer – 3 
 
24. 
2
HO
 
 2: 16 = 1:8
 
 Answer – 1  
 
25. In Black and white photography AgBr is involved. 
 2 AgBr 
Sunlight
2
2Ag Br ? ??? ? +
 
  
 Answer - 2 
 
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? + 
 (2) ( )
22
Cu 2HCl CuCl H Do not + ??? + 
 (3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? + 
 (4) 
22
Fe 2HCl FeCl H + ??? +
               (Occurs) 
  
 This is based on metal activity series 
 Answer – 2 
Biology : 
27.      (1)    
 Mushroom 
 Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,  
  Cuscuta exhibit parasitic mode of nutrition. 
28.   (2)  
 Right atrium 
 Explanation:  Right atrium receives deoxygenated blood 
 Left atrium receives oxygenated blood from the lungs 
 Right ventricle pumps blood to the lungs 
 Left ventricle pumps blood into aorta which supplies blood to the various regions of the body 
29.  (1)   
 Drosera          
  
30.   (2)  
 Hydra  
 Explanation Nerve net is primitive stage of development od nervous system  
 31.  (3)  
  Bryophyllum 
  
 
32.  (2) 
  two male gametes 
 Explanation :  The pollen tube contains 2 male gametes and one tube nucleus which generates the pollen  
tube 
33.  (1) 
 Four  
 Explanation: Considering a cross TtYy x TtYy , the groups of phenotypic characters are (TY, ty, Ty, tY ) 
34. (4)  
  
Fish                Amphibians         Reptiles        Birds           Mammals 
 According to origin, identify the secondary air pollutants 
35.  (3)  
 Smoke 
36.  (3) 45 
37.  (1) cuboidal epithelium  
38.  ( 2)  species 
39.  (1) estrogen 
40.  (2) bile juice   ( pancreas – pancreatic juice, stomach- gastric juice, bile juice – liver and intestine  – 
various digestive juice) 
 
 
MATHEMATICS  Solution 
81. (1) 
Hint. 
{ }
{ }
1 3 5 .....to365 terms
365
2 (364 2
2
365
2 728
2
365
730
2
365 365
133225
+++
= + ×
= +
= ×
= ×
=
 
82. (2) 
 
Let x price of one apple
y price of one guava
ATQ
19x 11y 482 0
11x 19y 418 0
by cross multiplicate
x y1
4598 9158 5302 7942 361 121
4560 2640
x 19 & y 11
240 270
Hence x y 8.
=
=
+- =
+- =
= =
- + -+ -
?= = = =
-=
 
83. (2) 
 Given one root is 
25 +
 
 
?
other root is 
25 -
 
 Hence, requires equation  
 
{ }
2
2
x (2 5) (2 5) x (2 5)(2 5) 0
x 4x 1 0
- + +- ++ - =
? - -=
 
84. (4) 
 From formulae,  
 
x 15 x
97.5 94.5 h
2(x 15) x (x 5)
15 3h
3h
25 5
h5
upper limit 94.5 5 99.5
+- ??
= +
??
+ - - +
??
??
?= =
??
??
?=
? = + =
 
85. (2) 
 By expanding the determinants, we get 
 
49 18 30 4b
4(a b) 48
a b 12
ans.2
-= -
? +=
?+=
 
86. (3) 
 Given 
22
22
a6 9,b6 5
2(a b ) 2.2(6 5) 4 11 44
5ab 5 (1) 5
2(a b ) 5ab 44 5 39.
= += -
? + = + = ×=
= ·=
? + - = -=
 
 
87. (4) 
 Let the total no. of swan = x 
 ATQ. 
 
2
7
X2 X
2
7x
x2
2
2x 4 7 x
4x 65x 16 0
x 16
+ =
? -=
? - =
? - + =
?=
 
 
88. (2)