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Page 1
NTSE SAT ANSWER 2015
1. 2
2. 1
3. 4
4. 3
5. 2
6. 1
7. 3
8. 4
9. No Solution
10. 1
11. 3
12. 2
13. 2
14. 2
15. 2
16. 2
17. 4
18. 1
19. 1
20. 3
21. 2
22. 3
23. 1
24. 2
25. 2
26. 2
27. 1
28. 2
29. 1
30. 2
31. 3
32. 2
33. 1
34. 4
35. 3
36. 3
37. 1
38. 2
39. 1
40. 2
81. 1
82. 2
83. 2
84. 4
85. 2
86. 3
87. 4
88. 2
89. 4
90. 1
91. 1
92. wrong que.
93. 2
94. 3
95. 2
96. 3
97. 1
98. 2
99. 1
100. 3
PHYSICS SOLUTIONS
1. (2)
Solution:
Phase
2. (1)
Solution.
Zero, avg of random velocity (motion) is zero here
3. 4
Solution.
Alternating current.
4. 3
Solution.
Rayleigh scattering has dependence on size of particle as well as wavelength of light.
5. 2
Solution.
Let speed in air = V
In the medium = 0.6 V
?refractive index of medium w.r.t. air
15
0.6 3
1.67
= =
=
6. 1
Solution.
Thicknening of eye lens ? move stressed eye
Focal length decreases ? cilliary muscle contract
I – B – i
7. 3
Solution.
Hydrogen ion ? proton
net flow is 3 x 1 x 10
18
electrons travelling left
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×=
8. 4
Solution.
Tangent of field line gives local direction.
9. No Solution
Solution.
Tap key to keep circuit open I – C – iv
Ammeter to be connected in series II – A – i
Voltmeter to be connected in parallel. III – d – ii
Galvenometer detects presence of current IV – b – iii
Page 2
NTSE SAT ANSWER 2015
1. 2
2. 1
3. 4
4. 3
5. 2
6. 1
7. 3
8. 4
9. No Solution
10. 1
11. 3
12. 2
13. 2
14. 2
15. 2
16. 2
17. 4
18. 1
19. 1
20. 3
21. 2
22. 3
23. 1
24. 2
25. 2
26. 2
27. 1
28. 2
29. 1
30. 2
31. 3
32. 2
33. 1
34. 4
35. 3
36. 3
37. 1
38. 2
39. 1
40. 2
81. 1
82. 2
83. 2
84. 4
85. 2
86. 3
87. 4
88. 2
89. 4
90. 1
91. 1
92. wrong que.
93. 2
94. 3
95. 2
96. 3
97. 1
98. 2
99. 1
100. 3
PHYSICS SOLUTIONS
1. (2)
Solution:
Phase
2. (1)
Solution.
Zero, avg of random velocity (motion) is zero here
3. 4
Solution.
Alternating current.
4. 3
Solution.
Rayleigh scattering has dependence on size of particle as well as wavelength of light.
5. 2
Solution.
Let speed in air = V
In the medium = 0.6 V
?refractive index of medium w.r.t. air
15
0.6 3
1.67
= =
=
6. 1
Solution.
Thicknening of eye lens ? move stressed eye
Focal length decreases ? cilliary muscle contract
I – B – i
7. 3
Solution.
Hydrogen ion ? proton
net flow is 3 x 1 x 10
18
electrons travelling left
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×=
8. 4
Solution.
Tangent of field line gives local direction.
9. No Solution
Solution.
Tap key to keep circuit open I – C – iv
Ammeter to be connected in series II – A – i
Voltmeter to be connected in parallel. III – d – ii
Galvenometer detects presence of current IV – b – iii
No choice is correct
In option 4 ? ii & i is replaced, to be it correct.
10. 1
Solution.
Virtual image can be produced by other optical insinemt.
11. 3.
12. 2.
Chemistry Solution
14. NO of elements is
1
st
period -2 H-He (1 – 2)
2
nd
period -8 Li-Ne (3-10)
3
rd
period -8 Na-Ar (11-18)
4
th
period -18 K-Kr (19-36)
Answer – 2
15. Antacids are used for indigestion
Ex - ( )
2
Mg OH
Answer – 2
16. Mercury ore is cinnabar (Hg5)
Bauxite -
23 2
Al O .2H O
Haematite -
23
Fe O
Cinnabar – Hg5
Dolomite -
33
MgCO .CaCO
Answer – 2
17.
32
KNO H O +
32
K NO H O
+-
??? + +
Temperature of solution falls endothermic reaction
Answer - 2
18. Ammonium chloride is salt of weak base and strong acid
4 42
NH OH HCl NH Cl H O + ??? +
Answer – 4
19.
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
2-pentene or pent – 2-ene
Answer – 1
20. Oxygen electron dot structure
O
. .
. .
.
O
. .
.
.
.
.
.
Oxygen – 8 -
22 4
1s 2s 2p (
0
6e s in valence shall)
Answer – 1
21. Eka – Aluminium can form an oxide like
Aluminium i e ( )
23 23
Ga O like Al O
Answer - 3
22. Pure copper acts as cathode and impure copper acts as anode
Page 3
NTSE SAT ANSWER 2015
1. 2
2. 1
3. 4
4. 3
5. 2
6. 1
7. 3
8. 4
9. No Solution
10. 1
11. 3
12. 2
13. 2
14. 2
15. 2
16. 2
17. 4
18. 1
19. 1
20. 3
21. 2
22. 3
23. 1
24. 2
25. 2
26. 2
27. 1
28. 2
29. 1
30. 2
31. 3
32. 2
33. 1
34. 4
35. 3
36. 3
37. 1
38. 2
39. 1
40. 2
81. 1
82. 2
83. 2
84. 4
85. 2
86. 3
87. 4
88. 2
89. 4
90. 1
91. 1
92. wrong que.
93. 2
94. 3
95. 2
96. 3
97. 1
98. 2
99. 1
100. 3
PHYSICS SOLUTIONS
1. (2)
Solution:
Phase
2. (1)
Solution.
Zero, avg of random velocity (motion) is zero here
3. 4
Solution.
Alternating current.
4. 3
Solution.
Rayleigh scattering has dependence on size of particle as well as wavelength of light.
5. 2
Solution.
Let speed in air = V
In the medium = 0.6 V
?refractive index of medium w.r.t. air
15
0.6 3
1.67
= =
=
6. 1
Solution.
Thicknening of eye lens ? move stressed eye
Focal length decreases ? cilliary muscle contract
I – B – i
7. 3
Solution.
Hydrogen ion ? proton
net flow is 3 x 1 x 10
18
electrons travelling left
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×=
8. 4
Solution.
Tangent of field line gives local direction.
9. No Solution
Solution.
Tap key to keep circuit open I – C – iv
Ammeter to be connected in series II – A – i
Voltmeter to be connected in parallel. III – d – ii
Galvenometer detects presence of current IV – b – iii
No choice is correct
In option 4 ? ii & i is replaced, to be it correct.
10. 1
Solution.
Virtual image can be produced by other optical insinemt.
11. 3.
12. 2.
Chemistry Solution
14. NO of elements is
1
st
period -2 H-He (1 – 2)
2
nd
period -8 Li-Ne (3-10)
3
rd
period -8 Na-Ar (11-18)
4
th
period -18 K-Kr (19-36)
Answer – 2
15. Antacids are used for indigestion
Ex - ( )
2
Mg OH
Answer – 2
16. Mercury ore is cinnabar (Hg5)
Bauxite -
23 2
Al O .2H O
Haematite -
23
Fe O
Cinnabar – Hg5
Dolomite -
33
MgCO .CaCO
Answer – 2
17.
32
KNO H O +
32
K NO H O
+-
??? + +
Temperature of solution falls endothermic reaction
Answer - 2
18. Ammonium chloride is salt of weak base and strong acid
4 42
NH OH HCl NH Cl H O + ??? +
Answer – 4
19.
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
2-pentene or pent – 2-ene
Answer – 1
20. Oxygen electron dot structure
O
. .
. .
.
O
. .
.
.
.
.
.
Oxygen – 8 -
22 4
1s 2s 2p (
0
6e s in valence shall)
Answer – 1
21. Eka – Aluminium can form an oxide like
Aluminium i e ( )
23 23
Ga O like Al O
Answer - 3
22. Pure copper acts as cathode and impure copper acts as anode
Answer - 2
23. (1)
2 2
CuO H H O Cu + ??? + (single displacement)
(2)
44
Zn CuSO ZnSO Cu + ??? +
(single displacement)
(3)
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement)
(4)
22
Zn 2HCl 2nCl H + ??? + (Single displacement)
Answer – 3
24.
2
HO
2: 16 = 1:8
Answer – 1
25. In Black and white photography AgBr is involved.
2 AgBr
Sunlight
2
2Ag Br ? ??? ? +
Answer - 2
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? +
(2) ( )
22
Cu 2HCl CuCl H Do not + ??? +
(3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? +
(4)
22
Fe 2HCl FeCl H + ??? +
(Occurs)
This is based on metal activity series
Answer – 2
Biology :
27. (1)
Mushroom
Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,
Cuscuta exhibit parasitic mode of nutrition.
28. (2)
Right atrium
Explanation: Right atrium receives deoxygenated blood
Left atrium receives oxygenated blood from the lungs
Right ventricle pumps blood to the lungs
Left ventricle pumps blood into aorta which supplies blood to the various regions of the body
29. (1)
Drosera
30. (2)
Hydra
Explanation Nerve net is primitive stage of development od nervous system
31. (3)
Bryophyllum
Page 4
NTSE SAT ANSWER 2015
1. 2
2. 1
3. 4
4. 3
5. 2
6. 1
7. 3
8. 4
9. No Solution
10. 1
11. 3
12. 2
13. 2
14. 2
15. 2
16. 2
17. 4
18. 1
19. 1
20. 3
21. 2
22. 3
23. 1
24. 2
25. 2
26. 2
27. 1
28. 2
29. 1
30. 2
31. 3
32. 2
33. 1
34. 4
35. 3
36. 3
37. 1
38. 2
39. 1
40. 2
81. 1
82. 2
83. 2
84. 4
85. 2
86. 3
87. 4
88. 2
89. 4
90. 1
91. 1
92. wrong que.
93. 2
94. 3
95. 2
96. 3
97. 1
98. 2
99. 1
100. 3
PHYSICS SOLUTIONS
1. (2)
Solution:
Phase
2. (1)
Solution.
Zero, avg of random velocity (motion) is zero here
3. 4
Solution.
Alternating current.
4. 3
Solution.
Rayleigh scattering has dependence on size of particle as well as wavelength of light.
5. 2
Solution.
Let speed in air = V
In the medium = 0.6 V
?refractive index of medium w.r.t. air
15
0.6 3
1.67
= =
=
6. 1
Solution.
Thicknening of eye lens ? move stressed eye
Focal length decreases ? cilliary muscle contract
I – B – i
7. 3
Solution.
Hydrogen ion ? proton
net flow is 3 x 1 x 10
18
electrons travelling left
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×=
8. 4
Solution.
Tangent of field line gives local direction.
9. No Solution
Solution.
Tap key to keep circuit open I – C – iv
Ammeter to be connected in series II – A – i
Voltmeter to be connected in parallel. III – d – ii
Galvenometer detects presence of current IV – b – iii
No choice is correct
In option 4 ? ii & i is replaced, to be it correct.
10. 1
Solution.
Virtual image can be produced by other optical insinemt.
11. 3.
12. 2.
Chemistry Solution
14. NO of elements is
1
st
period -2 H-He (1 – 2)
2
nd
period -8 Li-Ne (3-10)
3
rd
period -8 Na-Ar (11-18)
4
th
period -18 K-Kr (19-36)
Answer – 2
15. Antacids are used for indigestion
Ex - ( )
2
Mg OH
Answer – 2
16. Mercury ore is cinnabar (Hg5)
Bauxite -
23 2
Al O .2H O
Haematite -
23
Fe O
Cinnabar – Hg5
Dolomite -
33
MgCO .CaCO
Answer – 2
17.
32
KNO H O +
32
K NO H O
+-
??? + +
Temperature of solution falls endothermic reaction
Answer - 2
18. Ammonium chloride is salt of weak base and strong acid
4 42
NH OH HCl NH Cl H O + ??? +
Answer – 4
19.
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
2-pentene or pent – 2-ene
Answer – 1
20. Oxygen electron dot structure
O
. .
. .
.
O
. .
.
.
.
.
.
Oxygen – 8 -
22 4
1s 2s 2p (
0
6e s in valence shall)
Answer – 1
21. Eka – Aluminium can form an oxide like
Aluminium i e ( )
23 23
Ga O like Al O
Answer - 3
22. Pure copper acts as cathode and impure copper acts as anode
Answer - 2
23. (1)
2 2
CuO H H O Cu + ??? + (single displacement)
(2)
44
Zn CuSO ZnSO Cu + ??? +
(single displacement)
(3)
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement)
(4)
22
Zn 2HCl 2nCl H + ??? + (Single displacement)
Answer – 3
24.
2
HO
2: 16 = 1:8
Answer – 1
25. In Black and white photography AgBr is involved.
2 AgBr
Sunlight
2
2Ag Br ? ??? ? +
Answer - 2
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? +
(2) ( )
22
Cu 2HCl CuCl H Do not + ??? +
(3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? +
(4)
22
Fe 2HCl FeCl H + ??? +
(Occurs)
This is based on metal activity series
Answer – 2
Biology :
27. (1)
Mushroom
Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,
Cuscuta exhibit parasitic mode of nutrition.
28. (2)
Right atrium
Explanation: Right atrium receives deoxygenated blood
Left atrium receives oxygenated blood from the lungs
Right ventricle pumps blood to the lungs
Left ventricle pumps blood into aorta which supplies blood to the various regions of the body
29. (1)
Drosera
30. (2)
Hydra
Explanation Nerve net is primitive stage of development od nervous system
31. (3)
Bryophyllum
32. (2)
two male gametes
Explanation : The pollen tube contains 2 male gametes and one tube nucleus which generates the pollen
tube
33. (1)
Four
Explanation: Considering a cross TtYy x TtYy , the groups of phenotypic characters are (TY, ty, Ty, tY )
34. (4)
Fish Amphibians Reptiles Birds Mammals
According to origin, identify the secondary air pollutants
35. (3)
Smoke
36. (3) 45
37. (1) cuboidal epithelium
38. ( 2) species
39. (1) estrogen
40. (2) bile juice ( pancreas – pancreatic juice, stomach- gastric juice, bile juice – liver and intestine –
various digestive juice)
MATHEMATICS Solution
81. (1)
Hint.
{ }
{ }
1 3 5 .....to365 terms
365
2 (364 2
2
365
2 728
2
365
730
2
365 365
133225
+++
= + ×
= +
= ×
= ×
=
82. (2)
Let x price of one apple
y price of one guava
ATQ
19x 11y 482 0
11x 19y 418 0
by cross multiplicate
x y1
4598 9158 5302 7942 361 121
4560 2640
x 19 & y 11
240 270
Hence x y 8.
=
=
+- =
+- =
= =
- + -+ -
?= = = =
-=
83. (2)
Page 5
NTSE SAT ANSWER 2015
1. 2
2. 1
3. 4
4. 3
5. 2
6. 1
7. 3
8. 4
9. No Solution
10. 1
11. 3
12. 2
13. 2
14. 2
15. 2
16. 2
17. 4
18. 1
19. 1
20. 3
21. 2
22. 3
23. 1
24. 2
25. 2
26. 2
27. 1
28. 2
29. 1
30. 2
31. 3
32. 2
33. 1
34. 4
35. 3
36. 3
37. 1
38. 2
39. 1
40. 2
81. 1
82. 2
83. 2
84. 4
85. 2
86. 3
87. 4
88. 2
89. 4
90. 1
91. 1
92. wrong que.
93. 2
94. 3
95. 2
96. 3
97. 1
98. 2
99. 1
100. 3
PHYSICS SOLUTIONS
1. (2)
Solution:
Phase
2. (1)
Solution.
Zero, avg of random velocity (motion) is zero here
3. 4
Solution.
Alternating current.
4. 3
Solution.
Rayleigh scattering has dependence on size of particle as well as wavelength of light.
5. 2
Solution.
Let speed in air = V
In the medium = 0.6 V
?refractive index of medium w.r.t. air
15
0.6 3
1.67
= =
=
6. 1
Solution.
Thicknening of eye lens ? move stressed eye
Focal length decreases ? cilliary muscle contract
I – B – i
7. 3
Solution.
Hydrogen ion ? proton
net flow is 3 x 1 x 10
18
electrons travelling left
18 19
1
ne 3 1 10 1.6 10
current 4.8 10 A 0.48
t1
-
-
×× × ×
? = = = ×=
8. 4
Solution.
Tangent of field line gives local direction.
9. No Solution
Solution.
Tap key to keep circuit open I – C – iv
Ammeter to be connected in series II – A – i
Voltmeter to be connected in parallel. III – d – ii
Galvenometer detects presence of current IV – b – iii
No choice is correct
In option 4 ? ii & i is replaced, to be it correct.
10. 1
Solution.
Virtual image can be produced by other optical insinemt.
11. 3.
12. 2.
Chemistry Solution
14. NO of elements is
1
st
period -2 H-He (1 – 2)
2
nd
period -8 Li-Ne (3-10)
3
rd
period -8 Na-Ar (11-18)
4
th
period -18 K-Kr (19-36)
Answer – 2
15. Antacids are used for indigestion
Ex - ( )
2
Mg OH
Answer – 2
16. Mercury ore is cinnabar (Hg5)
Bauxite -
23 2
Al O .2H O
Haematite -
23
Fe O
Cinnabar – Hg5
Dolomite -
33
MgCO .CaCO
Answer – 2
17.
32
KNO H O +
32
K NO H O
+-
??? + +
Temperature of solution falls endothermic reaction
Answer - 2
18. Ammonium chloride is salt of weak base and strong acid
4 42
NH OH HCl NH Cl H O + ??? +
Answer – 4
19.
3 2 3
CH CH CH CH CH
1 23 4 5
-=- -
2-pentene or pent – 2-ene
Answer – 1
20. Oxygen electron dot structure
O
. .
. .
.
O
. .
.
.
.
.
.
Oxygen – 8 -
22 4
1s 2s 2p (
0
6e s in valence shall)
Answer – 1
21. Eka – Aluminium can form an oxide like
Aluminium i e ( )
23 23
Ga O like Al O
Answer - 3
22. Pure copper acts as cathode and impure copper acts as anode
Answer - 2
23. (1)
2 2
CuO H H O Cu + ??? + (single displacement)
(2)
44
Zn CuSO ZnSO Cu + ??? +
(single displacement)
(3)
33
AgNO NaCl AgCl NaNO + ??? + (Double displacement)
(4)
22
Zn 2HCl 2nCl H + ??? + (Single displacement)
Answer – 3
24.
2
HO
2: 16 = 1:8
Answer – 1
25. In Black and white photography AgBr is involved.
2 AgBr
Sunlight
2
2Ag Br ? ??? ? +
Answer - 2
26. (1) ( )
24 4 2
Mg H SO MgSO H Occurs + ??? +
(2) ( )
22
Cu 2HCl CuCl H Do not + ??? +
(3) ( )
32
2Al 6HCl 2AlCl 3H Occurs + ??? +
(4)
22
Fe 2HCl FeCl H + ??? +
(Occurs)
This is based on metal activity series
Answer – 2
Biology :
27. (1)
Mushroom
Explanation: Mushroom exhibits saprophytic mode of nutrition while others (ticks, tape worms,
Cuscuta exhibit parasitic mode of nutrition.
28. (2)
Right atrium
Explanation: Right atrium receives deoxygenated blood
Left atrium receives oxygenated blood from the lungs
Right ventricle pumps blood to the lungs
Left ventricle pumps blood into aorta which supplies blood to the various regions of the body
29. (1)
Drosera
30. (2)
Hydra
Explanation Nerve net is primitive stage of development od nervous system
31. (3)
Bryophyllum
32. (2)
two male gametes
Explanation : The pollen tube contains 2 male gametes and one tube nucleus which generates the pollen
tube
33. (1)
Four
Explanation: Considering a cross TtYy x TtYy , the groups of phenotypic characters are (TY, ty, Ty, tY )
34. (4)
Fish Amphibians Reptiles Birds Mammals
According to origin, identify the secondary air pollutants
35. (3)
Smoke
36. (3) 45
37. (1) cuboidal epithelium
38. ( 2) species
39. (1) estrogen
40. (2) bile juice ( pancreas – pancreatic juice, stomach- gastric juice, bile juice – liver and intestine –
various digestive juice)
MATHEMATICS Solution
81. (1)
Hint.
{ }
{ }
1 3 5 .....to365 terms
365
2 (364 2
2
365
2 728
2
365
730
2
365 365
133225
+++
= + ×
= +
= ×
= ×
=
82. (2)
Let x price of one apple
y price of one guava
ATQ
19x 11y 482 0
11x 19y 418 0
by cross multiplicate
x y1
4598 9158 5302 7942 361 121
4560 2640
x 19 & y 11
240 270
Hence x y 8.
=
=
+- =
+- =
= =
- + -+ -
?= = = =
-=
83. (2)
Given one root is
25 +
?
other root is
25 -
Hence, requires equation
{ }
2
2
x (2 5) (2 5) x (2 5)(2 5) 0
x 4x 1 0
- + +- ++ - =
? - -=
84. (4)
From formulae,
x 15 x
97.5 94.5 h
2(x 15) x (x 5)
15 3h
3h
25 5
h5
upper limit 94.5 5 99.5
+- ??
= +
??
+ - - +
??
??
?= =
??
??
?=
? = + =
85. (2)
By expanding the determinants, we get
49 18 30 4b
4(a b) 48
a b 12
ans.2
-= -
? +=
?+=
86. (3)
Given
22
22
a6 9,b6 5
2(a b ) 2.2(6 5) 4 11 44
5ab 5 (1) 5
2(a b ) 5ab 44 5 39.
= += -
? + = + = ×=
= ·=
? + - = -=
87. (4)
Let the total no. of swan = x
ATQ.
2
7
X2 X
2
7x
x2
2
2x 4 7 x
4x 65x 16 0
x 16
+ =
? -=
? - =
? - + =
?=
88. (2)
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