State Level Question Paper & Answer Key (SAT) - 2014-15 | NTSE for Class 10 PDF Download

 Page 1


     
 
 (For Class X Students) 
SAT (Paper-2) 
   
Time: 90 Min.          Max. Marks: 90 
 
91. A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is 
 (1) 15 W (2) 30 W 
 (3) 65 W (4) 60 W  
91. 1 
Sol. 
2
V
P
R
? 
 ? P ? V
2
 
 
92. A dichromatic light of wavelength 5600 Å and 6300 Å pass through a prism of crown glass. 
Then: 
 (1) deviation for both wavelengths is same.  
 (2) both will emerge without deviation.  
 (3) deviation for wavelength 5600 Å is greater than deviation for wavelength 6300 Å.   
 (4) deviation for wavelength 6300 Å is greater than deviation for wavelength 5600 Å. 
92. 3 
Sol. Smaller is wavelength of incident ray more is refractive index of material for this colour, 
hence more is deviation.  
 
93. A convex lens is in contact with concave lens. The magnitude of the ratio of their focal length 
is 
2
.
3
 Their equivalent focal length is 30 cm. What are their individual focal lengths (in cm). 
 (1) –75, +50 (2) +10, –15 
 (3) +75, –50 (4) –15, –10  
93. 2 
Sol. 
eff 1 2
1 1 1
f f f
? ? 
 Put  f
1
 = 2f 
 f
2
 = –3f 
 Solving, f = 5 cm. 
 
94. The reading of ideal  V 
 
connected across R in the circuit 
shown below is: 
 (1) 1 V (2) 2 V 
 (3) 3 V (4) 4 V  
 
200 ? 
I = .02A 
6 V 
V 
 
94. 2 
Sol. For complete circuit 
 V = IR 
 6 = (0.02) (200 + R) 
 ? R = 100 ? 
 ? Reading of voltmeter = IR = (0.02) (100) = 2V  
 
Page 2


     
 
 (For Class X Students) 
SAT (Paper-2) 
   
Time: 90 Min.          Max. Marks: 90 
 
91. A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is 
 (1) 15 W (2) 30 W 
 (3) 65 W (4) 60 W  
91. 1 
Sol. 
2
V
P
R
? 
 ? P ? V
2
 
 
92. A dichromatic light of wavelength 5600 Å and 6300 Å pass through a prism of crown glass. 
Then: 
 (1) deviation for both wavelengths is same.  
 (2) both will emerge without deviation.  
 (3) deviation for wavelength 5600 Å is greater than deviation for wavelength 6300 Å.   
 (4) deviation for wavelength 6300 Å is greater than deviation for wavelength 5600 Å. 
92. 3 
Sol. Smaller is wavelength of incident ray more is refractive index of material for this colour, 
hence more is deviation.  
 
93. A convex lens is in contact with concave lens. The magnitude of the ratio of their focal length 
is 
2
.
3
 Their equivalent focal length is 30 cm. What are their individual focal lengths (in cm). 
 (1) –75, +50 (2) +10, –15 
 (3) +75, –50 (4) –15, –10  
93. 2 
Sol. 
eff 1 2
1 1 1
f f f
? ? 
 Put  f
1
 = 2f 
 f
2
 = –3f 
 Solving, f = 5 cm. 
 
94. The reading of ideal  V 
 
connected across R in the circuit 
shown below is: 
 (1) 1 V (2) 2 V 
 (3) 3 V (4) 4 V  
 
200 ? 
I = .02A 
6 V 
V 
 
94. 2 
Sol. For complete circuit 
 V = IR 
 6 = (0.02) (200 + R) 
 ? R = 100 ? 
 ? Reading of voltmeter = IR = (0.02) (100) = 2V  
 
     
95. An object starting from rest move on a straight road for time t and comes to rest finally. The 
distance is converted in two parts. In the first part it is accelerated at constant acceleration ? 
and then decelerate at rate ?. Then maximum velocity is 
 (1) ?t (2) ?t 
 (3) t
2
? ? ? ? ?
? ?
? ?
 (4) t
? ? ? ?
? ?
? ? ?
? ?
  
95. 4 
Sol. V = (0) + ?t
1
 …(i) 
 0 = ( ?t
1
) + ?t
2
 …(ii) 
 t
1
 + t
2
 = t 
 ? V (t)
? ? ? ?
?
? ?
? ? ?
? ?
 
 
96. A person is standing in an elevator, in which situation he finds his weight less? 
 (1) When the elevator moves upward with constant acceleration.  
 (2) When the elevator moves downward with constant acceleration. 
 (3) When elevator moves upward with uniform velocity.   
 (4) When elevator moves downward with uniform velocity.   
96. 2 
Sol. Let ‘N’ be normal force by elevator floor on man.  
 Then, mg – N = ma (Assuming downward acceleration) 
 ? N < mg 
 Which matches with given condition in option (2). 
 
97. Velocity-time graph of an object is 
 Displacement – Time graph is:  
 
t 
V 
T 
2t 3t 
 [ [ 
(1) 
 
t 
S 
T 
2t 3t 
 
(2) 
 
t 
S 
T 
2t 3t 
 
(3) 
 
t 
S 
T 
2t 3t 
 
(4) 
 
t 
S 
T 
2t 3t 
 
97. 2 
Sol. Since velocity is always positive, displacement continuously increases which is shown only 
in option (2). 
 
98. A source emits sound of frequency 600 Hz inside water. The frequency heard in air will be: 
(V = 1500 m/s in water and V = 300 m/s in air). 
 (1) 300 Hz (2) 120 Hz 
 (3) 600 Hz (4) 6000 Hz  
98. 3 
Sol. Frequency of sound depends upon source and is independent of medium.  
 
Page 3


     
 
 (For Class X Students) 
SAT (Paper-2) 
   
Time: 90 Min.          Max. Marks: 90 
 
91. A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is 
 (1) 15 W (2) 30 W 
 (3) 65 W (4) 60 W  
91. 1 
Sol. 
2
V
P
R
? 
 ? P ? V
2
 
 
92. A dichromatic light of wavelength 5600 Å and 6300 Å pass through a prism of crown glass. 
Then: 
 (1) deviation for both wavelengths is same.  
 (2) both will emerge without deviation.  
 (3) deviation for wavelength 5600 Å is greater than deviation for wavelength 6300 Å.   
 (4) deviation for wavelength 6300 Å is greater than deviation for wavelength 5600 Å. 
92. 3 
Sol. Smaller is wavelength of incident ray more is refractive index of material for this colour, 
hence more is deviation.  
 
93. A convex lens is in contact with concave lens. The magnitude of the ratio of their focal length 
is 
2
.
3
 Their equivalent focal length is 30 cm. What are their individual focal lengths (in cm). 
 (1) –75, +50 (2) +10, –15 
 (3) +75, –50 (4) –15, –10  
93. 2 
Sol. 
eff 1 2
1 1 1
f f f
? ? 
 Put  f
1
 = 2f 
 f
2
 = –3f 
 Solving, f = 5 cm. 
 
94. The reading of ideal  V 
 
connected across R in the circuit 
shown below is: 
 (1) 1 V (2) 2 V 
 (3) 3 V (4) 4 V  
 
200 ? 
I = .02A 
6 V 
V 
 
94. 2 
Sol. For complete circuit 
 V = IR 
 6 = (0.02) (200 + R) 
 ? R = 100 ? 
 ? Reading of voltmeter = IR = (0.02) (100) = 2V  
 
     
95. An object starting from rest move on a straight road for time t and comes to rest finally. The 
distance is converted in two parts. In the first part it is accelerated at constant acceleration ? 
and then decelerate at rate ?. Then maximum velocity is 
 (1) ?t (2) ?t 
 (3) t
2
? ? ? ? ?
? ?
? ?
 (4) t
? ? ? ?
? ?
? ? ?
? ?
  
95. 4 
Sol. V = (0) + ?t
1
 …(i) 
 0 = ( ?t
1
) + ?t
2
 …(ii) 
 t
1
 + t
2
 = t 
 ? V (t)
? ? ? ?
?
? ?
? ? ?
? ?
 
 
96. A person is standing in an elevator, in which situation he finds his weight less? 
 (1) When the elevator moves upward with constant acceleration.  
 (2) When the elevator moves downward with constant acceleration. 
 (3) When elevator moves upward with uniform velocity.   
 (4) When elevator moves downward with uniform velocity.   
96. 2 
Sol. Let ‘N’ be normal force by elevator floor on man.  
 Then, mg – N = ma (Assuming downward acceleration) 
 ? N < mg 
 Which matches with given condition in option (2). 
 
97. Velocity-time graph of an object is 
 Displacement – Time graph is:  
 
t 
V 
T 
2t 3t 
 [ [ 
(1) 
 
t 
S 
T 
2t 3t 
 
(2) 
 
t 
S 
T 
2t 3t 
 
(3) 
 
t 
S 
T 
2t 3t 
 
(4) 
 
t 
S 
T 
2t 3t 
 
97. 2 
Sol. Since velocity is always positive, displacement continuously increases which is shown only 
in option (2). 
 
98. A source emits sound of frequency 600 Hz inside water. The frequency heard in air will be: 
(V = 1500 m/s in water and V = 300 m/s in air). 
 (1) 300 Hz (2) 120 Hz 
 (3) 600 Hz (4) 6000 Hz  
98. 3 
Sol. Frequency of sound depends upon source and is independent of medium.  
 
     
99. When a charged particle in motion enters in a uniform magnetic field perpendicularly then its 
 (1) Speed changes (2) Velocity changes 
 (3) K.E. changes (4) Acceleration does not change  
99. 2 
Sol. Charge will follow circular path with speed remaining same. 
 
100. The frequency of seconds pendulum is 
 (1) 0.5 Hz (2) 1.0 Hz 
 (3) 2.0 Hz (4) 1.5 Hz  
100. 1 
Sol. For seconds pendulum, T = 2 sec 
 f = 
1
T
 = 0.5 Hz 
 
101. The structure of solids is investigated by using 
 (1) Cosmic rays (2) X-rays 
 (3) Gamma rays (4) Infrared rays  
101. 2 
Sol. X-Rays are used to investigate structure of solids. 
 
102. Two bodies with kinetic energy in the ratio of 4 : 1 are moving with equal linear momentum. 
The ratio of their masses is 
 (1) 1 : 2 (2) 1 : 1 
 (3) 4 : 1 (4) 1 : 4  
102. 4 
Sol. 
2
1 1
2
2 2
(K.E.) p / 2m 4
(K.E.) p / 2m 1
? ? 
 ? 
1
2
m 1
m 4
?  
 
103. Which one of the following is the smallest in size? 
 (1) N
3–
 (2) O
2–
 
 (3) F
–
 (4) Na
+
 
103. 4 
Sol. Due to highest effective nuclear charge of sodium ion. 
 
104. Which chemical substance is added to LPG to help in detection of its leakage? 
 (1) Isobutane (2) Ethanethiol 
 (3) Propane (4) Hydrogen sulphide 
104. 2 
Sol. Ethanethiol or ethylmercaptan 
 
105. Which of the following salt does not contains the water of crystallization? 
 (1) Blue Vitriol (2) Baking soda 
 (3) Washing soda (4) Gypsum 
105 2 
Sol. CuSO
4
.5H
2
O (Blue Vitriol)  
 NaHCO
3
 (Baking Soda) 
 Na
2
CO
3
.10H
2
O(Washing Soda) 
 CaSO
4
.2H
2
O (Gypsum) 
 
106. The ion of an element has 3 positive charge, 27 mass-number and 14 neutrons. What is the 
number of electrons in this ion? 
 (1) 13 (2) 14 
 (3) 10 (4) 16 
106. 3 
Page 4


     
 
 (For Class X Students) 
SAT (Paper-2) 
   
Time: 90 Min.          Max. Marks: 90 
 
91. A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is 
 (1) 15 W (2) 30 W 
 (3) 65 W (4) 60 W  
91. 1 
Sol. 
2
V
P
R
? 
 ? P ? V
2
 
 
92. A dichromatic light of wavelength 5600 Å and 6300 Å pass through a prism of crown glass. 
Then: 
 (1) deviation for both wavelengths is same.  
 (2) both will emerge without deviation.  
 (3) deviation for wavelength 5600 Å is greater than deviation for wavelength 6300 Å.   
 (4) deviation for wavelength 6300 Å is greater than deviation for wavelength 5600 Å. 
92. 3 
Sol. Smaller is wavelength of incident ray more is refractive index of material for this colour, 
hence more is deviation.  
 
93. A convex lens is in contact with concave lens. The magnitude of the ratio of their focal length 
is 
2
.
3
 Their equivalent focal length is 30 cm. What are their individual focal lengths (in cm). 
 (1) –75, +50 (2) +10, –15 
 (3) +75, –50 (4) –15, –10  
93. 2 
Sol. 
eff 1 2
1 1 1
f f f
? ? 
 Put  f
1
 = 2f 
 f
2
 = –3f 
 Solving, f = 5 cm. 
 
94. The reading of ideal  V 
 
connected across R in the circuit 
shown below is: 
 (1) 1 V (2) 2 V 
 (3) 3 V (4) 4 V  
 
200 ? 
I = .02A 
6 V 
V 
 
94. 2 
Sol. For complete circuit 
 V = IR 
 6 = (0.02) (200 + R) 
 ? R = 100 ? 
 ? Reading of voltmeter = IR = (0.02) (100) = 2V  
 
     
95. An object starting from rest move on a straight road for time t and comes to rest finally. The 
distance is converted in two parts. In the first part it is accelerated at constant acceleration ? 
and then decelerate at rate ?. Then maximum velocity is 
 (1) ?t (2) ?t 
 (3) t
2
? ? ? ? ?
? ?
? ?
 (4) t
? ? ? ?
? ?
? ? ?
? ?
  
95. 4 
Sol. V = (0) + ?t
1
 …(i) 
 0 = ( ?t
1
) + ?t
2
 …(ii) 
 t
1
 + t
2
 = t 
 ? V (t)
? ? ? ?
?
? ?
? ? ?
? ?
 
 
96. A person is standing in an elevator, in which situation he finds his weight less? 
 (1) When the elevator moves upward with constant acceleration.  
 (2) When the elevator moves downward with constant acceleration. 
 (3) When elevator moves upward with uniform velocity.   
 (4) When elevator moves downward with uniform velocity.   
96. 2 
Sol. Let ‘N’ be normal force by elevator floor on man.  
 Then, mg – N = ma (Assuming downward acceleration) 
 ? N < mg 
 Which matches with given condition in option (2). 
 
97. Velocity-time graph of an object is 
 Displacement – Time graph is:  
 
t 
V 
T 
2t 3t 
 [ [ 
(1) 
 
t 
S 
T 
2t 3t 
 
(2) 
 
t 
S 
T 
2t 3t 
 
(3) 
 
t 
S 
T 
2t 3t 
 
(4) 
 
t 
S 
T 
2t 3t 
 
97. 2 
Sol. Since velocity is always positive, displacement continuously increases which is shown only 
in option (2). 
 
98. A source emits sound of frequency 600 Hz inside water. The frequency heard in air will be: 
(V = 1500 m/s in water and V = 300 m/s in air). 
 (1) 300 Hz (2) 120 Hz 
 (3) 600 Hz (4) 6000 Hz  
98. 3 
Sol. Frequency of sound depends upon source and is independent of medium.  
 
     
99. When a charged particle in motion enters in a uniform magnetic field perpendicularly then its 
 (1) Speed changes (2) Velocity changes 
 (3) K.E. changes (4) Acceleration does not change  
99. 2 
Sol. Charge will follow circular path with speed remaining same. 
 
100. The frequency of seconds pendulum is 
 (1) 0.5 Hz (2) 1.0 Hz 
 (3) 2.0 Hz (4) 1.5 Hz  
100. 1 
Sol. For seconds pendulum, T = 2 sec 
 f = 
1
T
 = 0.5 Hz 
 
101. The structure of solids is investigated by using 
 (1) Cosmic rays (2) X-rays 
 (3) Gamma rays (4) Infrared rays  
101. 2 
Sol. X-Rays are used to investigate structure of solids. 
 
102. Two bodies with kinetic energy in the ratio of 4 : 1 are moving with equal linear momentum. 
The ratio of their masses is 
 (1) 1 : 2 (2) 1 : 1 
 (3) 4 : 1 (4) 1 : 4  
102. 4 
Sol. 
2
1 1
2
2 2
(K.E.) p / 2m 4
(K.E.) p / 2m 1
? ? 
 ? 
1
2
m 1
m 4
?  
 
103. Which one of the following is the smallest in size? 
 (1) N
3–
 (2) O
2–
 
 (3) F
–
 (4) Na
+
 
103. 4 
Sol. Due to highest effective nuclear charge of sodium ion. 
 
104. Which chemical substance is added to LPG to help in detection of its leakage? 
 (1) Isobutane (2) Ethanethiol 
 (3) Propane (4) Hydrogen sulphide 
104. 2 
Sol. Ethanethiol or ethylmercaptan 
 
105. Which of the following salt does not contains the water of crystallization? 
 (1) Blue Vitriol (2) Baking soda 
 (3) Washing soda (4) Gypsum 
105 2 
Sol. CuSO
4
.5H
2
O (Blue Vitriol)  
 NaHCO
3
 (Baking Soda) 
 Na
2
CO
3
.10H
2
O(Washing Soda) 
 CaSO
4
.2H
2
O (Gypsum) 
 
106. The ion of an element has 3 positive charge, 27 mass-number and 14 neutrons. What is the 
number of electrons in this ion? 
 (1) 13 (2) 14 
 (3) 10 (4) 16 
106. 3 
     
Sol. Given 
 3 positive charge 
 27 mass number 
 14 neutron 
 Mass number of any atom = No. of protons + No. of neutrons 
 27 = No. of protons + 14 
 No. of protons = 13 
 No. of protons in atom = No. of electrons in atom = 13 
 No. of electrons in ion = 13 – 3 = 10 
 
107. Which one of the following is the natural fruit ripening hormone? 
 (1) Ethane (2) Ethene 
 (3) Ethyne  (4) Carbide 
107. 2 
Sol. Ethene is used as natural fruit ripening hormone. 
 
108. Which of the following contains acidic hydrogen? 
 (1) Ethene (2) Ethane 
 (3) Ethyne (4) But-2-yne 
108. 3 
Sol. 
H C C H ? ? ?
Sp hybridised carbon 
 
 Due to 50% S character carbon becomes more electronegative and acidic. So H
+
 ion will 
release easily. 
 
109. Silver jewellery becomes black on prolonged exposure to air, It is due to the formation of 
 (1) Ag
3
N (2) Ag
2
O 
 (3) Ag
2
S and Ag
3
N (4) Ag
2
S 
109. 4 
Sol. Silver combines with SO
2
 in air to give silver sulphide 
 
2 2 2
2Ag SO Ag S O ? ? ? ? ? 
 
110. What is the mass of oxygen required to react completely with 15 g of H
2
 gas to form water? 
 (1) 140 g  (2) 115 g  
 (3) 107.5 g  (4) 120 g  
110. 4 
Sol. 
2 2 2
2H O 2H O ? ? ? ? 
 4 g Hydrogen takes up 32 g oxygen 
 15 g Hydrogen takes up 
32
15
4
? = 120 g oxygen. 
111. Percentage purity of a sample of gold is 85%. How many atoms of gold are present in its      
1 gram sample? (Atomic mass of gold = 197 u) 
 (1) 2.6 ? 10
21
 (2) 2.6 ? 10
23
 
 (3) 3.0 ? 10
21
 (4) 4.5 ? 10
20
 
111. 1 
Sol. 85% gold in 1 gram sample 
 0.85 g gold is present in 1 gram sample 
 197 g of gold = 6.022 ? 10
23
 atoms of gold 
 0.85 g of gold  = 
23
21
6.022 10
.85 2.6 10
197
?
? ? ? 
 
112. The volume of 1 mole of an ideal gas at 25
o
C temperature and 1 bar pressure is: 
 (1) 22.4 L  (2) 22.7 L  
 (3) 24.8 L  (4) 24.4 L 
Page 5


     
 
 (For Class X Students) 
SAT (Paper-2) 
   
Time: 90 Min.          Max. Marks: 90 
 
91. A bulb of (220 V, 60 W) is operated on 110 V supply then power developed in it is 
 (1) 15 W (2) 30 W 
 (3) 65 W (4) 60 W  
91. 1 
Sol. 
2
V
P
R
? 
 ? P ? V
2
 
 
92. A dichromatic light of wavelength 5600 Å and 6300 Å pass through a prism of crown glass. 
Then: 
 (1) deviation for both wavelengths is same.  
 (2) both will emerge without deviation.  
 (3) deviation for wavelength 5600 Å is greater than deviation for wavelength 6300 Å.   
 (4) deviation for wavelength 6300 Å is greater than deviation for wavelength 5600 Å. 
92. 3 
Sol. Smaller is wavelength of incident ray more is refractive index of material for this colour, 
hence more is deviation.  
 
93. A convex lens is in contact with concave lens. The magnitude of the ratio of their focal length 
is 
2
.
3
 Their equivalent focal length is 30 cm. What are their individual focal lengths (in cm). 
 (1) –75, +50 (2) +10, –15 
 (3) +75, –50 (4) –15, –10  
93. 2 
Sol. 
eff 1 2
1 1 1
f f f
? ? 
 Put  f
1
 = 2f 
 f
2
 = –3f 
 Solving, f = 5 cm. 
 
94. The reading of ideal  V 
 
connected across R in the circuit 
shown below is: 
 (1) 1 V (2) 2 V 
 (3) 3 V (4) 4 V  
 
200 ? 
I = .02A 
6 V 
V 
 
94. 2 
Sol. For complete circuit 
 V = IR 
 6 = (0.02) (200 + R) 
 ? R = 100 ? 
 ? Reading of voltmeter = IR = (0.02) (100) = 2V  
 
     
95. An object starting from rest move on a straight road for time t and comes to rest finally. The 
distance is converted in two parts. In the first part it is accelerated at constant acceleration ? 
and then decelerate at rate ?. Then maximum velocity is 
 (1) ?t (2) ?t 
 (3) t
2
? ? ? ? ?
? ?
? ?
 (4) t
? ? ? ?
? ?
? ? ?
? ?
  
95. 4 
Sol. V = (0) + ?t
1
 …(i) 
 0 = ( ?t
1
) + ?t
2
 …(ii) 
 t
1
 + t
2
 = t 
 ? V (t)
? ? ? ?
?
? ?
? ? ?
? ?
 
 
96. A person is standing in an elevator, in which situation he finds his weight less? 
 (1) When the elevator moves upward with constant acceleration.  
 (2) When the elevator moves downward with constant acceleration. 
 (3) When elevator moves upward with uniform velocity.   
 (4) When elevator moves downward with uniform velocity.   
96. 2 
Sol. Let ‘N’ be normal force by elevator floor on man.  
 Then, mg – N = ma (Assuming downward acceleration) 
 ? N < mg 
 Which matches with given condition in option (2). 
 
97. Velocity-time graph of an object is 
 Displacement – Time graph is:  
 
t 
V 
T 
2t 3t 
 [ [ 
(1) 
 
t 
S 
T 
2t 3t 
 
(2) 
 
t 
S 
T 
2t 3t 
 
(3) 
 
t 
S 
T 
2t 3t 
 
(4) 
 
t 
S 
T 
2t 3t 
 
97. 2 
Sol. Since velocity is always positive, displacement continuously increases which is shown only 
in option (2). 
 
98. A source emits sound of frequency 600 Hz inside water. The frequency heard in air will be: 
(V = 1500 m/s in water and V = 300 m/s in air). 
 (1) 300 Hz (2) 120 Hz 
 (3) 600 Hz (4) 6000 Hz  
98. 3 
Sol. Frequency of sound depends upon source and is independent of medium.  
 
     
99. When a charged particle in motion enters in a uniform magnetic field perpendicularly then its 
 (1) Speed changes (2) Velocity changes 
 (3) K.E. changes (4) Acceleration does not change  
99. 2 
Sol. Charge will follow circular path with speed remaining same. 
 
100. The frequency of seconds pendulum is 
 (1) 0.5 Hz (2) 1.0 Hz 
 (3) 2.0 Hz (4) 1.5 Hz  
100. 1 
Sol. For seconds pendulum, T = 2 sec 
 f = 
1
T
 = 0.5 Hz 
 
101. The structure of solids is investigated by using 
 (1) Cosmic rays (2) X-rays 
 (3) Gamma rays (4) Infrared rays  
101. 2 
Sol. X-Rays are used to investigate structure of solids. 
 
102. Two bodies with kinetic energy in the ratio of 4 : 1 are moving with equal linear momentum. 
The ratio of their masses is 
 (1) 1 : 2 (2) 1 : 1 
 (3) 4 : 1 (4) 1 : 4  
102. 4 
Sol. 
2
1 1
2
2 2
(K.E.) p / 2m 4
(K.E.) p / 2m 1
? ? 
 ? 
1
2
m 1
m 4
?  
 
103. Which one of the following is the smallest in size? 
 (1) N
3–
 (2) O
2–
 
 (3) F
–
 (4) Na
+
 
103. 4 
Sol. Due to highest effective nuclear charge of sodium ion. 
 
104. Which chemical substance is added to LPG to help in detection of its leakage? 
 (1) Isobutane (2) Ethanethiol 
 (3) Propane (4) Hydrogen sulphide 
104. 2 
Sol. Ethanethiol or ethylmercaptan 
 
105. Which of the following salt does not contains the water of crystallization? 
 (1) Blue Vitriol (2) Baking soda 
 (3) Washing soda (4) Gypsum 
105 2 
Sol. CuSO
4
.5H
2
O (Blue Vitriol)  
 NaHCO
3
 (Baking Soda) 
 Na
2
CO
3
.10H
2
O(Washing Soda) 
 CaSO
4
.2H
2
O (Gypsum) 
 
106. The ion of an element has 3 positive charge, 27 mass-number and 14 neutrons. What is the 
number of electrons in this ion? 
 (1) 13 (2) 14 
 (3) 10 (4) 16 
106. 3 
     
Sol. Given 
 3 positive charge 
 27 mass number 
 14 neutron 
 Mass number of any atom = No. of protons + No. of neutrons 
 27 = No. of protons + 14 
 No. of protons = 13 
 No. of protons in atom = No. of electrons in atom = 13 
 No. of electrons in ion = 13 – 3 = 10 
 
107. Which one of the following is the natural fruit ripening hormone? 
 (1) Ethane (2) Ethene 
 (3) Ethyne  (4) Carbide 
107. 2 
Sol. Ethene is used as natural fruit ripening hormone. 
 
108. Which of the following contains acidic hydrogen? 
 (1) Ethene (2) Ethane 
 (3) Ethyne (4) But-2-yne 
108. 3 
Sol. 
H C C H ? ? ?
Sp hybridised carbon 
 
 Due to 50% S character carbon becomes more electronegative and acidic. So H
+
 ion will 
release easily. 
 
109. Silver jewellery becomes black on prolonged exposure to air, It is due to the formation of 
 (1) Ag
3
N (2) Ag
2
O 
 (3) Ag
2
S and Ag
3
N (4) Ag
2
S 
109. 4 
Sol. Silver combines with SO
2
 in air to give silver sulphide 
 
2 2 2
2Ag SO Ag S O ? ? ? ? ? 
 
110. What is the mass of oxygen required to react completely with 15 g of H
2
 gas to form water? 
 (1) 140 g  (2) 115 g  
 (3) 107.5 g  (4) 120 g  
110. 4 
Sol. 
2 2 2
2H O 2H O ? ? ? ? 
 4 g Hydrogen takes up 32 g oxygen 
 15 g Hydrogen takes up 
32
15
4
? = 120 g oxygen. 
111. Percentage purity of a sample of gold is 85%. How many atoms of gold are present in its      
1 gram sample? (Atomic mass of gold = 197 u) 
 (1) 2.6 ? 10
21
 (2) 2.6 ? 10
23
 
 (3) 3.0 ? 10
21
 (4) 4.5 ? 10
20
 
111. 1 
Sol. 85% gold in 1 gram sample 
 0.85 g gold is present in 1 gram sample 
 197 g of gold = 6.022 ? 10
23
 atoms of gold 
 0.85 g of gold  = 
23
21
6.022 10
.85 2.6 10
197
?
? ? ? 
 
112. The volume of 1 mole of an ideal gas at 25
o
C temperature and 1 bar pressure is: 
 (1) 22.4 L  (2) 22.7 L  
 (3) 24.8 L  (4) 24.4 L 
     
112. 3 
Sol. PV = nRT 
 
1 1
1 0.0821 L atm mol K 298 K
V
0.987 atm
? ?
? ?
? [1 bar = 0.987 atm] 
 V = 24.8 L  
 
113. Which of the following solution can be stored in aluminium container? 
 (1) MgSO
4
(aq) (2) ZnSO
4
(aq) 
 (3) CuSO
4
(aq) (4) FeSO
4
(aq) 
113. 1 
Sol. Aluminium is less reactive than ‘Mg’ (Magnesium). 
 ? It can’t displace Mg from its salt MgSO
4
. 
 
114. The cell organelle in which hydrolytic enzymes are stored is: 
 (1) Plastid   (2) Mitochondria 
 (3) Centrosome (4) Lysosome   
114. 4 
Sol. Lysosome carry the hydrolytic enzymes. 
 
115. Choose the incorrect statement about insulin: 
 (1) Deficiency of insulin leads to diabetes.  
 (2) It regulates the growth and development of the body. 
 (3) It controls sugar level in the blood.  
 (4) It is produced from the pancreas.  
115. 2 
Sol. Insulin secreted by pancreas it converts the glucose in to glycogen and by this it controls the 
sugar level in the blood and deficiency of insulin leads to diabetes. 
 
116. The animal which belongs to class pisces is: 
 (1) Silver fish (2) Jelly fish 
 (3) Star fish (4) Dog fish  
116. 4 
Sol. Dog fish (scoliodon) belongs to class pisces. 
 
117. Most of the plants absorb nitrogen in the form of: 
 (1) Uric acid (2) Amino acids 
 (3) Atmospheric nitrogen (4) Nitrates and Nitrites  
117. 4 
Sol. Nitrogen fixing bacteria converts atmospheric N
2
 into nitrite and nitrate and makes it 
available for the plants. 
 
118. In a synapse, the chemical signal is transmitted from: 
 (1) axonal end of a neuron to dendritic end of another neuron.  
 (2) axonal end to the cell body of the same neuron.  
 (3) Cell body to axonal end of the same neuron.   
 (4) dendritic end of one neuron to axonal end of another neuron.   
118. 3 
Sol. Junction between two Neuron is known as synapse. In the synapse the chemical signal is 
transmitted from cell body to axonal end of the same Neuron.  
 
119. After pollination, the growth of pollen tube on stigma toward ovule is due to: 
 (1) Phototropism  (2) Chemotropism 
 (3) Hydrotropism (4) Geotropism  
119. 2 
Sol. After reaching on stigma the pollen grain develops a pollen tube towards ovule because of 
chemical reactions (chemotropism).