IBPS RRB Clerk 2020: Prelims Question Paper Solutions

 Page 1


 
 
 
                                                   
 
 
IBPS RRB Clerk Prelims 2020 (Solutions) 
 
 
 
 
Directions (1-5): 
 
1. (b):  2. (d): 3. (c): 
4. (b):  5. (a): 6. (c): 
7. (d):  8. (a): 9. (b): 
   
Directions (10-12): 
C > E > A (86) > B > D 
 
10. (d): 
11. (a): 
12. (c): 
   
Directions (13-16): 
 
13. (a):  
   
S14. (e):  
   
 
15. (d):  
   
16. (b):  
   
   
Directions (17-21): 
 
 
17. (b):  18. (c): 19. (d): 
20. (b):  21. (c): 
   
 
Directions (22-23): 
22. (b):  
   
 
23. (c):  
   
   
Directions (24-27): 
 
 
24. (b):  25. (c): 26. (d): 
27. (b): 
 
28. (c):  
   
   
Directions (29-33): 
 
29. (c):  30. (b): 31. (a): 
32. (d):  33. (c): 
 
34. (c): 3 5 9 8 2 4 7 6 
  1 3 7 9 3 5 5 7 
 
Directions (35-39): 
 
Months 7
th
 12
th
 
January A F 
February C B 
March E D 
 
35. (c):  36. (b): 37. (b): 
38. (c):  39. (b): 40. (a): 
REASONING ABILITY 
Page 2


 
 
 
                                                   
 
 
IBPS RRB Clerk Prelims 2020 (Solutions) 
 
 
 
 
Directions (1-5): 
 
1. (b):  2. (d): 3. (c): 
4. (b):  5. (a): 6. (c): 
7. (d):  8. (a): 9. (b): 
   
Directions (10-12): 
C > E > A (86) > B > D 
 
10. (d): 
11. (a): 
12. (c): 
   
Directions (13-16): 
 
13. (a):  
   
S14. (e):  
   
 
15. (d):  
   
16. (b):  
   
   
Directions (17-21): 
 
 
17. (b):  18. (c): 19. (d): 
20. (b):  21. (c): 
   
 
Directions (22-23): 
22. (b):  
   
 
23. (c):  
   
   
Directions (24-27): 
 
 
24. (b):  25. (c): 26. (d): 
27. (b): 
 
28. (c):  
   
   
Directions (29-33): 
 
29. (c):  30. (b): 31. (a): 
32. (d):  33. (c): 
 
34. (c): 3 5 9 8 2 4 7 6 
  1 3 7 9 3 5 5 7 
 
Directions (35-39): 
 
Months 7
th
 12
th
 
January A F 
February C B 
March E D 
 
35. (c):  36. (b): 37. (b): 
38. (c):  39. (b): 40. (a): 
REASONING ABILITY 
 
 
 
                                                   
 
 
   
 
 
41. (b): Required percentage = 
36-33
36
 × 100 
   = 
3
36
 × 100 = 8
1
3
% 
 
42. (a): Required average = 
36+27+33
3
 = 32 
 
43. (e): Required ratio = 18 : 22 = 9 : 11 
 
44. (b): Total passenger in C and E = 27 + 33 = 60 
  Required percentage = 
60-36
36
 × 100 
   = 
24
36
 × 100 = 66
2
3
% 
 
45. (c): Required number of passengers = 18 + 27 + 22 = 
67 
 
46. (b): Pattern of series – 
  12 × 1 = 12 
  12 × 2 = 24 
  24 × 3 = 72 
  ? = 72 × 4 = 288 
  288 × 5 = 1440 
 
47. (e): Pattern of series – 
  16 + 1.8 = 17.8 
  17.8 + 3.6 = 21.4 
  21.4 + 7.2 = 28.6 
  28.6 + 14.4 = 43 
  ? = 43 + 28.8 = 71.8 
 
48. (b): Pattern of series – 
  12 × 0.5 + 1 = 7 
  7 × 1 + 1 = 8 
  8 × 1.5 + 1 = 13 
  ? = 13 × 2 + 1 = 27 
  27 × 2.5 + 1 = 68.5 
 
49. (d): Pattern of series – 
  72 + 7 = 79 
  79 – 14 = 65 
  65 + 28 = 93 
  ? = 93 – 56 = 37 
  37 + 112 = 149 
50. (b): Pattern of series – 
  8 × 1 + 1 = 9 
  9 × 2 + 1 = 19 
  19 × 3 + 1 = 58 
  58 × 4 + 1 = 233 
  233 × 5 + 1 = 1166  
 
51. (a): Let present age of Q = t years 
  So, present age of P = (t + 3) years 
  ATQ – 
  
?? +2
(?? +3)+2
 = 
4
5
 
  t = 10 years 
  So, Age of P after two years= (10 + 3) + 2 = 15 
year 
 
52. (c): Let total income of B = 100x Rs. 
  So, total income of A  
  = 100x × (1 +
20
100
) = 120?? ???? . 
  ATQ – 
  (100x + 120x) ×
30
100
= 26400 
  66x = 26400 
  x = 400 Rs. 
  So, income of B = 400 × 100 = 40000 ???? . 
 
53. (e): Let sum invested by man = Rs. X 
  And, rate of interest = r%  
  ATQ- 
?? ×?? ×?? ?? ×?? ×(?? +4)
 = 
1
2
 
  
?? (?? +4)
 = 
1
2
 ? T = 4  
 
54. (d): Let total work = 12 × 64 = 768 units 
  Required women = 768 ×
2
3
 ×
1
16
= 32 
55. (e): Let length of train be ‘l’ meters  
  ATQ – 
  72 ×
5
18
= 
?? 30
  
  l = 600 meters 
  Required time = 
600
54×
5
18
 = 40 sec 
 
56. (a): ATQ – 
  14 × 6 - 10 × ?? = 44 
  10T = 40 
  T = 4 
 
57. (c): Let cost price of article = 100x Rs. 
  So, marked price of article = 100x × (1 +
50
100
) =
150 ?? Rs. 
  And, selling price of article = (150x – 50) Rs. 
  ATQ – 
  (150x – 50) – 100x = 50 
  50x = 100 
  x = 2 Rs. 
  So, selling price of article = (150 × 2 - 50) =
250 ???? . 
 
58. (e): ATQ – 
  
?? (?? +800)
 = 
3200 
(6800-3200)
 
  X = 6400  
 
59. (b): Let total initial mixture in vessel = 4x 
  So, milk in vessel = 3x 
  And water in vessel = x 
  ATQ – 
  (3x – 20 ×
3?? 4?? ) - (?? - 20 ×
?? 4?? ) = 70 
Quantitative Aptitude 
Page 3


 
 
 
                                                   
 
 
IBPS RRB Clerk Prelims 2020 (Solutions) 
 
 
 
 
Directions (1-5): 
 
1. (b):  2. (d): 3. (c): 
4. (b):  5. (a): 6. (c): 
7. (d):  8. (a): 9. (b): 
   
Directions (10-12): 
C > E > A (86) > B > D 
 
10. (d): 
11. (a): 
12. (c): 
   
Directions (13-16): 
 
13. (a):  
   
S14. (e):  
   
 
15. (d):  
   
16. (b):  
   
   
Directions (17-21): 
 
 
17. (b):  18. (c): 19. (d): 
20. (b):  21. (c): 
   
 
Directions (22-23): 
22. (b):  
   
 
23. (c):  
   
   
Directions (24-27): 
 
 
24. (b):  25. (c): 26. (d): 
27. (b): 
 
28. (c):  
   
   
Directions (29-33): 
 
29. (c):  30. (b): 31. (a): 
32. (d):  33. (c): 
 
34. (c): 3 5 9 8 2 4 7 6 
  1 3 7 9 3 5 5 7 
 
Directions (35-39): 
 
Months 7
th
 12
th
 
January A F 
February C B 
March E D 
 
35. (c):  36. (b): 37. (b): 
38. (c):  39. (b): 40. (a): 
REASONING ABILITY 
 
 
 
                                                   
 
 
   
 
 
41. (b): Required percentage = 
36-33
36
 × 100 
   = 
3
36
 × 100 = 8
1
3
% 
 
42. (a): Required average = 
36+27+33
3
 = 32 
 
43. (e): Required ratio = 18 : 22 = 9 : 11 
 
44. (b): Total passenger in C and E = 27 + 33 = 60 
  Required percentage = 
60-36
36
 × 100 
   = 
24
36
 × 100 = 66
2
3
% 
 
45. (c): Required number of passengers = 18 + 27 + 22 = 
67 
 
46. (b): Pattern of series – 
  12 × 1 = 12 
  12 × 2 = 24 
  24 × 3 = 72 
  ? = 72 × 4 = 288 
  288 × 5 = 1440 
 
47. (e): Pattern of series – 
  16 + 1.8 = 17.8 
  17.8 + 3.6 = 21.4 
  21.4 + 7.2 = 28.6 
  28.6 + 14.4 = 43 
  ? = 43 + 28.8 = 71.8 
 
48. (b): Pattern of series – 
  12 × 0.5 + 1 = 7 
  7 × 1 + 1 = 8 
  8 × 1.5 + 1 = 13 
  ? = 13 × 2 + 1 = 27 
  27 × 2.5 + 1 = 68.5 
 
49. (d): Pattern of series – 
  72 + 7 = 79 
  79 – 14 = 65 
  65 + 28 = 93 
  ? = 93 – 56 = 37 
  37 + 112 = 149 
50. (b): Pattern of series – 
  8 × 1 + 1 = 9 
  9 × 2 + 1 = 19 
  19 × 3 + 1 = 58 
  58 × 4 + 1 = 233 
  233 × 5 + 1 = 1166  
 
51. (a): Let present age of Q = t years 
  So, present age of P = (t + 3) years 
  ATQ – 
  
?? +2
(?? +3)+2
 = 
4
5
 
  t = 10 years 
  So, Age of P after two years= (10 + 3) + 2 = 15 
year 
 
52. (c): Let total income of B = 100x Rs. 
  So, total income of A  
  = 100x × (1 +
20
100
) = 120?? ???? . 
  ATQ – 
  (100x + 120x) ×
30
100
= 26400 
  66x = 26400 
  x = 400 Rs. 
  So, income of B = 400 × 100 = 40000 ???? . 
 
53. (e): Let sum invested by man = Rs. X 
  And, rate of interest = r%  
  ATQ- 
?? ×?? ×?? ?? ×?? ×(?? +4)
 = 
1
2
 
  
?? (?? +4)
 = 
1
2
 ? T = 4  
 
54. (d): Let total work = 12 × 64 = 768 units 
  Required women = 768 ×
2
3
 ×
1
16
= 32 
55. (e): Let length of train be ‘l’ meters  
  ATQ – 
  72 ×
5
18
= 
?? 30
  
  l = 600 meters 
  Required time = 
600
54×
5
18
 = 40 sec 
 
56. (a): ATQ – 
  14 × 6 - 10 × ?? = 44 
  10T = 40 
  T = 4 
 
57. (c): Let cost price of article = 100x Rs. 
  So, marked price of article = 100x × (1 +
50
100
) =
150 ?? Rs. 
  And, selling price of article = (150x – 50) Rs. 
  ATQ – 
  (150x – 50) – 100x = 50 
  50x = 100 
  x = 2 Rs. 
  So, selling price of article = (150 × 2 - 50) =
250 ???? . 
 
58. (e): ATQ – 
  
?? (?? +800)
 = 
3200 
(6800-3200)
 
  X = 6400  
 
59. (b): Let total initial mixture in vessel = 4x 
  So, milk in vessel = 3x 
  And water in vessel = x 
  ATQ – 
  (3x – 20 ×
3?? 4?? ) - (?? - 20 ×
?? 4?? ) = 70 
Quantitative Aptitude 
 
 
 
                                                   
 
 
  (3x – 15) – (x – 5) = 70 
  2x = 80 
  x = 40 
  So, initial mixture in vessel = 4x = 4 × 40 =
160 liters 
 
60. (c): Let radius of circle be ‘r’ cm 
  ATQ – 
  
22
7
 × ?? × ?? = 616  
  r = 14 cm = breath of rectangle 
  Let length of rectangle be ‘l’ cm 
  Perimeter of rectangle = circumference of a circle 
+ 2  
  2(14 + l) = 2 ×
22
7
 × 14 + 2 
  2(14 + l) = 90 
  l = 31 cm 
 
61. (d): Required difference = (80 + 100) – (70 + 90) = 20 
 
62. (a): Total orders (all three items) received by R = (80 
+ 100 + 30) = 210 
  Total orders (all three items) received by Q = (40 
+ 70 + 90) = 200 
  Required percentage = 
210-200
200
 × 100 = 5% 
 
63. (e): Total orders of item A & B received by P = 80 + 60 
= 140 
  Total orders of item B & C received by Q = 70 + 
90 = 160 
  Required ratio = 140 : 160 = 7 : 8 
 
64. (b): Average number of orders of item B received by 
Q & R = 
70+100
2
 = 85 
  Required percentage = 
85
80
 × 100 = 106
1
4
% 
 
65. (c): Required sum = 80 + 60 + 50 = 190 
 
66. (e): 
48
100
× 625×
4
3
=? ? ? = 400  
 
67. (c): 
64+324
97
=?  
  ? = 4  
 
68. (b): 4
?
 × 2 =
256
2
 
  4
?
 = 64 
  4
?
 = (4)
3 
  
? = 3 
 
69. (c): 4 × ? = 512- 480 
  ? = 
32
4
  
  ? = 8 
 
70. (e): ? + 432 – 206 = 550 
  ? = 550 – 226 
  ? = 324 
 
71. (a): (?)
2
 = 196 – 96 
  ?
2
 = 100 ? ? = 10 
 
 
72. (d): 
40
100
× 400+
300
100
×? = 250 
  160 + 3 × ? = 250 
  ? = 
90
3
= 30 
 
73. (b): ÷ 7 = ? -180 
  ? = 183 
 
74. (e): 24 – 12 + 27 = 36 + ? 
  ?= 3 
 
75. (b): 119 + 41 + 9 =?
2
  
  ? = 13  
 
76. (b): 
12
100
 × (? +100) = 18 
  ? = 150 – 100 
  ? = 50 
 
77. (c): 
11
11
+ 9+? = 27  
  1 + 9 + ? = 27 
  ? = 17 
 
78. (b): ?
2
 + 20 = 36 
  ?
2
 = 16 ? ? = 4 
 
79. (d): ? = 9
1
3
+ 7
1
2
- 5
1
6
- 6
1
3
  
  ? = 9 + 7 - 5 - 6 (
1
3
+
1
2
-
1
6
-
1
3
)  
  ? = 5
1
6
  
 
80. (c): 
3
4
×3
7×2
3
6×3
= 3
?
 
  3
?
 = 3
4+14-18 
  
3
?
 = 3
0 
  ? = 0