Page 1
IIT-JAM - 2021
SECTION – A
cos x
e
Multiple Choice Questions (MCQ)
Q1 – Q10 Carry One Mark Each
Q1. The function is Taylor expanded about 0 x = . The coefficient of
2
x is
(a)
1
2
- (b)
2
e
- (c)
2
e
(d) Zero
Ans. : (b)
Solution: ( )
cos x
fx e =
Taylor expansion about
0
xx = is
( ) ( ) ( ) ( )
( )
( )
2
0
0 0 0 0
...
2!
xx
fx fx x x f x f x
-
' '' = + - + +8
? Taylor expansion about 0 x =
( ) ( ) ( )
( )
2
0
00
2!
f
f x f xf x
''
' = + + + - -8
Coefficient of
2
x is
( ) 0
2!
f ''
( )
cos x
fx e = ( )
cos
sin
x
f x xe ' ? =-
( ) ( ) ( )
cos cos 2 cos
cos sin sin cos sin
xx x
f x xe x xe x x e
??
'' =- + - =- +
??
( ) ( )
1
0 10 f e e '' ? = -+ =-
? coefficients of
( )
2
0
2! 2
f
e
x
''
-
= =
Q2. Let M be a 22 × matrix. Its trace is 6 and its determinant has value 8. Its eigenvalues
are
(a) 2 and 4 (b) 3 and 3 (c) 2 and 6 (d) 2 - and 3 -
Ans. : (a)
Solution: M is a 22 × matrix
We know trace = sum of eigenvalues
and determinant = product of eigenvalues
Let eigenvalues are
1
? and
2
? .
12
6 ?? ?+ = and
12
8 ?? =
1
2 ? = ,
2
4 ? =
Page 2
IIT-JAM - 2021
SECTION – A
cos x
e
Multiple Choice Questions (MCQ)
Q1 – Q10 Carry One Mark Each
Q1. The function is Taylor expanded about 0 x = . The coefficient of
2
x is
(a)
1
2
- (b)
2
e
- (c)
2
e
(d) Zero
Ans. : (b)
Solution: ( )
cos x
fx e =
Taylor expansion about
0
xx = is
( ) ( ) ( ) ( )
( )
( )
2
0
0 0 0 0
...
2!
xx
fx fx x x f x f x
-
' '' = + - + +8
? Taylor expansion about 0 x =
( ) ( ) ( )
( )
2
0
00
2!
f
f x f xf x
''
' = + + + - -8
Coefficient of
2
x is
( ) 0
2!
f ''
( )
cos x
fx e = ( )
cos
sin
x
f x xe ' ? =-
( ) ( ) ( )
cos cos 2 cos
cos sin sin cos sin
xx x
f x xe x xe x x e
??
'' =- + - =- +
??
( ) ( )
1
0 10 f e e '' ? = -+ =-
? coefficients of
( )
2
0
2! 2
f
e
x
''
-
= =
Q2. Let M be a 22 × matrix. Its trace is 6 and its determinant has value 8. Its eigenvalues
are
(a) 2 and 4 (b) 3 and 3 (c) 2 and 6 (d) 2 - and 3 -
Ans. : (a)
Solution: M is a 22 × matrix
We know trace = sum of eigenvalues
and determinant = product of eigenvalues
Let eigenvalues are
1
? and
2
? .
12
6 ?? ?+ = and
12
8 ?? =
1
2 ? = ,
2
4 ? =
Q3. A planet is in a highly eccentric orbit about a star. The distance of its closest approach is
300 times smaller than its farthest distance from the star. If the corresponding speeds are
c
v and
f
v , then
c
f
v
v
is
(a)
1
300
(b)
1
300
(c) 300 (d) 300
Ans. : (d)
Solution: Using conservation of angular momentum
300
300
f
cc
c c f f
f c c
r
vr
mv r mv r
vr r
= ?= = =
Q4. An object of density ? is floating in a liquid with 75% of its volume submerged. The
density of the liquid is
(a)
4
3
? (b)
3
2
? (c)
8
5
? (d) 2 ?
Ans. : (a)
Solution: Weight of object equal to buoyancy force
34
43
V g Vdg d ?? = ?=
Q5. An experiment with a Michelson interferometer is performed in vacuum using a laser of
wavelength 610nm . One of the beams of the interferometer passes through a small glass
cavity 1.3cm long. After the cavity is completely filled with a medium of refractive
index ,472 n dark fringes are counted to move past a reference line. Given that the speed
of light is
8
3 10 / ms × , the value of n is
(a) 1.01 (b) 1.04 (c) 1.06 (d) 1.10
Ans. : (a)
Solution: Change in optical path xm ? ?= ( ) 2 1 n tm ? ? -=
9
2
472 610 10
1
2 2 1 3 10
n
n
t
?
-
-
××
? -= =
× · ×
1 0 011 n ? -= · 1 011 n ?= ·
Page 3
IIT-JAM - 2021
SECTION – A
cos x
e
Multiple Choice Questions (MCQ)
Q1 – Q10 Carry One Mark Each
Q1. The function is Taylor expanded about 0 x = . The coefficient of
2
x is
(a)
1
2
- (b)
2
e
- (c)
2
e
(d) Zero
Ans. : (b)
Solution: ( )
cos x
fx e =
Taylor expansion about
0
xx = is
( ) ( ) ( ) ( )
( )
( )
2
0
0 0 0 0
...
2!
xx
fx fx x x f x f x
-
' '' = + - + +8
? Taylor expansion about 0 x =
( ) ( ) ( )
( )
2
0
00
2!
f
f x f xf x
''
' = + + + - -8
Coefficient of
2
x is
( ) 0
2!
f ''
( )
cos x
fx e = ( )
cos
sin
x
f x xe ' ? =-
( ) ( ) ( )
cos cos 2 cos
cos sin sin cos sin
xx x
f x xe x xe x x e
??
'' =- + - =- +
??
( ) ( )
1
0 10 f e e '' ? = -+ =-
? coefficients of
( )
2
0
2! 2
f
e
x
''
-
= =
Q2. Let M be a 22 × matrix. Its trace is 6 and its determinant has value 8. Its eigenvalues
are
(a) 2 and 4 (b) 3 and 3 (c) 2 and 6 (d) 2 - and 3 -
Ans. : (a)
Solution: M is a 22 × matrix
We know trace = sum of eigenvalues
and determinant = product of eigenvalues
Let eigenvalues are
1
? and
2
? .
12
6 ?? ?+ = and
12
8 ?? =
1
2 ? = ,
2
4 ? =
Q3. A planet is in a highly eccentric orbit about a star. The distance of its closest approach is
300 times smaller than its farthest distance from the star. If the corresponding speeds are
c
v and
f
v , then
c
f
v
v
is
(a)
1
300
(b)
1
300
(c) 300 (d) 300
Ans. : (d)
Solution: Using conservation of angular momentum
300
300
f
cc
c c f f
f c c
r
vr
mv r mv r
vr r
= ?= = =
Q4. An object of density ? is floating in a liquid with 75% of its volume submerged. The
density of the liquid is
(a)
4
3
? (b)
3
2
? (c)
8
5
? (d) 2 ?
Ans. : (a)
Solution: Weight of object equal to buoyancy force
34
43
V g Vdg d ?? = ?=
Q5. An experiment with a Michelson interferometer is performed in vacuum using a laser of
wavelength 610nm . One of the beams of the interferometer passes through a small glass
cavity 1.3cm long. After the cavity is completely filled with a medium of refractive
index ,472 n dark fringes are counted to move past a reference line. Given that the speed
of light is
8
3 10 / ms × , the value of n is
(a) 1.01 (b) 1.04 (c) 1.06 (d) 1.10
Ans. : (a)
Solution: Change in optical path xm ? ?= ( ) 2 1 n tm ? ? -=
9
2
472 610 10
1
2 2 1 3 10
n
n
t
?
-
-
××
? -= =
× · ×
1 0 011 n ? -= · 1 011 n ?= ·
Q6. For a semiconductor material, the conventional flat band energy diagram is shown in the
figure. The variables , YX respectively, are
(a) Energy, Momentum
(b) Energy, Distance
(c) Distance, Energy
(d) Momentum, Energy
Ans. : (b)
Solution: Along the y-axis energy varies while along x-axis distance is variable.
Q7. For the given circuit,
D
V is the threshold voltage of the diode. The graph that best
deposits variation of
0
V with
i
V is
(a)
(b)
(c)
(d)
0
i
V
0
V
0
i
V
0
V
0
i
V
0
V
D
V 0
i
V
0
V
i
V
1k ?
1k ?
0
V
+
-
X
valence band
conduction band
Y
Page 4
IIT-JAM - 2021
SECTION – A
cos x
e
Multiple Choice Questions (MCQ)
Q1 – Q10 Carry One Mark Each
Q1. The function is Taylor expanded about 0 x = . The coefficient of
2
x is
(a)
1
2
- (b)
2
e
- (c)
2
e
(d) Zero
Ans. : (b)
Solution: ( )
cos x
fx e =
Taylor expansion about
0
xx = is
( ) ( ) ( ) ( )
( )
( )
2
0
0 0 0 0
...
2!
xx
fx fx x x f x f x
-
' '' = + - + +8
? Taylor expansion about 0 x =
( ) ( ) ( )
( )
2
0
00
2!
f
f x f xf x
''
' = + + + - -8
Coefficient of
2
x is
( ) 0
2!
f ''
( )
cos x
fx e = ( )
cos
sin
x
f x xe ' ? =-
( ) ( ) ( )
cos cos 2 cos
cos sin sin cos sin
xx x
f x xe x xe x x e
??
'' =- + - =- +
??
( ) ( )
1
0 10 f e e '' ? = -+ =-
? coefficients of
( )
2
0
2! 2
f
e
x
''
-
= =
Q2. Let M be a 22 × matrix. Its trace is 6 and its determinant has value 8. Its eigenvalues
are
(a) 2 and 4 (b) 3 and 3 (c) 2 and 6 (d) 2 - and 3 -
Ans. : (a)
Solution: M is a 22 × matrix
We know trace = sum of eigenvalues
and determinant = product of eigenvalues
Let eigenvalues are
1
? and
2
? .
12
6 ?? ?+ = and
12
8 ?? =
1
2 ? = ,
2
4 ? =
Q3. A planet is in a highly eccentric orbit about a star. The distance of its closest approach is
300 times smaller than its farthest distance from the star. If the corresponding speeds are
c
v and
f
v , then
c
f
v
v
is
(a)
1
300
(b)
1
300
(c) 300 (d) 300
Ans. : (d)
Solution: Using conservation of angular momentum
300
300
f
cc
c c f f
f c c
r
vr
mv r mv r
vr r
= ?= = =
Q4. An object of density ? is floating in a liquid with 75% of its volume submerged. The
density of the liquid is
(a)
4
3
? (b)
3
2
? (c)
8
5
? (d) 2 ?
Ans. : (a)
Solution: Weight of object equal to buoyancy force
34
43
V g Vdg d ?? = ?=
Q5. An experiment with a Michelson interferometer is performed in vacuum using a laser of
wavelength 610nm . One of the beams of the interferometer passes through a small glass
cavity 1.3cm long. After the cavity is completely filled with a medium of refractive
index ,472 n dark fringes are counted to move past a reference line. Given that the speed
of light is
8
3 10 / ms × , the value of n is
(a) 1.01 (b) 1.04 (c) 1.06 (d) 1.10
Ans. : (a)
Solution: Change in optical path xm ? ?= ( ) 2 1 n tm ? ? -=
9
2
472 610 10
1
2 2 1 3 10
n
n
t
?
-
-
××
? -= =
× · ×
1 0 011 n ? -= · 1 011 n ?= ·
Q6. For a semiconductor material, the conventional flat band energy diagram is shown in the
figure. The variables , YX respectively, are
(a) Energy, Momentum
(b) Energy, Distance
(c) Distance, Energy
(d) Momentum, Energy
Ans. : (b)
Solution: Along the y-axis energy varies while along x-axis distance is variable.
Q7. For the given circuit,
D
V is the threshold voltage of the diode. The graph that best
deposits variation of
0
V with
i
V is
(a)
(b)
(c)
(d)
0
i
V
0
V
0
i
V
0
V
0
i
V
0
V
D
V 0
i
V
0
V
i
V
1k ?
1k ?
0
V
+
-
X
valence band
conduction band
Y
Ans. : (a)
Solution:
Q8. Arrange the following telescopes, where D is the telescope diameter and ? is the
wavelength, in order of decreasing resolving power:
I. 100 , 21 D m cm ? = = II. 2 , 500 D m nm ? = =
III. 1 , 100 D m nm ? = = IV. 2 , 10 D m mm ? = =
(a) III, II, IV, I (b) II, III, I, IV
(c) IV, III, II, I (d) III, II, I, IV
Ans. : (d)
Solution: 1.22 d
D
?
? =
3
2.56 10
I
d ?
-
= × ;
7
3.05 10
II
d?
-
= ×
7
1.22 10
III
d ?
-
= × ;
3
6.1 10
IV
d ?
-
= ×
Resolving power
1
d ?
=
III II I IV
RP RP RP RP > >>
Q9. Metallic lithium has bcc crystal structure. Each unit cell is a cube of side a . The number
of atoms per unit volume is
(a)
3
1
a
(b)
3
2
2a
(c)
3
2
a
(d)
3
4
a
• •
• •
+
-
.. oc
.. sc i
V
1k ?
1k ?
0
V
+
-
Negative half Cycle
Postive half Cycle
.. oc
.. sc
i
V
1k ?
1k ?
0
V
+
-
+
-
• •
• • 0 =
0
1
1
ii
k
V VV
k
=-=
Page 5
IIT-JAM - 2021
SECTION – A
cos x
e
Multiple Choice Questions (MCQ)
Q1 – Q10 Carry One Mark Each
Q1. The function is Taylor expanded about 0 x = . The coefficient of
2
x is
(a)
1
2
- (b)
2
e
- (c)
2
e
(d) Zero
Ans. : (b)
Solution: ( )
cos x
fx e =
Taylor expansion about
0
xx = is
( ) ( ) ( ) ( )
( )
( )
2
0
0 0 0 0
...
2!
xx
fx fx x x f x f x
-
' '' = + - + +8
? Taylor expansion about 0 x =
( ) ( ) ( )
( )
2
0
00
2!
f
f x f xf x
''
' = + + + - -8
Coefficient of
2
x is
( ) 0
2!
f ''
( )
cos x
fx e = ( )
cos
sin
x
f x xe ' ? =-
( ) ( ) ( )
cos cos 2 cos
cos sin sin cos sin
xx x
f x xe x xe x x e
??
'' =- + - =- +
??
( ) ( )
1
0 10 f e e '' ? = -+ =-
? coefficients of
( )
2
0
2! 2
f
e
x
''
-
= =
Q2. Let M be a 22 × matrix. Its trace is 6 and its determinant has value 8. Its eigenvalues
are
(a) 2 and 4 (b) 3 and 3 (c) 2 and 6 (d) 2 - and 3 -
Ans. : (a)
Solution: M is a 22 × matrix
We know trace = sum of eigenvalues
and determinant = product of eigenvalues
Let eigenvalues are
1
? and
2
? .
12
6 ?? ?+ = and
12
8 ?? =
1
2 ? = ,
2
4 ? =
Q3. A planet is in a highly eccentric orbit about a star. The distance of its closest approach is
300 times smaller than its farthest distance from the star. If the corresponding speeds are
c
v and
f
v , then
c
f
v
v
is
(a)
1
300
(b)
1
300
(c) 300 (d) 300
Ans. : (d)
Solution: Using conservation of angular momentum
300
300
f
cc
c c f f
f c c
r
vr
mv r mv r
vr r
= ?= = =
Q4. An object of density ? is floating in a liquid with 75% of its volume submerged. The
density of the liquid is
(a)
4
3
? (b)
3
2
? (c)
8
5
? (d) 2 ?
Ans. : (a)
Solution: Weight of object equal to buoyancy force
34
43
V g Vdg d ?? = ?=
Q5. An experiment with a Michelson interferometer is performed in vacuum using a laser of
wavelength 610nm . One of the beams of the interferometer passes through a small glass
cavity 1.3cm long. After the cavity is completely filled with a medium of refractive
index ,472 n dark fringes are counted to move past a reference line. Given that the speed
of light is
8
3 10 / ms × , the value of n is
(a) 1.01 (b) 1.04 (c) 1.06 (d) 1.10
Ans. : (a)
Solution: Change in optical path xm ? ?= ( ) 2 1 n tm ? ? -=
9
2
472 610 10
1
2 2 1 3 10
n
n
t
?
-
-
××
? -= =
× · ×
1 0 011 n ? -= · 1 011 n ?= ·
Q6. For a semiconductor material, the conventional flat band energy diagram is shown in the
figure. The variables , YX respectively, are
(a) Energy, Momentum
(b) Energy, Distance
(c) Distance, Energy
(d) Momentum, Energy
Ans. : (b)
Solution: Along the y-axis energy varies while along x-axis distance is variable.
Q7. For the given circuit,
D
V is the threshold voltage of the diode. The graph that best
deposits variation of
0
V with
i
V is
(a)
(b)
(c)
(d)
0
i
V
0
V
0
i
V
0
V
0
i
V
0
V
D
V 0
i
V
0
V
i
V
1k ?
1k ?
0
V
+
-
X
valence band
conduction band
Y
Ans. : (a)
Solution:
Q8. Arrange the following telescopes, where D is the telescope diameter and ? is the
wavelength, in order of decreasing resolving power:
I. 100 , 21 D m cm ? = = II. 2 , 500 D m nm ? = =
III. 1 , 100 D m nm ? = = IV. 2 , 10 D m mm ? = =
(a) III, II, IV, I (b) II, III, I, IV
(c) IV, III, II, I (d) III, II, I, IV
Ans. : (d)
Solution: 1.22 d
D
?
? =
3
2.56 10
I
d ?
-
= × ;
7
3.05 10
II
d?
-
= ×
7
1.22 10
III
d ?
-
= × ;
3
6.1 10
IV
d ?
-
= ×
Resolving power
1
d ?
=
III II I IV
RP RP RP RP > >>
Q9. Metallic lithium has bcc crystal structure. Each unit cell is a cube of side a . The number
of atoms per unit volume is
(a)
3
1
a
(b)
3
2
2a
(c)
3
2
a
(d)
3
4
a
• •
• •
+
-
.. oc
.. sc i
V
1k ?
1k ?
0
V
+
-
Negative half Cycle
Postive half Cycle
.. oc
.. sc
i
V
1k ?
1k ?
0
V
+
-
+
-
• •
• • 0 =
0
1
1
ii
k
V VV
k
=-=
Ans. : (c)
Solution: The effective number of atoms in BCC is
1
81 2
8
eff
n = × +=
The volume of the bcc unit cell of side a is
3
a .
Thus, the number of atoms per unit volume is
3
2
a
= .
Therefore, the correct option is (c).
Q10. The moment of inertia of a solid sphere (radius R and mass M ) about the axis which is
at a distance of
2
R
from the centre is
(a)
2
3
20
MR (b)
2
1
2
MR (c)
2
13
20
MR (d)
2
9
10
MR
Ans. : (c)
Solution:
Using parallel axis theorem
2
0. C M
I I Md = + ;
2
R
d = ,
2
.
2
5
C M
I MR =
2
2
2 2 22
0
2 2 8 5 13
5 2 5 4 20 20
R MR
I MR M MR MR MR
+ ?? ? ?
= + = += =
?? ? ?
?? ? ?
Q11 – Q30. carry two marks each
Q11. Let ( ) , xy denote the coordinates in a rectangular Cartesian coordinate system C . Let
( ) , xy '' denote the coordinates in another coordinate system C ' defined by
23 x xy ' = +
34 y xy '=-+
The area element in C ' , is
(a)
1
17
dx dy '' (b) 12dx dy '' (c) dx dy '' (d) x dx dy '' '
Ans. : (a)
Solution: ( ) ( ) ,, C xy C x y ' '' ?
dxdy Jdx dy '' =
where
( )
( )
,
,
xy
J xy
xx
J
xy
Jx y
yy
??
'' ??
= =
?? ''
'' ??
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