JEE Exam > JEE Notes > BITSAT Mock Tests Series & Past Year Papers 2025 > BITSAT Past Year Paper- 2022
BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 Q u e s t i o n 1 T h e s t o p p i n g p o t e n t i a l ( V 0 ) v e r s u s f r e q u e n c y ( v ) o f a g r a p h f o r p h o t o e l e c t r i c e f f e c t i n a m e t a l . F r o m t h e g r a p h , t h e p l a n c k ' s c o n s t a n t ( h ) i s . O p t i o n s : A . 6 . 6 0 × 1 0 - 3 4 J - s B . 6 . 6 9 × 1 0 - 3 4 J - s C . 6 . 6 2 × 1 0 - 3 4 J - s D . 6 . 6 3 × 1 0 - 3 4 J - s A n s w e r : A S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 2 I n a r e s o n a n c e c o l u m n f i r s t a n d s e c o n d r e s o n a n c e a r e o b t a i n e d a t d e p t h s 2 4 c m a n d 7 8 c m t h e t h i r d r e s o n a n c e w i l l b e o b t a i n e d a t d e p t h . O p t i o n s : e V 0 = h ( v - v 0 ) = h v - h v 0 V 0 = h e v - h v v 0 . . . . . . . . . . . . . . . . ( i ) F r o m E q . ( i ) , i t f o l l o w s t h a t t h e s l o p e o f t h e g r a p h i s h e . T h e r e f o r e , h = e × s l o p e = 1 . 6 × 1 0 - 1 9 × 1 6 5 - 0 ( 8 - 4 ) × 1 0 1 5 = 1 6 × 1 0 - 1 9 × 1 6 . 5 4 × 1 0 1 5 = 6 . 6 × 1 0 - 3 4 J - s . ( ) ( ) BITSAT - Paper 2022 Solved Paper Page 2 Q u e s t i o n 1 T h e s t o p p i n g p o t e n t i a l ( V 0 ) v e r s u s f r e q u e n c y ( v ) o f a g r a p h f o r p h o t o e l e c t r i c e f f e c t i n a m e t a l . F r o m t h e g r a p h , t h e p l a n c k ' s c o n s t a n t ( h ) i s . O p t i o n s : A . 6 . 6 0 × 1 0 - 3 4 J - s B . 6 . 6 9 × 1 0 - 3 4 J - s C . 6 . 6 2 × 1 0 - 3 4 J - s D . 6 . 6 3 × 1 0 - 3 4 J - s A n s w e r : A S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 2 I n a r e s o n a n c e c o l u m n f i r s t a n d s e c o n d r e s o n a n c e a r e o b t a i n e d a t d e p t h s 2 4 c m a n d 7 8 c m t h e t h i r d r e s o n a n c e w i l l b e o b t a i n e d a t d e p t h . O p t i o n s : e V 0 = h ( v - v 0 ) = h v - h v 0 V 0 = h e v - h v v 0 . . . . . . . . . . . . . . . . ( i ) F r o m E q . ( i ) , i t f o l l o w s t h a t t h e s l o p e o f t h e g r a p h i s h e . T h e r e f o r e , h = e × s l o p e = 1 . 6 × 1 0 - 1 9 × 1 6 5 - 0 ( 8 - 4 ) × 1 0 1 5 = 1 6 × 1 0 - 1 9 × 1 6 . 5 4 × 1 0 1 5 = 6 . 6 × 1 0 - 3 4 J - s . ( ) ( ) BITSAT - Paper 2022 Solved Paper A . 1 6 0 c m B . 1 3 2 c m C . 1 3 1 c m D . 1 5 2 c m A n s w e r : B S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 3 A s u b m a r i n e A t r a v e l l i n g a t 1 7 m s i s b e i n g c h a s e d a l o n g t h e l i n e o f i t s v e l o c i t y b y a n o t h e r s u b m a r i n e B t r a v e l l i n g a t 3 4 m s . B s e n d s a s o n a r s i g n a l o f 6 0 0 H z t o d e t e c t A a n d r e c e i v e s a r e f l e c t e d s o u n d o f f r e q u e n c y v . T h e o f v i s [ S p e e d o f s o u n d i n w a t e r = 1 5 0 0 m s - 1 ] O p t i o n s : A . 6 1 3 . 7 H z B . 6 1 3 7 H z C . 6 2 H z D . 5 3 9 H z A n s w e r : A S o l u t i o n : S o l u t i o n : G i v e n , f i r s t r e s o n a n c e c o l u m n a t d e o t h , l 1 = 2 4 c m S e c o n d r e s o n a n c e c o l u m n a t d e p t h , l 2 = 7 8 c m T h i r d r e s o n a n c e c o l u m n a t d e p t h , l 3 = ? A s l 1 + x = ? 4 = 2 4 . . . . . . . . . . . . . . . ( i ) l 2 + x = 3 ? 4 = 7 8 . . . . . . . . . . . . . . . . ( i i ) l 3 + x = 5 ? 4 . . . . . . . . . . . . . . . . ( i i i ) F r o m E q s . ( i ) a n d ( i i ) , x = l 2 - 3 l 1 2 = 7 8 - 3 ( 2 4 ) 2 = 3 . . . . . . . . . . . . . . . . . . ( i v ) s u b s t i t u t i n g l 1 a n d x v a l u e , w e g e t l 3 = 5 ( 2 4 ) + 4 ( 3 ) ? l 3 = 1 3 2 c m . G i v e n , v e l o c i t y o f s u b m a r i n e A , v A 1 7 m / s V e l o c i t y o f S u b m a r i n e B , v B = 3 4 m / s S i g n a l s e n t b y s u b m a r i n e B i s d e t e c t e d b y s u b m a r i n e A c a n b e s h o w n a s Page 3 Q u e s t i o n 1 T h e s t o p p i n g p o t e n t i a l ( V 0 ) v e r s u s f r e q u e n c y ( v ) o f a g r a p h f o r p h o t o e l e c t r i c e f f e c t i n a m e t a l . F r o m t h e g r a p h , t h e p l a n c k ' s c o n s t a n t ( h ) i s . O p t i o n s : A . 6 . 6 0 × 1 0 - 3 4 J - s B . 6 . 6 9 × 1 0 - 3 4 J - s C . 6 . 6 2 × 1 0 - 3 4 J - s D . 6 . 6 3 × 1 0 - 3 4 J - s A n s w e r : A S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 2 I n a r e s o n a n c e c o l u m n f i r s t a n d s e c o n d r e s o n a n c e a r e o b t a i n e d a t d e p t h s 2 4 c m a n d 7 8 c m t h e t h i r d r e s o n a n c e w i l l b e o b t a i n e d a t d e p t h . O p t i o n s : e V 0 = h ( v - v 0 ) = h v - h v 0 V 0 = h e v - h v v 0 . . . . . . . . . . . . . . . . ( i ) F r o m E q . ( i ) , i t f o l l o w s t h a t t h e s l o p e o f t h e g r a p h i s h e . T h e r e f o r e , h = e × s l o p e = 1 . 6 × 1 0 - 1 9 × 1 6 5 - 0 ( 8 - 4 ) × 1 0 1 5 = 1 6 × 1 0 - 1 9 × 1 6 . 5 4 × 1 0 1 5 = 6 . 6 × 1 0 - 3 4 J - s . ( ) ( ) BITSAT - Paper 2022 Solved Paper A . 1 6 0 c m B . 1 3 2 c m C . 1 3 1 c m D . 1 5 2 c m A n s w e r : B S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 3 A s u b m a r i n e A t r a v e l l i n g a t 1 7 m s i s b e i n g c h a s e d a l o n g t h e l i n e o f i t s v e l o c i t y b y a n o t h e r s u b m a r i n e B t r a v e l l i n g a t 3 4 m s . B s e n d s a s o n a r s i g n a l o f 6 0 0 H z t o d e t e c t A a n d r e c e i v e s a r e f l e c t e d s o u n d o f f r e q u e n c y v . T h e o f v i s [ S p e e d o f s o u n d i n w a t e r = 1 5 0 0 m s - 1 ] O p t i o n s : A . 6 1 3 . 7 H z B . 6 1 3 7 H z C . 6 2 H z D . 5 3 9 H z A n s w e r : A S o l u t i o n : S o l u t i o n : G i v e n , f i r s t r e s o n a n c e c o l u m n a t d e o t h , l 1 = 2 4 c m S e c o n d r e s o n a n c e c o l u m n a t d e p t h , l 2 = 7 8 c m T h i r d r e s o n a n c e c o l u m n a t d e p t h , l 3 = ? A s l 1 + x = ? 4 = 2 4 . . . . . . . . . . . . . . . ( i ) l 2 + x = 3 ? 4 = 7 8 . . . . . . . . . . . . . . . . ( i i ) l 3 + x = 5 ? 4 . . . . . . . . . . . . . . . . ( i i i ) F r o m E q s . ( i ) a n d ( i i ) , x = l 2 - 3 l 1 2 = 7 8 - 3 ( 2 4 ) 2 = 3 . . . . . . . . . . . . . . . . . . ( i v ) s u b s t i t u t i n g l 1 a n d x v a l u e , w e g e t l 3 = 5 ( 2 4 ) + 4 ( 3 ) ? l 3 = 1 3 2 c m . G i v e n , v e l o c i t y o f s u b m a r i n e A , v A 1 7 m / s V e l o c i t y o f S u b m a r i n e B , v B = 3 4 m / s S i g n a l s e n t b y s u b m a r i n e B i s d e t e c t e d b y s u b m a r i n e A c a n b e s h o w n a s - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 4 T r a n s v e r s e w a v e s o f t h e s a m e f r e q u e n c y a r e g e n e r a t e d i n t w o s t e e l w i r e s A a n d B . T h e d i a m e t e r o f A i s t w i c e t h a t o f B a n d t h e t e n s i o n i n A i s h a l f t h a t i n B . T h e r a t i o o f t h e v e l o c i t i e s o f t h e w a v e s i n A a n d B i s O p t i o n s : A . 1 : 2 B . 1 : v 2 C . 1 : 2 v 2 D . 3 : 2 v 2 A n s w e r : C S o l u t i o n : S o l u t i o n : F r e q u e n c y o f t h e s i g n a l , f 0 = 6 0 0 H z s p e e d o f s o u n d i n w a t e r v s = 1 5 0 0 m s - 1 F r e q u e n c y r e c e i v e d b y s u b m a r i n e A i s f 1 = v S - v A v S - v B f 0 = 1 5 0 0 - 1 7 1 5 0 0 - 3 4 × 6 0 0 h z f 1 = 1 4 8 3 1 4 6 6 × 6 0 0 . . . . . . . . . . . . ( i ) F r e q u e n c y r e c e i v e d b y s u b m a r i n e i s f 2 = v S + v B v s v A f 1 S u b s t i t u t i n g g i v e n v a l u e s a n d f 1 v a l u e f r o m E q . ( i ) , w e g e t f 2 = 1 5 0 0 + 3 4 1 5 0 0 + 1 7 × 1 4 8 3 1 4 6 6 × 6 0 0 f 2 = 1 . 0 1 1 2 × 1 . 0 1 1 5 × 6 0 0 f 2 = 6 1 3 . 7 H z . ( ) [ ] ( ) ( ) [ ] T h e v e l o c i t y i f t r a n s v e r s e w a v e s i s g i v e n b y v = T m w h e r e , T = T e n s i o n a n d m = m a s s p e r u n i t l e n g t h o f t h e w i r e . I f r i s t h e r a d i u s i f t h e w i r e a n d ? i t s d e n s i t y t h e n , m = p r 2 ? ? v = T m = T p r 2 ? ? v A = v T A r A v p ? a n d v B = v T B r B v p ? N o w , v a v B = T A T B . r B r A v v v v Page 4 Q u e s t i o n 1 T h e s t o p p i n g p o t e n t i a l ( V 0 ) v e r s u s f r e q u e n c y ( v ) o f a g r a p h f o r p h o t o e l e c t r i c e f f e c t i n a m e t a l . F r o m t h e g r a p h , t h e p l a n c k ' s c o n s t a n t ( h ) i s . O p t i o n s : A . 6 . 6 0 × 1 0 - 3 4 J - s B . 6 . 6 9 × 1 0 - 3 4 J - s C . 6 . 6 2 × 1 0 - 3 4 J - s D . 6 . 6 3 × 1 0 - 3 4 J - s A n s w e r : A S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 2 I n a r e s o n a n c e c o l u m n f i r s t a n d s e c o n d r e s o n a n c e a r e o b t a i n e d a t d e p t h s 2 4 c m a n d 7 8 c m t h e t h i r d r e s o n a n c e w i l l b e o b t a i n e d a t d e p t h . O p t i o n s : e V 0 = h ( v - v 0 ) = h v - h v 0 V 0 = h e v - h v v 0 . . . . . . . . . . . . . . . . ( i ) F r o m E q . ( i ) , i t f o l l o w s t h a t t h e s l o p e o f t h e g r a p h i s h e . T h e r e f o r e , h = e × s l o p e = 1 . 6 × 1 0 - 1 9 × 1 6 5 - 0 ( 8 - 4 ) × 1 0 1 5 = 1 6 × 1 0 - 1 9 × 1 6 . 5 4 × 1 0 1 5 = 6 . 6 × 1 0 - 3 4 J - s . ( ) ( ) BITSAT - Paper 2022 Solved Paper A . 1 6 0 c m B . 1 3 2 c m C . 1 3 1 c m D . 1 5 2 c m A n s w e r : B S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 3 A s u b m a r i n e A t r a v e l l i n g a t 1 7 m s i s b e i n g c h a s e d a l o n g t h e l i n e o f i t s v e l o c i t y b y a n o t h e r s u b m a r i n e B t r a v e l l i n g a t 3 4 m s . B s e n d s a s o n a r s i g n a l o f 6 0 0 H z t o d e t e c t A a n d r e c e i v e s a r e f l e c t e d s o u n d o f f r e q u e n c y v . T h e o f v i s [ S p e e d o f s o u n d i n w a t e r = 1 5 0 0 m s - 1 ] O p t i o n s : A . 6 1 3 . 7 H z B . 6 1 3 7 H z C . 6 2 H z D . 5 3 9 H z A n s w e r : A S o l u t i o n : S o l u t i o n : G i v e n , f i r s t r e s o n a n c e c o l u m n a t d e o t h , l 1 = 2 4 c m S e c o n d r e s o n a n c e c o l u m n a t d e p t h , l 2 = 7 8 c m T h i r d r e s o n a n c e c o l u m n a t d e p t h , l 3 = ? A s l 1 + x = ? 4 = 2 4 . . . . . . . . . . . . . . . ( i ) l 2 + x = 3 ? 4 = 7 8 . . . . . . . . . . . . . . . . ( i i ) l 3 + x = 5 ? 4 . . . . . . . . . . . . . . . . ( i i i ) F r o m E q s . ( i ) a n d ( i i ) , x = l 2 - 3 l 1 2 = 7 8 - 3 ( 2 4 ) 2 = 3 . . . . . . . . . . . . . . . . . . ( i v ) s u b s t i t u t i n g l 1 a n d x v a l u e , w e g e t l 3 = 5 ( 2 4 ) + 4 ( 3 ) ? l 3 = 1 3 2 c m . G i v e n , v e l o c i t y o f s u b m a r i n e A , v A 1 7 m / s V e l o c i t y o f S u b m a r i n e B , v B = 3 4 m / s S i g n a l s e n t b y s u b m a r i n e B i s d e t e c t e d b y s u b m a r i n e A c a n b e s h o w n a s - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 4 T r a n s v e r s e w a v e s o f t h e s a m e f r e q u e n c y a r e g e n e r a t e d i n t w o s t e e l w i r e s A a n d B . T h e d i a m e t e r o f A i s t w i c e t h a t o f B a n d t h e t e n s i o n i n A i s h a l f t h a t i n B . T h e r a t i o o f t h e v e l o c i t i e s o f t h e w a v e s i n A a n d B i s O p t i o n s : A . 1 : 2 B . 1 : v 2 C . 1 : 2 v 2 D . 3 : 2 v 2 A n s w e r : C S o l u t i o n : S o l u t i o n : F r e q u e n c y o f t h e s i g n a l , f 0 = 6 0 0 H z s p e e d o f s o u n d i n w a t e r v s = 1 5 0 0 m s - 1 F r e q u e n c y r e c e i v e d b y s u b m a r i n e A i s f 1 = v S - v A v S - v B f 0 = 1 5 0 0 - 1 7 1 5 0 0 - 3 4 × 6 0 0 h z f 1 = 1 4 8 3 1 4 6 6 × 6 0 0 . . . . . . . . . . . . ( i ) F r e q u e n c y r e c e i v e d b y s u b m a r i n e i s f 2 = v S + v B v s v A f 1 S u b s t i t u t i n g g i v e n v a l u e s a n d f 1 v a l u e f r o m E q . ( i ) , w e g e t f 2 = 1 5 0 0 + 3 4 1 5 0 0 + 1 7 × 1 4 8 3 1 4 6 6 × 6 0 0 f 2 = 1 . 0 1 1 2 × 1 . 0 1 1 5 × 6 0 0 f 2 = 6 1 3 . 7 H z . ( ) [ ] ( ) ( ) [ ] T h e v e l o c i t y i f t r a n s v e r s e w a v e s i s g i v e n b y v = T m w h e r e , T = T e n s i o n a n d m = m a s s p e r u n i t l e n g t h o f t h e w i r e . I f r i s t h e r a d i u s i f t h e w i r e a n d ? i t s d e n s i t y t h e n , m = p r 2 ? ? v = T m = T p r 2 ? ? v A = v T A r A v p ? a n d v B = v T B r B v p ? N o w , v a v B = T A T B . r B r A v v v v - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 5 I n t h e d i a g r a m s h o w n b e l o w , b o t h t h e s t r i n g s A B a n d C D a r e m a d e o f s a m e m a t e r i a l a n d h a v e s a m e c r o s s - s e c t i o n . T h e p u l l e y s a r e l i g h t a n d f i c t i o n l e s s . I f t h e s p e e d o f w a v e i n s t r i n g A B i s v 1 a n d i n C D i s v 2 , t h e n v 1 v 2 i s O p t i o n s : A . 1 B . v 2 C . 2 D . 1 v 2 A n s w e r : D S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 6 W h a t w i l l b e t h e a c c e l e r a t i o n d u e t o g r a v i t y a t a d e p t h d , w h e r e g i s ? r A = 2 r B a n d T A = 1 2 T B H e n c e , v A v B = 1 2 v 2 L e t t h e s p e e d o f w a v e i n s t r i n g b e v a n d t e n s i o n i n s t r i n g b e T . v ? v T v A B v C D = v T 2 T = 1 v 2 Page 5 Q u e s t i o n 1 T h e s t o p p i n g p o t e n t i a l ( V 0 ) v e r s u s f r e q u e n c y ( v ) o f a g r a p h f o r p h o t o e l e c t r i c e f f e c t i n a m e t a l . F r o m t h e g r a p h , t h e p l a n c k ' s c o n s t a n t ( h ) i s . O p t i o n s : A . 6 . 6 0 × 1 0 - 3 4 J - s B . 6 . 6 9 × 1 0 - 3 4 J - s C . 6 . 6 2 × 1 0 - 3 4 J - s D . 6 . 6 3 × 1 0 - 3 4 J - s A n s w e r : A S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 2 I n a r e s o n a n c e c o l u m n f i r s t a n d s e c o n d r e s o n a n c e a r e o b t a i n e d a t d e p t h s 2 4 c m a n d 7 8 c m t h e t h i r d r e s o n a n c e w i l l b e o b t a i n e d a t d e p t h . O p t i o n s : e V 0 = h ( v - v 0 ) = h v - h v 0 V 0 = h e v - h v v 0 . . . . . . . . . . . . . . . . ( i ) F r o m E q . ( i ) , i t f o l l o w s t h a t t h e s l o p e o f t h e g r a p h i s h e . T h e r e f o r e , h = e × s l o p e = 1 . 6 × 1 0 - 1 9 × 1 6 5 - 0 ( 8 - 4 ) × 1 0 1 5 = 1 6 × 1 0 - 1 9 × 1 6 . 5 4 × 1 0 1 5 = 6 . 6 × 1 0 - 3 4 J - s . ( ) ( ) BITSAT - Paper 2022 Solved Paper A . 1 6 0 c m B . 1 3 2 c m C . 1 3 1 c m D . 1 5 2 c m A n s w e r : B S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 3 A s u b m a r i n e A t r a v e l l i n g a t 1 7 m s i s b e i n g c h a s e d a l o n g t h e l i n e o f i t s v e l o c i t y b y a n o t h e r s u b m a r i n e B t r a v e l l i n g a t 3 4 m s . B s e n d s a s o n a r s i g n a l o f 6 0 0 H z t o d e t e c t A a n d r e c e i v e s a r e f l e c t e d s o u n d o f f r e q u e n c y v . T h e o f v i s [ S p e e d o f s o u n d i n w a t e r = 1 5 0 0 m s - 1 ] O p t i o n s : A . 6 1 3 . 7 H z B . 6 1 3 7 H z C . 6 2 H z D . 5 3 9 H z A n s w e r : A S o l u t i o n : S o l u t i o n : G i v e n , f i r s t r e s o n a n c e c o l u m n a t d e o t h , l 1 = 2 4 c m S e c o n d r e s o n a n c e c o l u m n a t d e p t h , l 2 = 7 8 c m T h i r d r e s o n a n c e c o l u m n a t d e p t h , l 3 = ? A s l 1 + x = ? 4 = 2 4 . . . . . . . . . . . . . . . ( i ) l 2 + x = 3 ? 4 = 7 8 . . . . . . . . . . . . . . . . ( i i ) l 3 + x = 5 ? 4 . . . . . . . . . . . . . . . . ( i i i ) F r o m E q s . ( i ) a n d ( i i ) , x = l 2 - 3 l 1 2 = 7 8 - 3 ( 2 4 ) 2 = 3 . . . . . . . . . . . . . . . . . . ( i v ) s u b s t i t u t i n g l 1 a n d x v a l u e , w e g e t l 3 = 5 ( 2 4 ) + 4 ( 3 ) ? l 3 = 1 3 2 c m . G i v e n , v e l o c i t y o f s u b m a r i n e A , v A 1 7 m / s V e l o c i t y o f S u b m a r i n e B , v B = 3 4 m / s S i g n a l s e n t b y s u b m a r i n e B i s d e t e c t e d b y s u b m a r i n e A c a n b e s h o w n a s - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 4 T r a n s v e r s e w a v e s o f t h e s a m e f r e q u e n c y a r e g e n e r a t e d i n t w o s t e e l w i r e s A a n d B . T h e d i a m e t e r o f A i s t w i c e t h a t o f B a n d t h e t e n s i o n i n A i s h a l f t h a t i n B . T h e r a t i o o f t h e v e l o c i t i e s o f t h e w a v e s i n A a n d B i s O p t i o n s : A . 1 : 2 B . 1 : v 2 C . 1 : 2 v 2 D . 3 : 2 v 2 A n s w e r : C S o l u t i o n : S o l u t i o n : F r e q u e n c y o f t h e s i g n a l , f 0 = 6 0 0 H z s p e e d o f s o u n d i n w a t e r v s = 1 5 0 0 m s - 1 F r e q u e n c y r e c e i v e d b y s u b m a r i n e A i s f 1 = v S - v A v S - v B f 0 = 1 5 0 0 - 1 7 1 5 0 0 - 3 4 × 6 0 0 h z f 1 = 1 4 8 3 1 4 6 6 × 6 0 0 . . . . . . . . . . . . ( i ) F r e q u e n c y r e c e i v e d b y s u b m a r i n e i s f 2 = v S + v B v s v A f 1 S u b s t i t u t i n g g i v e n v a l u e s a n d f 1 v a l u e f r o m E q . ( i ) , w e g e t f 2 = 1 5 0 0 + 3 4 1 5 0 0 + 1 7 × 1 4 8 3 1 4 6 6 × 6 0 0 f 2 = 1 . 0 1 1 2 × 1 . 0 1 1 5 × 6 0 0 f 2 = 6 1 3 . 7 H z . ( ) [ ] ( ) ( ) [ ] T h e v e l o c i t y i f t r a n s v e r s e w a v e s i s g i v e n b y v = T m w h e r e , T = T e n s i o n a n d m = m a s s p e r u n i t l e n g t h o f t h e w i r e . I f r i s t h e r a d i u s i f t h e w i r e a n d ? i t s d e n s i t y t h e n , m = p r 2 ? ? v = T m = T p r 2 ? ? v A = v T A r A v p ? a n d v B = v T B r B v p ? N o w , v a v B = T A T B . r B r A v v v v - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 5 I n t h e d i a g r a m s h o w n b e l o w , b o t h t h e s t r i n g s A B a n d C D a r e m a d e o f s a m e m a t e r i a l a n d h a v e s a m e c r o s s - s e c t i o n . T h e p u l l e y s a r e l i g h t a n d f i c t i o n l e s s . I f t h e s p e e d o f w a v e i n s t r i n g A B i s v 1 a n d i n C D i s v 2 , t h e n v 1 v 2 i s O p t i o n s : A . 1 B . v 2 C . 2 D . 1 v 2 A n s w e r : D S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 6 W h a t w i l l b e t h e a c c e l e r a t i o n d u e t o g r a v i t y a t a d e p t h d , w h e r e g i s ? r A = 2 r B a n d T A = 1 2 T B H e n c e , v A v B = 1 2 v 2 L e t t h e s p e e d o f w a v e i n s t r i n g b e v a n d t e n s i o n i n s t r i n g b e T . v ? v T v A B v C D = v T 2 T = 1 v 2 a c c e l e r a t i o n d u e t o g r a v i t y o n t h e s u r f a c e o f e a r t h ? O p t i o n s : A . g 1 + d R 2 B . g 1 - 2 d R C . g 1 - d R 2 D . g 1 - d R A n s w e r : D S o l u t i o n : S o l u t i o n : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Q u e s t i o n 7 A d i r e c t c u r r e n t o f 6 A i s s u p e r i m p o s e d o n a n a l t e r n a t i n g c u r r e n t I = 1 0 s i n ? t f l o w i n g t h r o u g h a w i r e . T h e e f f e c t i v e v a l u e o f t h e r e s u l t i n g c u r r e n t w i l l b e O p t i o n s : A . 5 v 2 B . 5 v 3 C . 9 . 2 7 D . 8 . 3 7 A n s w e r : C S o l u t i o n : S o l u t i o n : [ ] [ ] [ ] [ ] A c c e l e r a t i o n d u e t o g r a v i t y a t t h e s u r f a c e o f e a r t h , g = G M R 2 = 4 3 p ? G R . . . . . . . . . . . . . . . . . ( i ) ? M = 4 3 p R 3 . ? W h e r e , ? = d e n s i t y o f e a r t h . A c c e l e r a t i o n d u e t o g r a v i t y a t d e p t h d f r o m t h e s u r f a c e o f e a r t h , g ' = 4 3 p ? G ( R - d ) . . . . . . . . . . . ( i i ) F r o m E q s . ( i ) a n d ( i i ) , w e g e t g ' = g 1 - d R [ ] [ ] G i v e n , I = 6 + 1 0 s i n ? tRead More
|
2 videos|17 docs|85 tests
|
About this Document
|
2.6K Views |
|
4.75/5 Rating |
|
Dec 23, 2024 Last updated |
Document Description: BITSAT Past Year Paper- 2022 for JEE 2024 is part of BITSAT Mock Tests Series & Past Year Papers 2025 preparation.
The notes and questions for BITSAT Past Year Paper- 2022 have been prepared according to the JEE exam syllabus. Information about BITSAT Past Year Paper- 2022 covers topics
like and BITSAT Past Year Paper- 2022 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for BITSAT Past Year Paper- 2022.
Introduction of BITSAT Past Year Paper- 2022 in English is available as part of our BITSAT Mock Tests Series & Past Year Papers 2025
for JEE & BITSAT Past Year Paper- 2022 in Hindi for BITSAT Mock Tests Series & Past Year Papers 2025 course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE
Description
Full syllabus notes, lecture & questions for BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE - JEE | Plus excerises question with solution to help you revise complete syllabus for BITSAT Mock Tests Series & Past Year Papers 2025 | Best notes, free PDF download
Information about BITSAT Past Year Paper- 2022
In this doc you can find the meaning of BITSAT Past Year Paper- 2022 defined & explained in the simplest way possible. Besides explaining types of
BITSAT Past Year Paper- 2022 theory, EduRev gives you an ample number of questions to practice BITSAT Past Year Paper- 2022 tests, examples and also practice JEE
tests
|
2 videos|17 docs|85 tests
|
Download as PDF
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE
,practice quizzes
,Important questions
,BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE
,mock tests for examination
,video lectures
,shortcuts and tricks
,MCQs
,past year papers
,Sample Paper
,Summary
,Previous Year Questions with Solutions
,Viva Questions
,Exam
,ppt
,BITSAT Past Year Paper- 2022 | BITSAT Mock Tests Series & Past Year Papers 2025 - JEE
,Semester Notes
,Objective type Questions
,study material
,Extra Questions
,Free
;
Additional Information about BITSAT Past Year Paper- 2022 for JEE Preparation
BITSAT Past Year Paper- 2022 Free PDF Download
The BITSAT Past Year Paper- 2022 is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the BITSAT Past Year Paper- 2022 now and kickstart your journey towards success in the JEE exam.
Importance of BITSAT Past Year Paper- 2022
The importance of BITSAT Past Year Paper- 2022 cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
BITSAT Past Year Paper- 2022 Notes
BITSAT Past Year Paper- 2022 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to BITSAT Past Year Paper- 2022.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, BITSAT Past Year Paper- 2022 Notes on EduRev are your ultimate resource for success.
BITSAT Past Year Paper- 2022 JEE Questions
The "BITSAT Past Year Paper- 2022 JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study BITSAT Past Year Paper- 2022 on the App
Students of JEE can study BITSAT Past Year Paper- 2022 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the BITSAT Past Year Paper- 2022,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of BITSAT Past Year Paper- 2022 is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup