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Thermal Properties of Matter: JEE Main Previous Year Questions (2021-2026)

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JEE Main Previous Year Questions (2021-2026): 
Thermal Properties of Matter 
 
(January 2026) 
 
Q1: Two wires A and B made of different materials of lengths 6.0 cm and 5.4 cm , 
respectively and area of cross sections 3.0 × 10
-5
 m
2
 and 4.5 × 10
-5
 m
2
 , respectively are 
stretched by the same magnitude under a given load. The ratio of the Young's modulus of 
A to that of B is x : 3. The value of x is 
(a) 2 
(b) 1 
(c) 4 
(d) 5 
Ans: (d) 
Sol:  
 
Young's Modulus is given by : 
 
Where: 
F is the applied force (load) 
L is the original length. 
A is the area of cross-section 
Page 2


JEE Main Previous Year Questions (2021-2026): 
Thermal Properties of Matter 
 
(January 2026) 
 
Q1: Two wires A and B made of different materials of lengths 6.0 cm and 5.4 cm , 
respectively and area of cross sections 3.0 × 10
-5
 m
2
 and 4.5 × 10
-5
 m
2
 , respectively are 
stretched by the same magnitude under a given load. The ratio of the Young's modulus of 
A to that of B is x : 3. The value of x is 
(a) 2 
(b) 1 
(c) 4 
(d) 5 
Ans: (d) 
Sol:  
 
Young's Modulus is given by : 
 
Where: 
F is the applied force (load) 
L is the original length. 
A is the area of cross-section 
?L is the change in length (stretching) According to question, both wires are stretched by the 
same magnitude (?L
A
 = ?L
B
) under the same given load (F
A
 = F
B
).  
Therefore, for both wires: 
 
Let Y
A
 and Y
B
 be the Young's moduli for wires A and B: 
 
The given values : 
 
So, the value of x is 5 . Hence, the correct option is (d). 
 
 
Q2: A cubical block of density ?
b
 = 600 kg / m
3
 floats in a liquid of density ?
e
 = 900 kg / m
3
. 
If the height of block is H = 8.0 cm then height of the submerged part is ____ cm.  
(a) 6.3  
(b) 4.3  
(c) 7.3  
(d) 5.3  
Ans: (d) 
Sol:  
When an object floats in a liquid, the weight of the object is exactly balanced by the buoyant 
force (up thrust) exerted by the liquid. 
Page 3


JEE Main Previous Year Questions (2021-2026): 
Thermal Properties of Matter 
 
(January 2026) 
 
Q1: Two wires A and B made of different materials of lengths 6.0 cm and 5.4 cm , 
respectively and area of cross sections 3.0 × 10
-5
 m
2
 and 4.5 × 10
-5
 m
2
 , respectively are 
stretched by the same magnitude under a given load. The ratio of the Young's modulus of 
A to that of B is x : 3. The value of x is 
(a) 2 
(b) 1 
(c) 4 
(d) 5 
Ans: (d) 
Sol:  
 
Young's Modulus is given by : 
 
Where: 
F is the applied force (load) 
L is the original length. 
A is the area of cross-section 
?L is the change in length (stretching) According to question, both wires are stretched by the 
same magnitude (?L
A
 = ?L
B
) under the same given load (F
A
 = F
B
).  
Therefore, for both wires: 
 
Let Y
A
 and Y
B
 be the Young's moduli for wires A and B: 
 
The given values : 
 
So, the value of x is 5 . Hence, the correct option is (d). 
 
 
Q2: A cubical block of density ?
b
 = 600 kg / m
3
 floats in a liquid of density ?
e
 = 900 kg / m
3
. 
If the height of block is H = 8.0 cm then height of the submerged part is ____ cm.  
(a) 6.3  
(b) 4.3  
(c) 7.3  
(d) 5.3  
Ans: (d) 
Sol:  
When an object floats in a liquid, the weight of the object is exactly balanced by the buoyant 
force (up thrust) exerted by the liquid. 
 
Weight of block is  
Buoyant force (F
B
) acting on a submerged body is equal to the weight of displaced liquid, 
 
For flotation : 
 
For a cubical block with a uniform cross-sectional area (A): 
Total Volume = V
total 
= AH 
Submerged Volume V
submerged
 = Ah  (where h is the submerged height) 
 
Putting the given values, 
Page 4


JEE Main Previous Year Questions (2021-2026): 
Thermal Properties of Matter 
 
(January 2026) 
 
Q1: Two wires A and B made of different materials of lengths 6.0 cm and 5.4 cm , 
respectively and area of cross sections 3.0 × 10
-5
 m
2
 and 4.5 × 10
-5
 m
2
 , respectively are 
stretched by the same magnitude under a given load. The ratio of the Young's modulus of 
A to that of B is x : 3. The value of x is 
(a) 2 
(b) 1 
(c) 4 
(d) 5 
Ans: (d) 
Sol:  
 
Young's Modulus is given by : 
 
Where: 
F is the applied force (load) 
L is the original length. 
A is the area of cross-section 
?L is the change in length (stretching) According to question, both wires are stretched by the 
same magnitude (?L
A
 = ?L
B
) under the same given load (F
A
 = F
B
).  
Therefore, for both wires: 
 
Let Y
A
 and Y
B
 be the Young's moduli for wires A and B: 
 
The given values : 
 
So, the value of x is 5 . Hence, the correct option is (d). 
 
 
Q2: A cubical block of density ?
b
 = 600 kg / m
3
 floats in a liquid of density ?
e
 = 900 kg / m
3
. 
If the height of block is H = 8.0 cm then height of the submerged part is ____ cm.  
(a) 6.3  
(b) 4.3  
(c) 7.3  
(d) 5.3  
Ans: (d) 
Sol:  
When an object floats in a liquid, the weight of the object is exactly balanced by the buoyant 
force (up thrust) exerted by the liquid. 
 
Weight of block is  
Buoyant force (F
B
) acting on a submerged body is equal to the weight of displaced liquid, 
 
For flotation : 
 
For a cubical block with a uniform cross-sectional area (A): 
Total Volume = V
total 
= AH 
Submerged Volume V
submerged
 = Ah  (where h is the submerged height) 
 
Putting the given values, 
 
Therefore, the height of the submerged part of the block is approximately 5.3 cm. 
Hence, the correct option is (d). 
 
Q3: A brass wire of length 2 m and radius 1 mm at 27
°
C is held taut between two rigid 
supports. Initially it was cooled to a temperature of - 43
°
C creating a tension T in the 
wire. The temperature to which the wire has to be cooled in order to increase the tension 
in it to 1.4 T, is _ _ _ _ °C.  
(a) -71  
(b) -80  
(c)  -65  
(d) -86  
Ans: (a) 
Sol:  
A metal rod of original length L that is free to move. If we heat this rod by a temperature 
difference ?T, it will naturally expand.  
The change in length (?L) is given by the law of linear thermal expansion: 
 
Where a = Coefficient of Linear Expansion  
When a wire fixed at both ends is cooled, it contracts. Since the supports are rigid, they prevent 
this contraction, creating a tension in the wire. 
 
According to Hooke's Law, Stress is proportional to Strain within the elastic limit. The constant of 
proportionality is Young's Modulus (Y). 
 
Page 5


JEE Main Previous Year Questions (2021-2026): 
Thermal Properties of Matter 
 
(January 2026) 
 
Q1: Two wires A and B made of different materials of lengths 6.0 cm and 5.4 cm , 
respectively and area of cross sections 3.0 × 10
-5
 m
2
 and 4.5 × 10
-5
 m
2
 , respectively are 
stretched by the same magnitude under a given load. The ratio of the Young's modulus of 
A to that of B is x : 3. The value of x is 
(a) 2 
(b) 1 
(c) 4 
(d) 5 
Ans: (d) 
Sol:  
 
Young's Modulus is given by : 
 
Where: 
F is the applied force (load) 
L is the original length. 
A is the area of cross-section 
?L is the change in length (stretching) According to question, both wires are stretched by the 
same magnitude (?L
A
 = ?L
B
) under the same given load (F
A
 = F
B
).  
Therefore, for both wires: 
 
Let Y
A
 and Y
B
 be the Young's moduli for wires A and B: 
 
The given values : 
 
So, the value of x is 5 . Hence, the correct option is (d). 
 
 
Q2: A cubical block of density ?
b
 = 600 kg / m
3
 floats in a liquid of density ?
e
 = 900 kg / m
3
. 
If the height of block is H = 8.0 cm then height of the submerged part is ____ cm.  
(a) 6.3  
(b) 4.3  
(c) 7.3  
(d) 5.3  
Ans: (d) 
Sol:  
When an object floats in a liquid, the weight of the object is exactly balanced by the buoyant 
force (up thrust) exerted by the liquid. 
 
Weight of block is  
Buoyant force (F
B
) acting on a submerged body is equal to the weight of displaced liquid, 
 
For flotation : 
 
For a cubical block with a uniform cross-sectional area (A): 
Total Volume = V
total 
= AH 
Submerged Volume V
submerged
 = Ah  (where h is the submerged height) 
 
Putting the given values, 
 
Therefore, the height of the submerged part of the block is approximately 5.3 cm. 
Hence, the correct option is (d). 
 
Q3: A brass wire of length 2 m and radius 1 mm at 27
°
C is held taut between two rigid 
supports. Initially it was cooled to a temperature of - 43
°
C creating a tension T in the 
wire. The temperature to which the wire has to be cooled in order to increase the tension 
in it to 1.4 T, is _ _ _ _ °C.  
(a) -71  
(b) -80  
(c)  -65  
(d) -86  
Ans: (a) 
Sol:  
A metal rod of original length L that is free to move. If we heat this rod by a temperature 
difference ?T, it will naturally expand.  
The change in length (?L) is given by the law of linear thermal expansion: 
 
Where a = Coefficient of Linear Expansion  
When a wire fixed at both ends is cooled, it contracts. Since the supports are rigid, they prevent 
this contraction, creating a tension in the wire. 
 
According to Hooke's Law, Stress is proportional to Strain within the elastic limit. The constant of 
proportionality is Young's Modulus (Y). 
 
Stress is defined as Force (F) per unit Area (A). 
 
Let the new final temperature be t
2
. 
Read More

FAQs on Thermal Properties of Matter: JEE Main Previous Year Questions (2021-2026)

1. What are the most important thermal properties of matter formulas I need to memorise for JEE Main?
Ans. Key formulas include linear thermal expansion (ΔL = α L₀ ΔT), volume expansion (ΔV = β V₀ ΔT), heat capacity (Q = mcΔT), specific heat capacity, latent heat, and thermal conductivity (H = kA(T₁-T₂)/d). Students should master coefficients of expansion, calorimetry equations, and Newton's law of cooling. Understanding relationships between these thermal expansion concepts strengthens problem-solving for JEE Main previous year questions.
2. Why do thermal properties questions in JEE Main focus on coefficient of linear and volume expansion?
Ans. Coefficient of linear expansion and volume expansion determine how materials respond to temperature changes-critical for real-world engineering applications. JEE Main emphasises this conceptual confusion because students often confuse linear thermal expansion with volumetric changes. The relationship β ≈ 3α for isotropic solids appears frequently in previous year questions. Mastering these thermal expansion relationships helps solve complex calorimetry and heat conduction problems efficiently.
3. How do I avoid making mistakes with latent heat calculations in thermal properties questions?
Ans. Latent heat remains constant during phase transitions; temperature doesn't change during melting or boiling. Common mistakes include adding temperature change to latent heat calculations or forgetting that latent heat (L) must multiply mass directly: Q = mL. Previous year JEE Main questions test whether students distinguish between sensible heat (temperature-dependent) and latent heat (temperature-independent). Always check whether heat involves phase change or temperature change first.
4. What's the difference between thermal conductivity and thermal resistance in heat conduction problems?
Ans. Thermal conductivity (k) measures how quickly heat flows through material; higher k means better conduction. Thermal resistance (R = d/kA) opposes heat flow; materials with low conductivity have high resistance. In JEE Main problems, thermal resistance behaves like electrical resistance in series and parallel arrangements. Understanding this analogy helps solve composite wall heat transfer questions from previous year papers systematically.
5. Which thermal properties concepts appear most frequently in recent JEE Main exams (2021-2026)?
Ans. Recent JEE Main previous year questions emphasise Newton's law of cooling, thermal equilibrium in calorimetry, and composite thermal resistance calculations. Heat capacity relationships, specific heat capacity comparisons, and practical scenarios involving thermal expansion in bridges or railway tracks appear consistently. Students should practice questions involving mixed concepts-combining thermal expansion with stress calculations or cooling curves with latent heat. Refer to mind maps and MCQ tests on EduRev for targeted practice on high-frequency topics.
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