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Electrostatic Potential and Capacitance: JEE Main Previous Year Questions (2021-2026)

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JEE Main Previous Year Questions (2021-2026): 
Electrostatic Potential and Capacitance 
 
(January 2026) 
 
Q1: Identify the correct statements: 
A. Effective capacitance of a series combination of capacitors is always smaller than the 
smallest capacitance of the capacitor in the combination. 
B. When a dielectric medium is placed between the charged plates of a capacitor, 
displacement of charges cannot occur due to insulation property of dielectric. 
C. Increasing of area of capacitor plate or decreasing of thickness of dielectric is an 
alternate method to increase the capacitance. 
D. For a point charge, concentric spherical shells centered at the location of the charge 
are equipotential surfaces. 
Choose the correct answer from the options given below : 
(a) A, C and D Only 
(b) A, B and C Only 
(c) B and D Only 
(d) C and D Only 
Ans: (a) 
Sol: 
In a series combination, the effective capacitance (C
eff
) is given by: 
 
Mathematically, the sum of reciprocals always results in a total value that is less than any 
individual component. Hence, statement (A) is correct.  
While dielectrics are insulators and do not allow the flow of current (conduction), they absolutely 
allow the displacement of charges. Under an external electric field, the molecules in a dielectric 
polarize, i.e., their positive and negative charges shift slightly in opposite directions. This is 
known as dielectric polarization. 
Page 2


JEE Main Previous Year Questions (2021-2026): 
Electrostatic Potential and Capacitance 
 
(January 2026) 
 
Q1: Identify the correct statements: 
A. Effective capacitance of a series combination of capacitors is always smaller than the 
smallest capacitance of the capacitor in the combination. 
B. When a dielectric medium is placed between the charged plates of a capacitor, 
displacement of charges cannot occur due to insulation property of dielectric. 
C. Increasing of area of capacitor plate or decreasing of thickness of dielectric is an 
alternate method to increase the capacitance. 
D. For a point charge, concentric spherical shells centered at the location of the charge 
are equipotential surfaces. 
Choose the correct answer from the options given below : 
(a) A, C and D Only 
(b) A, B and C Only 
(c) B and D Only 
(d) C and D Only 
Ans: (a) 
Sol: 
In a series combination, the effective capacitance (C
eff
) is given by: 
 
Mathematically, the sum of reciprocals always results in a total value that is less than any 
individual component. Hence, statement (A) is correct.  
While dielectrics are insulators and do not allow the flow of current (conduction), they absolutely 
allow the displacement of charges. Under an external electric field, the molecules in a dielectric 
polarize, i.e., their positive and negative charges shift slightly in opposite directions. This is 
known as dielectric polarization. 
 
Hence, the statement (B) is incorrect. 
The capacitance (C) of a parallel plate capacitor is given by: 
 
Where A is the area and d is the distance (thickness of dielectric). 
If A increases, C increases  
If d decreases, C increases 
Hence, the statement (C) is correct.  
The potential (V) due to a point charge is V = kq/r . 
This means the potential depends only on the distance (r) from the charge.  
For a fixed r , the potential is constant. All points at a constant distance r from a center form a 
spherical shell. Therefore, these concentric shells are equipotential surfaces.  
Hence, the statement (D) is correct.  
Statements A, C, and D are true, while statement B is false. Hence, the correct option is (A). 
 
 
Q2: Three parallel plate capacitors each with area A and separation d are filled with two 
dielectric (k
1
 and k
2
) in the following fashion. Which of the following is true? (k
1
 > k
2
) 
Page 3


JEE Main Previous Year Questions (2021-2026): 
Electrostatic Potential and Capacitance 
 
(January 2026) 
 
Q1: Identify the correct statements: 
A. Effective capacitance of a series combination of capacitors is always smaller than the 
smallest capacitance of the capacitor in the combination. 
B. When a dielectric medium is placed between the charged plates of a capacitor, 
displacement of charges cannot occur due to insulation property of dielectric. 
C. Increasing of area of capacitor plate or decreasing of thickness of dielectric is an 
alternate method to increase the capacitance. 
D. For a point charge, concentric spherical shells centered at the location of the charge 
are equipotential surfaces. 
Choose the correct answer from the options given below : 
(a) A, C and D Only 
(b) A, B and C Only 
(c) B and D Only 
(d) C and D Only 
Ans: (a) 
Sol: 
In a series combination, the effective capacitance (C
eff
) is given by: 
 
Mathematically, the sum of reciprocals always results in a total value that is less than any 
individual component. Hence, statement (A) is correct.  
While dielectrics are insulators and do not allow the flow of current (conduction), they absolutely 
allow the displacement of charges. Under an external electric field, the molecules in a dielectric 
polarize, i.e., their positive and negative charges shift slightly in opposite directions. This is 
known as dielectric polarization. 
 
Hence, the statement (B) is incorrect. 
The capacitance (C) of a parallel plate capacitor is given by: 
 
Where A is the area and d is the distance (thickness of dielectric). 
If A increases, C increases  
If d decreases, C increases 
Hence, the statement (C) is correct.  
The potential (V) due to a point charge is V = kq/r . 
This means the potential depends only on the distance (r) from the charge.  
For a fixed r , the potential is constant. All points at a constant distance r from a center form a 
spherical shell. Therefore, these concentric shells are equipotential surfaces.  
Hence, the statement (D) is correct.  
Statements A, C, and D are true, while statement B is false. Hence, the correct option is (A). 
 
 
Q2: Three parallel plate capacitors each with area A and separation d are filled with two 
dielectric (k
1
 and k
2
) in the following fashion. Which of the following is true? (k
1
 > k
2
) 
 
 
(a) C
C
 > C
B
 > C
A 
(b) C
B
 > C
C
 > C
A 
(c) C
A
 > C
C
 > C
B 
(d) C
C
 > C
A
 > C
B 
Ans: (c) 
Sol: 
The capacitance of a parallel plate capacitor is , where k is the dielectric 
constant of the material, A is the area of the plate and d is the separation between the plates.  
When capacitors are in parallel then the equivalent capacitance is given as  
 
When capacitors are in series then the equivalent capacitance is given as 
 
For Capacitor (A) 
Page 4


JEE Main Previous Year Questions (2021-2026): 
Electrostatic Potential and Capacitance 
 
(January 2026) 
 
Q1: Identify the correct statements: 
A. Effective capacitance of a series combination of capacitors is always smaller than the 
smallest capacitance of the capacitor in the combination. 
B. When a dielectric medium is placed between the charged plates of a capacitor, 
displacement of charges cannot occur due to insulation property of dielectric. 
C. Increasing of area of capacitor plate or decreasing of thickness of dielectric is an 
alternate method to increase the capacitance. 
D. For a point charge, concentric spherical shells centered at the location of the charge 
are equipotential surfaces. 
Choose the correct answer from the options given below : 
(a) A, C and D Only 
(b) A, B and C Only 
(c) B and D Only 
(d) C and D Only 
Ans: (a) 
Sol: 
In a series combination, the effective capacitance (C
eff
) is given by: 
 
Mathematically, the sum of reciprocals always results in a total value that is less than any 
individual component. Hence, statement (A) is correct.  
While dielectrics are insulators and do not allow the flow of current (conduction), they absolutely 
allow the displacement of charges. Under an external electric field, the molecules in a dielectric 
polarize, i.e., their positive and negative charges shift slightly in opposite directions. This is 
known as dielectric polarization. 
 
Hence, the statement (B) is incorrect. 
The capacitance (C) of a parallel plate capacitor is given by: 
 
Where A is the area and d is the distance (thickness of dielectric). 
If A increases, C increases  
If d decreases, C increases 
Hence, the statement (C) is correct.  
The potential (V) due to a point charge is V = kq/r . 
This means the potential depends only on the distance (r) from the charge.  
For a fixed r , the potential is constant. All points at a constant distance r from a center form a 
spherical shell. Therefore, these concentric shells are equipotential surfaces.  
Hence, the statement (D) is correct.  
Statements A, C, and D are true, while statement B is false. Hence, the correct option is (A). 
 
 
Q2: Three parallel plate capacitors each with area A and separation d are filled with two 
dielectric (k
1
 and k
2
) in the following fashion. Which of the following is true? (k
1
 > k
2
) 
 
 
(a) C
C
 > C
B
 > C
A 
(b) C
B
 > C
C
 > C
A 
(c) C
A
 > C
C
 > C
B 
(d) C
C
 > C
A
 > C
B 
Ans: (c) 
Sol: 
The capacitance of a parallel plate capacitor is , where k is the dielectric 
constant of the material, A is the area of the plate and d is the separation between the plates.  
When capacitors are in parallel then the equivalent capacitance is given as  
 
When capacitors are in series then the equivalent capacitance is given as 
 
For Capacitor (A) 
 
The capacitance,  
The capacitance,  
The capacitance,  
C
A2
 and C
A3
 are in parallel, 
 
Now, C
A1
 and C
A(2,3)
 are in series, so the equivalent capacitance of capacitor A is 
 
Page 5


JEE Main Previous Year Questions (2021-2026): 
Electrostatic Potential and Capacitance 
 
(January 2026) 
 
Q1: Identify the correct statements: 
A. Effective capacitance of a series combination of capacitors is always smaller than the 
smallest capacitance of the capacitor in the combination. 
B. When a dielectric medium is placed between the charged plates of a capacitor, 
displacement of charges cannot occur due to insulation property of dielectric. 
C. Increasing of area of capacitor plate or decreasing of thickness of dielectric is an 
alternate method to increase the capacitance. 
D. For a point charge, concentric spherical shells centered at the location of the charge 
are equipotential surfaces. 
Choose the correct answer from the options given below : 
(a) A, C and D Only 
(b) A, B and C Only 
(c) B and D Only 
(d) C and D Only 
Ans: (a) 
Sol: 
In a series combination, the effective capacitance (C
eff
) is given by: 
 
Mathematically, the sum of reciprocals always results in a total value that is less than any 
individual component. Hence, statement (A) is correct.  
While dielectrics are insulators and do not allow the flow of current (conduction), they absolutely 
allow the displacement of charges. Under an external electric field, the molecules in a dielectric 
polarize, i.e., their positive and negative charges shift slightly in opposite directions. This is 
known as dielectric polarization. 
 
Hence, the statement (B) is incorrect. 
The capacitance (C) of a parallel plate capacitor is given by: 
 
Where A is the area and d is the distance (thickness of dielectric). 
If A increases, C increases  
If d decreases, C increases 
Hence, the statement (C) is correct.  
The potential (V) due to a point charge is V = kq/r . 
This means the potential depends only on the distance (r) from the charge.  
For a fixed r , the potential is constant. All points at a constant distance r from a center form a 
spherical shell. Therefore, these concentric shells are equipotential surfaces.  
Hence, the statement (D) is correct.  
Statements A, C, and D are true, while statement B is false. Hence, the correct option is (A). 
 
 
Q2: Three parallel plate capacitors each with area A and separation d are filled with two 
dielectric (k
1
 and k
2
) in the following fashion. Which of the following is true? (k
1
 > k
2
) 
 
 
(a) C
C
 > C
B
 > C
A 
(b) C
B
 > C
C
 > C
A 
(c) C
A
 > C
C
 > C
B 
(d) C
C
 > C
A
 > C
B 
Ans: (c) 
Sol: 
The capacitance of a parallel plate capacitor is , where k is the dielectric 
constant of the material, A is the area of the plate and d is the separation between the plates.  
When capacitors are in parallel then the equivalent capacitance is given as  
 
When capacitors are in series then the equivalent capacitance is given as 
 
For Capacitor (A) 
 
The capacitance,  
The capacitance,  
The capacitance,  
C
A2
 and C
A3
 are in parallel, 
 
Now, C
A1
 and C
A(2,3)
 are in series, so the equivalent capacitance of capacitor A is 
 
For Capacitor (B) 
 
 
Now, C
B1
 and C
B(2,3)
 are in series, so the equivalent capacitance of capacitor B is  
Read More

FAQs on Electrostatic Potential and Capacitance: JEE Main Previous Year Questions (2021-2026)

1. What's the difference between electric potential and electric potential energy?
Ans. Electric potential is the work done per unit positive charge to bring a test charge from infinity to a point, measured in volts. Electric potential energy is the total work stored when a charge is placed in an electric field. Potential is field-dependent; potential energy depends on both field strength and the charge magnitude itself.
2. How do I solve capacitance problems when capacitors are connected in series and parallel?
Ans. For series capacitors, reciprocals add: 1/C_total = 1/C₁ + 1/C₂. For parallel capacitors, capacitances add directly: C_total = C₁ + C₂. Series reduces overall capacitance and divides voltage; parallel increases capacitance and maintains equal voltage across all capacitors. Practice with mixed configurations using EduRev's MCQ tests and visual worksheets for quick mastery.
3. Why does the electric field inside a conductor always equal zero?
Ans. Charges in a conductor redistribute until internal electric field vanishes; otherwise, charges would continue moving. This electrostatic equilibrium state ensures zero potential difference inside the conductor. All excess charge accumulates on the outer surface, creating a zero-field interior-a fundamental principle tested frequently in JEE Main.
4. What's the relationship between electric field and potential gradient, and when does it matter for JEE?
Ans. Electric field equals the negative potential gradient: E = -dV/dr. This relationship reveals how rapidly potential changes across distance. Understanding gradient helps solve problems involving non-uniform fields and potential variations in complex geometries. This concept frequently appears in JEE Main numerical-answer questions requiring precise calculation methods.
5. How do dielectric materials affect capacitance, and what's the dielectric constant formula?
Ans. Dielectric materials increase capacitance by factor κ (dielectric constant): C = κC₀, where C₀ is capacitance without dielectric. The material polarizes, reducing internal electric field strength. Dielectrics are inserted between capacitor plates to store more charge at same voltage-a crucial mechanism in JEE problems involving energy storage and field modification.
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