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General Organic Chemistry: JEE Main Previous Year Questions (2021-2026)
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Page 1 JEE Main Previous Year Questions (2021-2026): General Organic Chemistry (January 2026) Q1: Identify the correct statements: The presence of –NO 2 group in benzene ring A. activates the ring towards electrophilic substitutions. B. deactivates the ring towards electrophilic substitutions. C. activates the ring towards nucleophilic substitutions. D. deactivates the ring towards nucleophilic substitutions. Choose the correct answer from the options given below: A: A and D Only B: B and D Only C: C and A Only D: B and C Only Answer: D Explanation: Presence of NO 2 group on the benzene ring deactivates the ring towards electrophilic substitution reactions because it shows -M effect (it withdraws electrons from the ring by resonance). Because the NO 2 group pulls electron density away, the ring becomes less reactive towards electrophiles. At the same time, the NO 2 group activates the ring towards nucleophilic substitution because the withdrawal of electrons makes the ring more suitable for attack by nucleophiles (electron-rich species). Ans. ? B & C Q2: The cyclic cations having the same number of hyperconjugation are : Page 2 JEE Main Previous Year Questions (2021-2026): General Organic Chemistry (January 2026) Q1: Identify the correct statements: The presence of –NO 2 group in benzene ring A. activates the ring towards electrophilic substitutions. B. deactivates the ring towards electrophilic substitutions. C. activates the ring towards nucleophilic substitutions. D. deactivates the ring towards nucleophilic substitutions. Choose the correct answer from the options given below: A: A and D Only B: B and D Only C: C and A Only D: B and C Only Answer: D Explanation: Presence of NO 2 group on the benzene ring deactivates the ring towards electrophilic substitution reactions because it shows -M effect (it withdraws electrons from the ring by resonance). Because the NO 2 group pulls electron density away, the ring becomes less reactive towards electrophiles. At the same time, the NO 2 group activates the ring towards nucleophilic substitution because the withdrawal of electrons makes the ring more suitable for attack by nucleophiles (electron-rich species). Ans. ? B & C Q2: The cyclic cations having the same number of hyperconjugation are : Choose the correct answer from the options given below: A: B and C Only B: A and B Only C: A and C Only D: A, C and D only Answer: C Explanation: A & C Page 3 JEE Main Previous Year Questions (2021-2026): General Organic Chemistry (January 2026) Q1: Identify the correct statements: The presence of –NO 2 group in benzene ring A. activates the ring towards electrophilic substitutions. B. deactivates the ring towards electrophilic substitutions. C. activates the ring towards nucleophilic substitutions. D. deactivates the ring towards nucleophilic substitutions. Choose the correct answer from the options given below: A: A and D Only B: B and D Only C: C and A Only D: B and C Only Answer: D Explanation: Presence of NO 2 group on the benzene ring deactivates the ring towards electrophilic substitution reactions because it shows -M effect (it withdraws electrons from the ring by resonance). Because the NO 2 group pulls electron density away, the ring becomes less reactive towards electrophiles. At the same time, the NO 2 group activates the ring towards nucleophilic substitution because the withdrawal of electrons makes the ring more suitable for attack by nucleophiles (electron-rich species). Ans. ? B & C Q2: The cyclic cations having the same number of hyperconjugation are : Choose the correct answer from the options given below: A: B and C Only B: A and B Only C: A and C Only D: A, C and D only Answer: C Explanation: A & C Q3: The CORRECT order of stability for the following is: CH 2 = CH ?, CH 3 – CH 2 ?, CH = C ? A: CH = C ? > CH 3 – CH 2 ? > CH 2 = CH ? B: CH 2 = CH ? > CH = C ? > CH 3 – CH 2 ? C: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? D: CH 3 – CH 2 ? > CH 2 = CH ? > CH = C ? Answer: C Explanation: Stability of carbanions depends mainly on how well the carbon can hold the negative charge. Step 1: Use NCERT idea – effect of hybridisation (electronegativity) Greater s-character ? carbon is more electronegative ? negative charge is more stable. sp carbon: 50% s-character (most electronegative) sp² carbon: 33% s-character sp³ carbon: 25% s-character (least electronegative) So stability order due to hybridisation is: sp > sp² > sp³ Step 2: Apply to given carbanions CH = C ? is on an sp carbon ? most stable CH 2 = CH ? is on an sp² carbon ? next CH 3 – CH 2 ? is on an sp³ carbon and also has +I effect of CH 3 which destabilises the negative charge ? least stable Correct order: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? Correct option: C Q4: Given below are two statements: Statement I : There are several conformers for n -butane. Out of those conformers, Statement II : As the dihedral angle increases, torsional strain decreases from (X) to (Y). In the light of the above statements, choose the correct answer from the options given below A: Statement I is false but Statement II is true B: Both Statement I and Statement II are false C: Statement I is true but Statement II is false Page 4 JEE Main Previous Year Questions (2021-2026): General Organic Chemistry (January 2026) Q1: Identify the correct statements: The presence of –NO 2 group in benzene ring A. activates the ring towards electrophilic substitutions. B. deactivates the ring towards electrophilic substitutions. C. activates the ring towards nucleophilic substitutions. D. deactivates the ring towards nucleophilic substitutions. Choose the correct answer from the options given below: A: A and D Only B: B and D Only C: C and A Only D: B and C Only Answer: D Explanation: Presence of NO 2 group on the benzene ring deactivates the ring towards electrophilic substitution reactions because it shows -M effect (it withdraws electrons from the ring by resonance). Because the NO 2 group pulls electron density away, the ring becomes less reactive towards electrophiles. At the same time, the NO 2 group activates the ring towards nucleophilic substitution because the withdrawal of electrons makes the ring more suitable for attack by nucleophiles (electron-rich species). Ans. ? B & C Q2: The cyclic cations having the same number of hyperconjugation are : Choose the correct answer from the options given below: A: B and C Only B: A and B Only C: A and C Only D: A, C and D only Answer: C Explanation: A & C Q3: The CORRECT order of stability for the following is: CH 2 = CH ?, CH 3 – CH 2 ?, CH = C ? A: CH = C ? > CH 3 – CH 2 ? > CH 2 = CH ? B: CH 2 = CH ? > CH = C ? > CH 3 – CH 2 ? C: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? D: CH 3 – CH 2 ? > CH 2 = CH ? > CH = C ? Answer: C Explanation: Stability of carbanions depends mainly on how well the carbon can hold the negative charge. Step 1: Use NCERT idea – effect of hybridisation (electronegativity) Greater s-character ? carbon is more electronegative ? negative charge is more stable. sp carbon: 50% s-character (most electronegative) sp² carbon: 33% s-character sp³ carbon: 25% s-character (least electronegative) So stability order due to hybridisation is: sp > sp² > sp³ Step 2: Apply to given carbanions CH = C ? is on an sp carbon ? most stable CH 2 = CH ? is on an sp² carbon ? next CH 3 – CH 2 ? is on an sp³ carbon and also has +I effect of CH 3 which destabilises the negative charge ? least stable Correct order: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? Correct option: C Q4: Given below are two statements: Statement I : There are several conformers for n -butane. Out of those conformers, Statement II : As the dihedral angle increases, torsional strain decreases from (X) to (Y). In the light of the above statements, choose the correct answer from the options given below A: Statement I is false but Statement II is true B: Both Statement I and Statement II are false C: Statement I is true but Statement II is false D: Both Statement I and Statement II are true Answer: D Explanation: Both Statements are correct. Q5: Find out the statements which are not true. A. Resonating structures with more number of covalent bonds and lesser charge separation are more stable. B. In electromeric effect, an unsaturated system shows +E effect with nucleophile and -E effect with electrophile. C. Inductive effect is responsible for high melting point, boiling point and dipole moment of polar compounds. D. The greater the number of alkyl groups attached to the doubly bonded carbon atoms, higher is the heat of hydrogenation. E. Stability of carbanion increases with the increase in s- character of the carbon carrying the negative charge. Choose the correct answer from the options given below: A: A, D & E only B: A, C & D only C: B & D only D: B, D & E only Answer: C Explanation: Statement B & D are not true Q6: Arrange the following carbanions in the decreasing order of stability. Page 5 JEE Main Previous Year Questions (2021-2026): General Organic Chemistry (January 2026) Q1: Identify the correct statements: The presence of –NO 2 group in benzene ring A. activates the ring towards electrophilic substitutions. B. deactivates the ring towards electrophilic substitutions. C. activates the ring towards nucleophilic substitutions. D. deactivates the ring towards nucleophilic substitutions. Choose the correct answer from the options given below: A: A and D Only B: B and D Only C: C and A Only D: B and C Only Answer: D Explanation: Presence of NO 2 group on the benzene ring deactivates the ring towards electrophilic substitution reactions because it shows -M effect (it withdraws electrons from the ring by resonance). Because the NO 2 group pulls electron density away, the ring becomes less reactive towards electrophiles. At the same time, the NO 2 group activates the ring towards nucleophilic substitution because the withdrawal of electrons makes the ring more suitable for attack by nucleophiles (electron-rich species). Ans. ? B & C Q2: The cyclic cations having the same number of hyperconjugation are : Choose the correct answer from the options given below: A: B and C Only B: A and B Only C: A and C Only D: A, C and D only Answer: C Explanation: A & C Q3: The CORRECT order of stability for the following is: CH 2 = CH ?, CH 3 – CH 2 ?, CH = C ? A: CH = C ? > CH 3 – CH 2 ? > CH 2 = CH ? B: CH 2 = CH ? > CH = C ? > CH 3 – CH 2 ? C: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? D: CH 3 – CH 2 ? > CH 2 = CH ? > CH = C ? Answer: C Explanation: Stability of carbanions depends mainly on how well the carbon can hold the negative charge. Step 1: Use NCERT idea – effect of hybridisation (electronegativity) Greater s-character ? carbon is more electronegative ? negative charge is more stable. sp carbon: 50% s-character (most electronegative) sp² carbon: 33% s-character sp³ carbon: 25% s-character (least electronegative) So stability order due to hybridisation is: sp > sp² > sp³ Step 2: Apply to given carbanions CH = C ? is on an sp carbon ? most stable CH 2 = CH ? is on an sp² carbon ? next CH 3 – CH 2 ? is on an sp³ carbon and also has +I effect of CH 3 which destabilises the negative charge ? least stable Correct order: CH = C ? > CH 2 = CH ? > CH 3 – CH 2 ? Correct option: C Q4: Given below are two statements: Statement I : There are several conformers for n -butane. Out of those conformers, Statement II : As the dihedral angle increases, torsional strain decreases from (X) to (Y). In the light of the above statements, choose the correct answer from the options given below A: Statement I is false but Statement II is true B: Both Statement I and Statement II are false C: Statement I is true but Statement II is false D: Both Statement I and Statement II are true Answer: D Explanation: Both Statements are correct. Q5: Find out the statements which are not true. A. Resonating structures with more number of covalent bonds and lesser charge separation are more stable. B. In electromeric effect, an unsaturated system shows +E effect with nucleophile and -E effect with electrophile. C. Inductive effect is responsible for high melting point, boiling point and dipole moment of polar compounds. D. The greater the number of alkyl groups attached to the doubly bonded carbon atoms, higher is the heat of hydrogenation. E. Stability of carbanion increases with the increase in s- character of the carbon carrying the negative charge. Choose the correct answer from the options given below: A: A, D & E only B: A, C & D only C: B & D only D: B, D & E only Answer: C Explanation: Statement B & D are not true Q6: Arrange the following carbanions in the decreasing order of stability. Choose the correct answer from the options given below: A: I > II > IV > V > III B: IV > II > I > III > V C: I > IV > II > V > III D: IV > I > II > V > III Answer: D Explanation: Carbanion means a carbon atom carrying a negative charge. Such a species is stable when this negative charge is reduced (spread out) or pulled away. If a group attached to the carbanion is electron withdrawing (shows -I effect), it pulls electron density towards itself. This reduces the negative charge on carbon, so the carbanion becomes more stable. If a group attached to the carbanion is electron donating (shows +I effect), it pushes electron density towards the carbon. This increases the negative charge on carbon, so the carbanion becomes less stable. So, while arranging in decreasing order of stability: carbanions with stronger electron withdrawing groups will be more stable, and those with electron donating groups will be less stable. Q7: Given below are two statements: In the light of the above statements, choose the correct answer from the options given below: A: Statement I is false but Statement II is true B: Statement I is true but Statement II is false C: Both Statement I and Statement II are true D: Both Statement I and Statement II are false Answer: B Explanation: For hyperconjugation to occur, we need at least one hydrogen atom on the carbon atom next to the positively charged carbon. This special hydrogen is called an alpha-hydrogen (a-hydrogen). The rule is simple: More the number of alpha-hydrogens, the more the hyperconjugation structures, and the greater the stability of the carbocation. Now, let's analyze the two statements. Analysis of Statement I: Let's look at the tert-butyl carbocation: Its structure is:Read More
FAQs on General Organic Chemistry: JEE Main Previous Year Questions (2021-2026)
| 1. What are the most important concepts tested in JEE Main General Organic Chemistry questions from recent years? |  |
Ans. Recent JEE Main papers emphasise reaction mechanisms, nucleophilic substitution (SN1 and SN2), elimination reactions, and functional group transformations. Stereochemistry, acid-base strength predictions, and resonance effects frequently appear. Students should focus on understanding electron movement, carbocation stability, and how molecular structure determines reactivity patterns. Previous year questions reveal that conceptual clarity matters more than memorisation.
| 2. How do I identify whether a reaction follows SN1 or SN2 mechanism in JEE previous year questions? | |
Ans. SN1 mechanisms occur with tertiary substrates, polar aprotic solvents, and form stable carbocations; SN2 requires primary substrates, polar protic solvents, and proceeds via backside attack. Examine substrate structure, leaving group ability, and solvent type in JEE questions. Tertiary alkyl halides almost always indicate SN1, while primary systems suggest SN2. Practice distinguishing these patterns through previous year problem-solving.
| 3. Why do some organic compounds show different reactivity even with similar functional groups in JEE exams? | |
Ans. Reactivity depends on electronic effects (inductive and resonance), steric hindrance, and substrate structure-not just functional groups alone. Electron-withdrawing groups deactivate nucleophiles; electron-donating groups activate them. Adjacent atoms and bond polarisation significantly influence reactivity. JEE questions test whether students recognise that identical-looking compounds behave differently based on surrounding molecular environment and substitution patterns.
| 4. What's the difference between elimination and substitution reactions that JEE questions always ask about? | |
Ans. Substitution replaces a leaving group with a nucleophile (SN1/SN2); elimination removes a leaving group and adjacent hydrogen, forming a double bond (E1/E2). Strong bases and heat favour elimination; weak bases and polar solvents favour substitution. JEE previous year papers frequently combine both pathways in single scenarios, requiring students to predict which dominates based on conditions and substrate structure.
| 5. How should I approach solving isomerism and stereochemistry problems from recent JEE Main question papers? | |
Ans. Identify all possible carbon skeletons (structural isomers), then determine stereogenic centres and their configurations using R/S naming conventions. Check for geometrical isomerism in alkenes and ring systems. Previous year JEE questions test whether candidates recognise optical activity, distinguish enantiomers from diastereomers, and predict reactivity differences. Use flashcards and mind maps to visualise 3D structures effectively during revision.
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