Page 1
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Exercise 6.5 Page No: 231
1. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
Solution:
(i) Given function is:
As, for all x ? R
Adding 3 both sides, we get
The minimum value of f(x) is 3 when 2x – 1 = 0, which means
This function does not have a maximum value.
(ii) Given function is:
Using squaring method for a quadratic equation:
=
Page 2
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Exercise 6.5 Page No: 231
1. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
Solution:
(i) Given function is:
As, for all x ? R
Adding 3 both sides, we get
The minimum value of f(x) is 3 when 2x – 1 = 0, which means
This function does not have a maximum value.
(ii) Given function is:
Using squaring method for a quadratic equation:
=
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
……….(i)
As for all x ? R
Subtracting 2 from both sides,
Therefore, minimum value of f(x) is -2 and is obtained when
, that is,
And this function does not have a maximum value.
(iii) Given function is: ……….(i)
As for all R
Multiplying both sides by and adding 10 both sides,
[Using equation (1)]
Maximum value of f(x) is 10 which is obtained when
x -1 = 0 which implies x = 1.
And minimum value of f(x) does not exist.
(iv) Given function is:
At
At
Page 3
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Exercise 6.5 Page No: 231
1. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
Solution:
(i) Given function is:
As, for all x ? R
Adding 3 both sides, we get
The minimum value of f(x) is 3 when 2x – 1 = 0, which means
This function does not have a maximum value.
(ii) Given function is:
Using squaring method for a quadratic equation:
=
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
……….(i)
As for all x ? R
Subtracting 2 from both sides,
Therefore, minimum value of f(x) is -2 and is obtained when
, that is,
And this function does not have a maximum value.
(iii) Given function is: ……….(i)
As for all R
Multiplying both sides by and adding 10 both sides,
[Using equation (1)]
Maximum value of f(x) is 10 which is obtained when
x -1 = 0 which implies x = 1.
And minimum value of f(x) does not exist.
(iv) Given function is:
At
At
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Hence, maximum value and minimum value of g(x) do not exist.
2. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
(v)
Solution: (i) Given function is: ……….(1)
As for all R
Subtracting 1 from both sides,
Therefore, minimum value of f(x) is -1 which is obtained when x + 2 = 0 or x = -2.
From equation (1), maximum value of hence it does not exist.
(ii) Given function is:
As for all R
Multiplying by both sides and adding 3 both sides,
Maximum value of g(x) is 3 which is obtained when x + 1 = 0 or x = -1.
From equation (1), minimum value of , does not exist.
Page 4
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Exercise 6.5 Page No: 231
1. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
Solution:
(i) Given function is:
As, for all x ? R
Adding 3 both sides, we get
The minimum value of f(x) is 3 when 2x – 1 = 0, which means
This function does not have a maximum value.
(ii) Given function is:
Using squaring method for a quadratic equation:
=
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
……….(i)
As for all x ? R
Subtracting 2 from both sides,
Therefore, minimum value of f(x) is -2 and is obtained when
, that is,
And this function does not have a maximum value.
(iii) Given function is: ……….(i)
As for all R
Multiplying both sides by and adding 10 both sides,
[Using equation (1)]
Maximum value of f(x) is 10 which is obtained when
x -1 = 0 which implies x = 1.
And minimum value of f(x) does not exist.
(iv) Given function is:
At
At
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Hence, maximum value and minimum value of g(x) do not exist.
2. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
(v)
Solution: (i) Given function is: ……….(1)
As for all R
Subtracting 1 from both sides,
Therefore, minimum value of f(x) is -1 which is obtained when x + 2 = 0 or x = -2.
From equation (1), maximum value of hence it does not exist.
(ii) Given function is:
As for all R
Multiplying by both sides and adding 3 both sides,
Maximum value of g(x) is 3 which is obtained when x + 1 = 0 or x = -1.
From equation (1), minimum value of , does not exist.
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
(iii) Given function is: ……….(i)
As for all R
Adding 5 to all sides,
Therefore, minimum value of is 4 and maximum value is 6.
(iv) Given function is:
As for all R
Adding 3 to all sides,
Therefore, minimum value of f(x) is 2 and maximum value is 4.
(v) Given function is: ……….(i)
As
Adding 1 to both sides,
Therefore, neither minimum value not maximum value of h(x) exists.
3. Find the local maxima and local minima, if any, of the following functions. Find also the
local maximum and the local minimum values, as the case may be:
(i)
(ii)
(iii)
(iv)
Page 5
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Exercise 6.5 Page No: 231
1. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
Solution:
(i) Given function is:
As, for all x ? R
Adding 3 both sides, we get
The minimum value of f(x) is 3 when 2x – 1 = 0, which means
This function does not have a maximum value.
(ii) Given function is:
Using squaring method for a quadratic equation:
=
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
……….(i)
As for all x ? R
Subtracting 2 from both sides,
Therefore, minimum value of f(x) is -2 and is obtained when
, that is,
And this function does not have a maximum value.
(iii) Given function is: ……….(i)
As for all R
Multiplying both sides by and adding 10 both sides,
[Using equation (1)]
Maximum value of f(x) is 10 which is obtained when
x -1 = 0 which implies x = 1.
And minimum value of f(x) does not exist.
(iv) Given function is:
At
At
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
Hence, maximum value and minimum value of g(x) do not exist.
2. Find the maximum and minimum values, if any, of the following functions given by:
(i)
(ii)
(iii)
(iv)
(v)
Solution: (i) Given function is: ……….(1)
As for all R
Subtracting 1 from both sides,
Therefore, minimum value of f(x) is -1 which is obtained when x + 2 = 0 or x = -2.
From equation (1), maximum value of hence it does not exist.
(ii) Given function is:
As for all R
Multiplying by both sides and adding 3 both sides,
Maximum value of g(x) is 3 which is obtained when x + 1 = 0 or x = -1.
From equation (1), minimum value of , does not exist.
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
(iii) Given function is: ……….(i)
As for all R
Adding 5 to all sides,
Therefore, minimum value of is 4 and maximum value is 6.
(iv) Given function is:
As for all R
Adding 3 to all sides,
Therefore, minimum value of f(x) is 2 and maximum value is 4.
(v) Given function is: ……….(i)
As
Adding 1 to both sides,
Therefore, neither minimum value not maximum value of h(x) exists.
3. Find the local maxima and local minima, if any, of the following functions. Find also the
local maximum and the local minimum values, as the case may be:
(i)
(ii)
(iii)
(iv)
NCERT Solutions for Class 12 Maths Chapter 6 Application of
Derivatives
(v)
(vi)
(vii)
(viii)
Solution: (i) Given function is:
and
Now
[Turning point]
Again, when x = 0, [Positive]
Therefore, x=0, is a point of local minima and local minimum value =
(ii) Given function is:
and
Now
or [Turning points]
Again, when ,
[Negative]
is a point of local maxima and local maximum value
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