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Page 1 RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 1. Solution: In parallelogram ABCD, Base AB = 32cm Height DL = 16.5cm. Area = Base x height = 32 x 16.5 cm² = 528 cm² Question 2. . Solution: Base of parallelogram = 1 m 60m = 160 cm and height = 75 cm Area = Base x height = 160 x 75 = 12000 cm² = 12001/ 10000 m² = 1.2m² Page 2 RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 1. Solution: In parallelogram ABCD, Base AB = 32cm Height DL = 16.5cm. Area = Base x height = 32 x 16.5 cm² = 528 cm² Question 2. . Solution: Base of parallelogram = 1 m 60m = 160 cm and height = 75 cm Area = Base x height = 160 x 75 = 12000 cm² = 12001/ 10000 m² = 1.2m² RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Base of parallelogram = 14dm = 140cm and height = 6.5 dm = 65cm Area (in cm²) = Base x height = 140 x 65 = 9100 cm² Area (in m²) = 140/100x 65/100 = 9100/10000 = 0.91 m² Question 4. Solution: Area of parallelogram = 54 cm² Base = 15 cm Question 5. Solution: Area of parallelogram ABCD = 153 cm² Question 3. Page 3 RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 1. Solution: In parallelogram ABCD, Base AB = 32cm Height DL = 16.5cm. Area = Base x height = 32 x 16.5 cm² = 528 cm² Question 2. . Solution: Base of parallelogram = 1 m 60m = 160 cm and height = 75 cm Area = Base x height = 160 x 75 = 12000 cm² = 12001/ 10000 m² = 1.2m² RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Base of parallelogram = 14dm = 140cm and height = 6.5 dm = 65cm Area (in cm²) = Base x height = 140 x 65 = 9100 cm² Area (in m²) = 140/100x 65/100 = 9100/10000 = 0.91 m² Question 4. Solution: Area of parallelogram = 54 cm² Base = 15 cm Question 5. Solution: Area of parallelogram ABCD = 153 cm² Question 3. RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 6. Solution: In parallelogram ABCD AB || DC and AD || BC and AB = DC, AD = BC AB = DC = 18cm, BC = 12cm Area of parallelogram ABCD = Base x altitude = DC x AL = 18 x 6.4cm2 = 115.2 cm² and area of parallelogram ABCD = BC x AM ? 115.2 = 12 x AM ? AM = 9.6 cm Question 7. Solution: In parallelogram ABCD AB = DC = 15 cm BC = AD = 8 cm. Distance between longer sides AB and DC is 4cm i.e. perpendicular DL = 4cm. DM ? BC. Area of parallelogram = Base x altitude = AB x DL = 15 x 4 = 60 cm² Again let DM = x cm area ABCD = BC x DM = 8 x x = 8x cm² 8x cm² = 60 cm² ? x = 7.5 cm Distance between shorter lines = 7.5 cm Page 4 RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 1. Solution: In parallelogram ABCD, Base AB = 32cm Height DL = 16.5cm. Area = Base x height = 32 x 16.5 cm² = 528 cm² Question 2. . Solution: Base of parallelogram = 1 m 60m = 160 cm and height = 75 cm Area = Base x height = 160 x 75 = 12000 cm² = 12001/ 10000 m² = 1.2m² RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Base of parallelogram = 14dm = 140cm and height = 6.5 dm = 65cm Area (in cm²) = Base x height = 140 x 65 = 9100 cm² Area (in m²) = 140/100x 65/100 = 9100/10000 = 0.91 m² Question 4. Solution: Area of parallelogram = 54 cm² Base = 15 cm Question 5. Solution: Area of parallelogram ABCD = 153 cm² Question 3. RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 6. Solution: In parallelogram ABCD AB || DC and AD || BC and AB = DC, AD = BC AB = DC = 18cm, BC = 12cm Area of parallelogram ABCD = Base x altitude = DC x AL = 18 x 6.4cm2 = 115.2 cm² and area of parallelogram ABCD = BC x AM ? 115.2 = 12 x AM ? AM = 9.6 cm Question 7. Solution: In parallelogram ABCD AB = DC = 15 cm BC = AD = 8 cm. Distance between longer sides AB and DC is 4cm i.e. perpendicular DL = 4cm. DM ? BC. Area of parallelogram = Base x altitude = AB x DL = 15 x 4 = 60 cm² Again let DM = x cm area ABCD = BC x DM = 8 x x = 8x cm² 8x cm² = 60 cm² ? x = 7.5 cm Distance between shorter lines = 7.5 cm RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Let Base of the parallelogram = x ? x² = 108 x 3 = 324 = (18)² ? x = 18 Base = 18 cm and altitude = x 18 = 6 cm Question 9. Solution: Area of parallelogram = 512 cm² Let height of the parallelogram = x Then base = 2x Area = Base x height ? 512 = 2x x x ? 2x² = 512 ? x² = 256 = (16)² ? x = 16 Base = 2x = 2 x 16 = 32 cm and height = x = 16 cm Question 8. Page 5 RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 1. Solution: In parallelogram ABCD, Base AB = 32cm Height DL = 16.5cm. Area = Base x height = 32 x 16.5 cm² = 528 cm² Question 2. . Solution: Base of parallelogram = 1 m 60m = 160 cm and height = 75 cm Area = Base x height = 160 x 75 = 12000 cm² = 12001/ 10000 m² = 1.2m² RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Base of parallelogram = 14dm = 140cm and height = 6.5 dm = 65cm Area (in cm²) = Base x height = 140 x 65 = 9100 cm² Area (in m²) = 140/100x 65/100 = 9100/10000 = 0.91 m² Question 4. Solution: Area of parallelogram = 54 cm² Base = 15 cm Question 5. Solution: Area of parallelogram ABCD = 153 cm² Question 3. RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Question 6. Solution: In parallelogram ABCD AB || DC and AD || BC and AB = DC, AD = BC AB = DC = 18cm, BC = 12cm Area of parallelogram ABCD = Base x altitude = DC x AL = 18 x 6.4cm2 = 115.2 cm² and area of parallelogram ABCD = BC x AM ? 115.2 = 12 x AM ? AM = 9.6 cm Question 7. Solution: In parallelogram ABCD AB = DC = 15 cm BC = AD = 8 cm. Distance between longer sides AB and DC is 4cm i.e. perpendicular DL = 4cm. DM ? BC. Area of parallelogram = Base x altitude = AB x DL = 15 x 4 = 60 cm² Again let DM = x cm area ABCD = BC x DM = 8 x x = 8x cm² 8x cm² = 60 cm² ? x = 7.5 cm Distance between shorter lines = 7.5 cm RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: Let Base of the parallelogram = x ? x² = 108 x 3 = 324 = (18)² ? x = 18 Base = 18 cm and altitude = x 18 = 6 cm Question 9. Solution: Area of parallelogram = 512 cm² Let height of the parallelogram = x Then base = 2x Area = Base x height ? 512 = 2x x x ? 2x² = 512 ? x² = 256 = (16)² ? x = 16 Base = 2x = 2 x 16 = 32 cm and height = x = 16 cm Question 8. RS Aggarwal Solutions Class 7 Chapter 20 - Mensuration (Ex 20C) Exercise 20C Solution: (i) Each side of rhombus = 12 cm height = 7.5 cm Area = Base x height = 12 x 7.5 = 90 cm² (ii) Each side = 2 cm = 20 cm Height = 12.6 cm Area = Base x height = 20 x 12.6 = 252 cm² Question 11. Question 10. Solution: (i) Diagonals of rhombus ABCD are 16 cm and 28 cmRead More
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