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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection : G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection : G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection : G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection : G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
Q.9 S el ect the opti on i n whi ch the gi v en ? gur e i s embedded ( r otati on i s N O T al l owed). A n s 1. 2. 3. 4. Question ID : 6 3 0 6 8 0 5 2 4 4 8 6 Op tion 1 ID : 6 3 0 6 8 0 2 0 5 0 0 4 5 Op tion 2 ID : 6 3 0 6 8 0 2 0 5 0 0 4 4 Op tion 3 ID : 6 3 0 6 8 0 2 0 5 0 0 4 6 Op tion 4 ID : 6 3 0 6 8 0 2 0 5 0 0 4 3 S tatus : A n s wer ed Ch osen Op tion : 2 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection : G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
Q.9 S el ect the opti on i n whi ch the gi v en ? gur e i s embedded ( r otati on i s N O T al l owed). A n s 1. 2. 3. 4. Question ID : 6 3 0 6 8 0 5 2 4 4 8 6 Op tion 1 ID : 6 3 0 6 8 0 2 0 5 0 0 4 5 Op tion 2 ID : 6 3 0 6 8 0 2 0 5 0 0 4 4 Op tion 3 ID : 6 3 0 6 8 0 2 0 5 0 0 4 6 Op tion 4 ID : 6 3 0 6 8 0 2 0 5 0 0 4 3 S tatus : A n s wer ed Ch osen Op tion : 2 www.prepp.in
Q.1 0 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 4 7 , 1 , 2 3 ) ( 5 8 , 4 , 2 7 ) A n s 1. (50, 14, 16) 2. (36, 30, 5) 3. (64, 5, 12) 4. (74, 18, 28) Question ID : 6 3 0 6 8 0 3 7 6 8 1 9 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 4 2 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 4 1 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 3 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 4 0 S tatus : A n s wer ed Ch osen Op tion : 4 Q.1 1 W hat s houl d come i n pl ace of the ques ti on mark ( ? ) i n the gi v en s eri es ? 1 1 5 , 9 1 , 7 0 , 5 2 , 3 7 , ? A n s 1. 25 2. 27 3. 23 4. 21 Question ID : 6 3 0 6 8 0 3 8 0 5 6 0 Op tion 1 ID : 6 3 0 6 8 0 1 4 8 3 2 3 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 8 3 2 2 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 8 3 2 2 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 8 3 2 2 7 S tatus : A n s wer ed Ch osen Op tion : 1 Q.1 2 A n i l s tar ts fr om poi n t A an d dri v es 7 km t owar ds the eas t. He then tak es a l eft turn , dri v es 3 km, turn s l eft, an d dri v es 9 km. He then tak es a ri ght turn an d dri v es 3 km. He tak es a ? n al ri ght turn , dri v es 2 km, an d s t ops at poi n t P . How far ( s hor tes t di s tan ce) an d t owar ds whi ch di r ecti on s houl d he dri v e i n or der t o r each poi n t A agai n ? ( A l l turn s ar e 9 0 ° turn s on l y , un l es s s peci ? ed.) A n s 1. 6 km t owar ds th e south 2. 8 km t owar ds th e east 3. 9 km t owar ds th e east 4. 6 km t owar ds th e west Question ID : 6 3 0 6 8 0 3 7 7 4 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 0 8 3 5 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 0 8 3 6 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 0 8 3 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 0 8 3 8 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
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