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Mechanical Engineering Exam  >  Mechanical Engineering Notes  >   SSC JE (Technical)  >  SSC JE Mechanical Paper 1 June 7, 2024 Shift 2

SSC JE Mechanical Paper 1 June 7, 2024 Shift 2

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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection :   G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection :   G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection :   G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection :   G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
Q.9 S el ect the opti on i n whi ch the gi v en ? gur e i s embedded ( r otati on i s N O T al l owed). A n s 1. 2. 3. 4. Question ID : 6 3 0 6 8 0 5 2 4 4 8 6 Op tion 1 ID : 6 3 0 6 8 0 2 0 5 0 0 4 5 Op tion 2 ID : 6 3 0 6 8 0 2 0 5 0 0 4 4 Op tion 3 ID : 6 3 0 6 8 0 2 0 5 0 0 4 6 Op tion 4 ID : 6 3 0 6 8 0 2 0 5 0 0 4 3 S tatus : A n s wer ed Ch osen Op tion : 2 www.prepp.in
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Q.1 Q, R , S , T , U, an d V ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der) . S s i ts s econ d t o the l eft of R . Q s i ts thi r d t o the ri ght of S . T i s n ot an i mmedi ate n ei ghbour of S . U s i ts t o the i mmedi ate l eft of S . How man y peopl e ar e s i tti n g between U an d R when coun ted fr om the ri ght of R ? A n s 1. Z er o 2. T h r ee 3. One 4. T wo Question ID : 6 3 0 6 8 0 3 7 7 6 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 6 3 1 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 6 3 4 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 6 3 2 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 6 3 3 S tatus : N ot A n s wer ed Ch osen Op tion : -- Q.2 S e v en peopl e - S , O , L, D , I, E, an d R - ar e s i tti n g ar oun d a ci r cul ar tabl e, faci n g the cen tr e ( n ot n eces s ari l y i n the s ame or der). O s i ts four th t o the l eft of E an d R s i ts thi r d t o the ri ght of O . L s i ts t o the i mmedi ate l eft of R an d t o the i mmedi ate ri ght of D . S s i ts s econ d t o the ri ght of R . W ho ar e the i mmedi ate n ei ghbours of I? A n s 1. O and D 2. O and L 3. S and E 4. S and O Question ID : 6 3 0 6 8 0 3 7 7 6 2 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 5 5 7 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 5 5 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 5 5 5 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 5 5 6 S tatus : N ot A n s wer ed Ch osen Op tion : -- Roll Num b er Candidate Nam e V enue Nam e Exam Date 07/ 06/ 2024 Exam T im e 1:00 P M - 3:00 P M S ub ject J unior Eng ineer 2024 Mech anical P ap er I S ection :   G en er al In tel l i gen ce an d R eas on i n g www.prepp.in
SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Question Paper with Answers
Q.3 W hat wi l l come i n the pl ace of the ques ti on mark ( ? ) i n the fol l owi n g equati on , i f ‘ + ’ an d ‘ - ’ ar e i n ter chan ged an d ‘ × ’ an d ‘ ÷ ’ ar e i n ter chan ged? 2 0 - 2 ÷ 4 × 2 + 6 = ? A n s 1. 18 2. 20 3. 22 4. 14 Question ID : 6 3 0 6 8 0 3 7 7 7 0 7 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 1 8 8 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 1 8 8 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 1 8 9 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 1 8 8 9 S tatus : A n s wer ed Ch osen Op tion : 1 Q.4 J N HF i s r el ated t o MQK I i n a cer tai n wa y bas ed on the En gl i s h al phabeti cal or der . In the s ame wa y , HLFD i s r el ated t o K OIG . T o whi ch of the fol l owi n g i s F J DB r el ated, fol l owi n g the s ame l ogi c? A n s 1. IMGE 2. IMEG 3. MIGE 4. MIEG Question ID : 6 3 0 6 8 0 4 6 6 9 5 8 Op tion 1 ID : 6 3 0 6 8 0 1 8 2 3 8 0 2 Op tion 2 ID : 6 3 0 6 8 0 1 8 2 3 8 0 3 Op tion 3 ID : 6 3 0 6 8 0 1 8 2 3 8 0 4 Op tion 4 ID : 6 3 0 6 8 0 1 8 2 3 8 0 5 S tatus : A n s wer ed Ch osen Op tion : 1 Q.5 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 1 7 , 6 8 , 8 ) ( 1 6 , 7 2 , 9 ) A n s 1. (13, 78, 5) 2. (10, 105, 21) 3. (25, 140, 12) 4. (11, 109, 13) Question ID : 6 3 0 6 8 0 3 7 6 8 1 1 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 0 8 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 0 9 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 1 0 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 0 7 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
Q.6 R ead the gi v en s tatemen ts an d con cl us i on s car eful l y . A s s umi n g that the i n formati on gi v en i n the s tatemen ts i s true, e v en i f i t appears t o be at v ari an ce wi th common l y kn own facts , deci de whi ch of the gi v en con cl us i on s l ogi cal l y fol l ow( s ) fr om the s tatemen ts . S tatemen ts : S ome machi n es ar e s hrugs . A l l machi n es ar e bi n s . N o s hrug i s a cl oth. Con cl us i on ( I): N o cl oth i s a machi n e. Con cl us i on ( II): A t l eas t s ome s hrugs ar e bi n s . A n s 1. Both conclusions (I) and (II) f ollow 2. Only conclusion (I) f ollows 3. Neith er conclusion (I) nor (II) f ollows 4. Only conclusion (II) f ollows Question ID : 6 3 0 6 8 0 3 7 6 5 2 5 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 7 1 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 7 1 6 7 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 7 1 6 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 7 1 6 8 S tatus : A n s wer ed Ch osen Op tion : 4 Q.7 S el ect the pai r i n whi ch the n umbers ar e r el ated t o each other i n the s ame wa y as ar e the n umbers of the gi v en pai rs . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/del eti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 2 9 7 , 4 6 6 ) ( 3 4 2 , 5 1 1 ) A n s 1. (225, 394) 2. (194, 353) 3. (116, 292) 4. (189, 348) Question ID : 6 3 0 6 8 0 3 9 2 0 6 2 Op tion 1 ID : 6 3 0 6 8 0 1 5 2 8 6 2 2 Op tion 2 ID : 6 3 0 6 8 0 1 5 2 8 6 2 4 Op tion 3 ID : 6 3 0 6 8 0 1 5 2 8 6 2 5 Op tion 4 ID : 6 3 0 6 8 0 1 5 2 8 6 2 3 S tatus : A n s wer ed Ch osen Op tion : 1 Q.8 W hat s houl d come i n pl ace of ? i n the gi v en s eri es bas ed on the En gl i s h al phabeti cal or der? BLH, EK F , HJ D , K IB, ? A n s 1. MF X 2. MEX 3. NHZ 4. OGY Question ID : 6 3 0 6 8 0 3 7 5 9 7 4 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 4 9 7 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 4 9 6 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 4 9 6 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 4 9 6 9 S tatus : A n s wer ed Ch osen Op tion : 3 www.prepp.in
Q.9 S el ect the opti on i n whi ch the gi v en ? gur e i s embedded ( r otati on i s N O T al l owed). A n s 1. 2. 3. 4. Question ID : 6 3 0 6 8 0 5 2 4 4 8 6 Op tion 1 ID : 6 3 0 6 8 0 2 0 5 0 0 4 5 Op tion 2 ID : 6 3 0 6 8 0 2 0 5 0 0 4 4 Op tion 3 ID : 6 3 0 6 8 0 2 0 5 0 0 4 6 Op tion 4 ID : 6 3 0 6 8 0 2 0 5 0 0 4 3 S tatus : A n s wer ed Ch osen Op tion : 2 www.prepp.in
Q.1 0 S el ect the s et i n whi ch the n umbers ar e r el ated i n the s ame wa y as ar e the n umbers of the fol l owi n g s ets . ( N O T E: Oper ati on s s houl d be per formed on the whol e n umbers , wi thout br eaki n g down the n umbers i n t o i ts con s ti tuen t di gi ts . E.g. 1 3 – Oper ati on s on 1 3 s uch as addi n g/s ubtr acti n g/mul ti pl yi n g etc. t o 1 3 can be per formed. Br eaki n g down 1 3 i n t o 1 an d 3 an d then per formi n g mathemati cal oper ati on s on 1 an d 3 i s n ot al l owed.) ( 4 7 , 1 , 2 3 ) ( 5 8 , 4 , 2 7 ) A n s 1. (50, 14, 16) 2. (36, 30, 5) 3. (64, 5, 12) 4. (74, 18, 28) Question ID : 6 3 0 6 8 0 3 7 6 8 1 9 Op tion 1 ID : 6 3 0 6 8 0 1 4 6 8 3 4 2 Op tion 2 ID : 6 3 0 6 8 0 1 4 6 8 3 4 1 Op tion 3 ID : 6 3 0 6 8 0 1 4 6 8 3 3 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 6 8 3 4 0 S tatus : A n s wer ed Ch osen Op tion : 4 Q.1 1 W hat s houl d come i n pl ace of the ques ti on mark ( ? ) i n the gi v en s eri es ? 1 1 5 , 9 1 , 7 0 , 5 2 , 3 7 , ? A n s 1. 25 2. 27 3. 23 4. 21 Question ID : 6 3 0 6 8 0 3 8 0 5 6 0 Op tion 1 ID : 6 3 0 6 8 0 1 4 8 3 2 3 0 Op tion 2 ID : 6 3 0 6 8 0 1 4 8 3 2 2 8 Op tion 3 ID : 6 3 0 6 8 0 1 4 8 3 2 2 9 Op tion 4 ID : 6 3 0 6 8 0 1 4 8 3 2 2 7 S tatus : A n s wer ed Ch osen Op tion : 1 Q.1 2 A n i l s tar ts fr om poi n t A an d dri v es 7 km t owar ds the eas t. He then tak es a l eft turn , dri v es 3 km, turn s l eft, an d dri v es 9 km. He then tak es a ri ght turn an d dri v es 3 km. He tak es a ? n al ri ght turn , dri v es 2 km, an d s t ops at poi n t P . How far ( s hor tes t di s tan ce) an d t owar ds whi ch di r ecti on s houl d he dri v e i n or der t o r each poi n t A agai n ? ( A l l turn s ar e 9 0 ° turn s on l y , un l es s s peci ? ed.) A n s 1. 6 km t owar ds th e south 2. 8 km t owar ds th e east 3. 9 km t owar ds th e east 4. 6 km t owar ds th e west Question ID : 6 3 0 6 8 0 3 7 7 4 4 3 Op tion 1 ID : 6 3 0 6 8 0 1 4 7 0 8 3 5 Op tion 2 ID : 6 3 0 6 8 0 1 4 7 0 8 3 6 Op tion 3 ID : 6 3 0 6 8 0 1 4 7 0 8 3 7 Op tion 4 ID : 6 3 0 6 8 0 1 4 7 0 8 3 8 S tatus : A n s wer ed Ch osen Op tion : 1 www.prepp.in
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FAQs on SSC JE Mechanical Paper 1 June 7, 2024 Shift 2

1. What are the most important topics covered in SSC JE Mechanical Paper 1 June 7, 2024 Shift 2?
Ans. SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 included questions on thermodynamics, fluid mechanics, strength of materials, machine design, and manufacturing processes. The exam focused on practical applications and conceptual understanding rather than theoretical derivations. Students should prioritise these high-weightage areas when preparing for similar shifts. Refer to previous year question papers and detailed notes to identify specific sub-topics and question patterns that appeared in this shift.
2. How can I solve thermodynamics questions faster in SSC JE Mechanical exams?
Ans. Quick thermodynamics problem-solving requires memorising standard formulas, understanding the first and second laws of thermodynamics, and recognising common question patterns from previous papers. Master the relationship between heat, work, and internal energy early. Practice mock tests focusing on time management-aim to solve each question in 1-2 minutes maximum. Use flashcards and mind maps to recall key concepts instantly during the exam.
3. What's the difference between elastic and plastic deformation in strength of materials for SSC JE?
Ans. Elastic deformation is temporary-the material returns to its original shape after the stress is removed, whereas plastic deformation is permanent and causes irreversible shape changes. Understanding this distinction is crucial for designing safe mechanical components. Elastic behaviour follows Hooke's Law, while plastic deformation occurs beyond the yield point. This conceptual difference frequently appears in SSC JE Mechanical Paper 1 questions.
4. Which machine design concepts appear most frequently in SSC JE exams?
Ans. Shaft design, bearing selection, gear design, and coupling calculations dominate SSC JE Mechanical Paper 1. These topics test both theoretical knowledge and practical engineering judgement. Students often struggle with stress concentration factors and fatigue analysis in shafts. Review previous year papers from June 7, 2024 and earlier shifts to identify recurring design principles and calculation methods commonly tested in this exam.
5. How do I approach fluid mechanics problems in SSC JE without making calculation errors?
Ans. Begin by identifying the fluid flow type-laminar, turbulent, or compressible-then apply the appropriate continuity equation or Bernoulli's principle systematically. Write down unit conversions upfront to avoid common errors. Sketch a clear problem diagram showing all given data and unknowns. Practice questions from previous shifts repeatedly, focusing on pressure drop calculations, velocity profiles, and energy losses in piping systems regularly tested in SSC JE Mechanical exams.
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Document Description: SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 for Mechanical Engineering 2026 is part of Mechanical Engineering SSC JE (Technical) preparation. The notes and questions for SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 have been prepared according to the Mechanical Engineering exam syllabus. Information about SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 covers topics like and SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 Example, for Mechanical Engineering 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for SSC JE Mechanical Paper 1 June 7, 2024 Shift 2.
Introduction of SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 in English is available as part of our Mechanical Engineering SSC JE (Technical) for Mechanical Engineering & SSC JE Mechanical Paper 1 June 7, 2024 Shift 2 in Hindi for Mechanical Engineering SSC JE (Technical) course. Download more important topics related with notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Mechanical Engineering: SSC JE Mechanical Paper 1 June 7, 2024 Shift 2
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