Page 1
JEE Main Previous Year Questions
(2025): Determinants
Q1: Let the system of equations
?? + ???? - ?? = ??
???? + ???? - ???? = ??
?????? + ?? + ?? ?? = ??
?? , ?? ? R, have infinitely many solutions. Then the number of the solutions of this
system,
if ?? , ?? , ?? are integers and satisfy ?? = ?? + ?? + ?? = ???? , is :
JEE Main 2025 (Online) 7th April Evening Shift
Options:
A. 4
B. 5
C. 3
D. 6
Ans: C
Solution:
For infinitely many solution
? = 0
|
1 5 -1
4 3 -3
24 1 ?? | = 0
? 1(3?? + 3) - 5(4?? + 72) - 1(4 - 72) = 0
? -17?? + 3 - 4 × 72 - 4 = 0
? 17?? = -289
? ?? = -17
?1 = 0
? |
1 5 -1
7 3 -3
?? 1 -17
| = 0
? 1(-51 + 3) - 5(-119 + 3?? ) - 1(7 - 3?? ) = 0
? -48 + 595 - 15?? - 7 + 3?? = 0
? 12?? = 540
?? = 45
?? + 5?? - ?? = 1
4?? + 3?? - 3?? = 7
24?? + ?? - 17?? = 45
Let ?? = 1
Page 2
JEE Main Previous Year Questions
(2025): Determinants
Q1: Let the system of equations
?? + ???? - ?? = ??
???? + ???? - ???? = ??
?????? + ?? + ?? ?? = ??
?? , ?? ? R, have infinitely many solutions. Then the number of the solutions of this
system,
if ?? , ?? , ?? are integers and satisfy ?? = ?? + ?? + ?? = ???? , is :
JEE Main 2025 (Online) 7th April Evening Shift
Options:
A. 4
B. 5
C. 3
D. 6
Ans: C
Solution:
For infinitely many solution
? = 0
|
1 5 -1
4 3 -3
24 1 ?? | = 0
? 1(3?? + 3) - 5(4?? + 72) - 1(4 - 72) = 0
? -17?? + 3 - 4 × 72 - 4 = 0
? 17?? = -289
? ?? = -17
?1 = 0
? |
1 5 -1
7 3 -3
?? 1 -17
| = 0
? 1(-51 + 3) - 5(-119 + 3?? ) - 1(7 - 3?? ) = 0
? -48 + 595 - 15?? - 7 + 3?? = 0
? 12?? = 540
?? = 45
?? + 5?? - ?? = 1
4?? + 3?? - 3?? = 7
24?? + ?? - 17?? = 45
Let ?? = 1
?? + 5?? = 1 + ?? ] × 4
4?? + 3?? = 7 + 3??
4x + 20y = 4 + 4?? -17y = 3 - ??
y =
?? - 3
17
, x = 1 + ?? -
5?? - 15
17
=
32 - 12?? 17
7 =
?? - 3
17
+
32 + 12?? 17
+ ?? = 77
7 =
30?? + 29
17
= 77
3 = ?? = 42
?? = 3,20,37
Q2: If the system of linear equations :
?? + ?? + ?? ?? = ??
?? ?? + ?? ?? + ???? = ?? + ??
-?? - ?? ?? + ?? ?? = ?? ??
where ?? , ?? ? ?? , has infinitely many solutions, then ?? ?? + ?? ?? is equal to :
JEE Main 2025 (Online) 22nd January Evening Shift
Options:
A. 12
B. 9
C. 22
D. 16
Ans: D
Solution:
We begin with the system:
?? + ?? + 2?? = 6
2?? + 3?? + ???? = ?? + 1
-?? - 3?? + ???? = 2??
Step 1. Solve the first equation for ?? :
?? = 6 - ?? - 2?? .
Step 2. Substitute ?? = 6 - ?? - 2?? into the second equation:
2(6 - ?? - 2?? ) + 3?? + ???? = ?? + 1.
Expanding and simplifying:
12 - 2?? - 4?? + 3?? + ???? = ?? + 1 ? ?? + (?? - 4)?? = ?? - 11.
Call this Equation (I).
Step 3. Substitute ?? = 6 - ?? - 2?? into the third equation:
Page 3
JEE Main Previous Year Questions
(2025): Determinants
Q1: Let the system of equations
?? + ???? - ?? = ??
???? + ???? - ???? = ??
?????? + ?? + ?? ?? = ??
?? , ?? ? R, have infinitely many solutions. Then the number of the solutions of this
system,
if ?? , ?? , ?? are integers and satisfy ?? = ?? + ?? + ?? = ???? , is :
JEE Main 2025 (Online) 7th April Evening Shift
Options:
A. 4
B. 5
C. 3
D. 6
Ans: C
Solution:
For infinitely many solution
? = 0
|
1 5 -1
4 3 -3
24 1 ?? | = 0
? 1(3?? + 3) - 5(4?? + 72) - 1(4 - 72) = 0
? -17?? + 3 - 4 × 72 - 4 = 0
? 17?? = -289
? ?? = -17
?1 = 0
? |
1 5 -1
7 3 -3
?? 1 -17
| = 0
? 1(-51 + 3) - 5(-119 + 3?? ) - 1(7 - 3?? ) = 0
? -48 + 595 - 15?? - 7 + 3?? = 0
? 12?? = 540
?? = 45
?? + 5?? - ?? = 1
4?? + 3?? - 3?? = 7
24?? + ?? - 17?? = 45
Let ?? = 1
?? + 5?? = 1 + ?? ] × 4
4?? + 3?? = 7 + 3??
4x + 20y = 4 + 4?? -17y = 3 - ??
y =
?? - 3
17
, x = 1 + ?? -
5?? - 15
17
=
32 - 12?? 17
7 =
?? - 3
17
+
32 + 12?? 17
+ ?? = 77
7 =
30?? + 29
17
= 77
3 = ?? = 42
?? = 3,20,37
Q2: If the system of linear equations :
?? + ?? + ?? ?? = ??
?? ?? + ?? ?? + ???? = ?? + ??
-?? - ?? ?? + ?? ?? = ?? ??
where ?? , ?? ? ?? , has infinitely many solutions, then ?? ?? + ?? ?? is equal to :
JEE Main 2025 (Online) 22nd January Evening Shift
Options:
A. 12
B. 9
C. 22
D. 16
Ans: D
Solution:
We begin with the system:
?? + ?? + 2?? = 6
2?? + 3?? + ???? = ?? + 1
-?? - 3?? + ???? = 2??
Step 1. Solve the first equation for ?? :
?? = 6 - ?? - 2?? .
Step 2. Substitute ?? = 6 - ?? - 2?? into the second equation:
2(6 - ?? - 2?? ) + 3?? + ???? = ?? + 1.
Expanding and simplifying:
12 - 2?? - 4?? + 3?? + ???? = ?? + 1 ? ?? + (?? - 4)?? = ?? - 11.
Call this Equation (I).
Step 3. Substitute ?? = 6 - ?? - 2?? into the third equation:
-(6 - ?? - 2?? ) - 3?? + ???? = 2?? .
Expanding and simplifying:
-6 + ?? + 2?? - 3?? + ???? = 2?? ? -2?? + (?? + 2)?? = 2?? + 6.
Call this Equation (II).
Step 4. For the system to have infinitely many solutions, the two equations in ?? and ?? must be
dependent-that is, one must be a constant multiple of the other. Assume there exists a constant
?? such that
-2 = ?? · 1 ? ?? = -2.
Apply this to the coefficient of ?? and the constant term.
For the ?? -coefficient in Equations (I) and (II):
?? + 2 = ?? (?? - 4) = -2(?? - 4) = -2?? + 8.
Thus,
?? = -2?? + 6.
For the constant term:
2?? + 6 = ?? (?? - 11) = -2(?? - 11) = -2?? + 22.
Substitute ?? = -2?? + 6 into this equation:
2(-2?? + 6) + 6 = -2?? + 22 ? -4?? + 12 + 6 = -2?? + 22.
Simplify:
-4?? + 18 = -2?? + 22.
Solve for ?? :
-4?? + 18 + 4?? = -2?? + 22 + 4?? ? 18 = 2?? + 22,
2?? = 18 - 22 = -4 ? ?? = -2.
Substitute ?? = -2 into ?? = -2?? + 6 :
?? = -2(-2) + 6 = 4 + 6 = 10.
Step 5. We now compute
7?? + 3?? = 7(-2) + 3(10) = -14 + 30 = 16.
Thus, the value of 7?? + 3?? is
16.
Q3: If the system of linear equations
?? ?? + ?? + ???? = ??
?? ?? + ???? - ?? = -??
?? + ?? ?? + ?? = ??
has infinitely many solutions, then the value of ???? ?? - ?? ?? is :
JEE Main 2025 (Online) 2nd April Morning Shift
Options:
A. 31
B. 37
C. 43
D. 49
Ans: A
Page 4
JEE Main Previous Year Questions
(2025): Determinants
Q1: Let the system of equations
?? + ???? - ?? = ??
???? + ???? - ???? = ??
?????? + ?? + ?? ?? = ??
?? , ?? ? R, have infinitely many solutions. Then the number of the solutions of this
system,
if ?? , ?? , ?? are integers and satisfy ?? = ?? + ?? + ?? = ???? , is :
JEE Main 2025 (Online) 7th April Evening Shift
Options:
A. 4
B. 5
C. 3
D. 6
Ans: C
Solution:
For infinitely many solution
? = 0
|
1 5 -1
4 3 -3
24 1 ?? | = 0
? 1(3?? + 3) - 5(4?? + 72) - 1(4 - 72) = 0
? -17?? + 3 - 4 × 72 - 4 = 0
? 17?? = -289
? ?? = -17
?1 = 0
? |
1 5 -1
7 3 -3
?? 1 -17
| = 0
? 1(-51 + 3) - 5(-119 + 3?? ) - 1(7 - 3?? ) = 0
? -48 + 595 - 15?? - 7 + 3?? = 0
? 12?? = 540
?? = 45
?? + 5?? - ?? = 1
4?? + 3?? - 3?? = 7
24?? + ?? - 17?? = 45
Let ?? = 1
?? + 5?? = 1 + ?? ] × 4
4?? + 3?? = 7 + 3??
4x + 20y = 4 + 4?? -17y = 3 - ??
y =
?? - 3
17
, x = 1 + ?? -
5?? - 15
17
=
32 - 12?? 17
7 =
?? - 3
17
+
32 + 12?? 17
+ ?? = 77
7 =
30?? + 29
17
= 77
3 = ?? = 42
?? = 3,20,37
Q2: If the system of linear equations :
?? + ?? + ?? ?? = ??
?? ?? + ?? ?? + ???? = ?? + ??
-?? - ?? ?? + ?? ?? = ?? ??
where ?? , ?? ? ?? , has infinitely many solutions, then ?? ?? + ?? ?? is equal to :
JEE Main 2025 (Online) 22nd January Evening Shift
Options:
A. 12
B. 9
C. 22
D. 16
Ans: D
Solution:
We begin with the system:
?? + ?? + 2?? = 6
2?? + 3?? + ???? = ?? + 1
-?? - 3?? + ???? = 2??
Step 1. Solve the first equation for ?? :
?? = 6 - ?? - 2?? .
Step 2. Substitute ?? = 6 - ?? - 2?? into the second equation:
2(6 - ?? - 2?? ) + 3?? + ???? = ?? + 1.
Expanding and simplifying:
12 - 2?? - 4?? + 3?? + ???? = ?? + 1 ? ?? + (?? - 4)?? = ?? - 11.
Call this Equation (I).
Step 3. Substitute ?? = 6 - ?? - 2?? into the third equation:
-(6 - ?? - 2?? ) - 3?? + ???? = 2?? .
Expanding and simplifying:
-6 + ?? + 2?? - 3?? + ???? = 2?? ? -2?? + (?? + 2)?? = 2?? + 6.
Call this Equation (II).
Step 4. For the system to have infinitely many solutions, the two equations in ?? and ?? must be
dependent-that is, one must be a constant multiple of the other. Assume there exists a constant
?? such that
-2 = ?? · 1 ? ?? = -2.
Apply this to the coefficient of ?? and the constant term.
For the ?? -coefficient in Equations (I) and (II):
?? + 2 = ?? (?? - 4) = -2(?? - 4) = -2?? + 8.
Thus,
?? = -2?? + 6.
For the constant term:
2?? + 6 = ?? (?? - 11) = -2(?? - 11) = -2?? + 22.
Substitute ?? = -2?? + 6 into this equation:
2(-2?? + 6) + 6 = -2?? + 22 ? -4?? + 12 + 6 = -2?? + 22.
Simplify:
-4?? + 18 = -2?? + 22.
Solve for ?? :
-4?? + 18 + 4?? = -2?? + 22 + 4?? ? 18 = 2?? + 22,
2?? = 18 - 22 = -4 ? ?? = -2.
Substitute ?? = -2 into ?? = -2?? + 6 :
?? = -2(-2) + 6 = 4 + 6 = 10.
Step 5. We now compute
7?? + 3?? = 7(-2) + 3(10) = -14 + 30 = 16.
Thus, the value of 7?? + 3?? is
16.
Q3: If the system of linear equations
?? ?? + ?? + ???? = ??
?? ?? + ???? - ?? = -??
?? + ?? ?? + ?? = ??
has infinitely many solutions, then the value of ???? ?? - ?? ?? is :
JEE Main 2025 (Online) 2nd April Morning Shift
Options:
A. 31
B. 37
C. 43
D. 49
Ans: A
Solution:
3?? + ?? + ???? = 3
2?? + ???? - ?? = -3
?? + 2?? + ?? = 4
has infinite solution
? ? = 0, ?
1
= ?
2
= ?
3
? = 0 ? |
3 1 ?? 2 ?? -1
1 2 1
| = 0
?
2
= 0 ? |
3 3 ?? 2 -3 -1
1 4 1
| = 0
? 3(-3 + 4) - 3(2 + 1) + ?? (8 + 3) = 0
? 3 - 9 + 11?? = 0
? ?? =
6
11
?
3
= 0 ? |
3 1 3
2 ?? -3
1 2 4
| = 0
? 3(4?? + 6) - 1(8 + 3) + 3(4 - ?? ) = 0
12?? + 18 - 11 + 12 - 3?? = 0
9?? = -19
?? =
-19
9
? 22?? - 9?? = 31
Q4: If the system of equations
?? ?? + ???? + ?? ?? = ??
?? ?? + ?? ?? - ?? = ??
?? ?? + ?? ?? + ???? = ??
has infinitely many solutions, then (?? ?? + ?? ?? ) is equal to :
JEE Main 2025 (Online) 2nd April Evening Shift
Options:
A. 30
B. 26
C. 22
D. 18
Ans: B
Solution:
Page 5
JEE Main Previous Year Questions
(2025): Determinants
Q1: Let the system of equations
?? + ???? - ?? = ??
???? + ???? - ???? = ??
?????? + ?? + ?? ?? = ??
?? , ?? ? R, have infinitely many solutions. Then the number of the solutions of this
system,
if ?? , ?? , ?? are integers and satisfy ?? = ?? + ?? + ?? = ???? , is :
JEE Main 2025 (Online) 7th April Evening Shift
Options:
A. 4
B. 5
C. 3
D. 6
Ans: C
Solution:
For infinitely many solution
? = 0
|
1 5 -1
4 3 -3
24 1 ?? | = 0
? 1(3?? + 3) - 5(4?? + 72) - 1(4 - 72) = 0
? -17?? + 3 - 4 × 72 - 4 = 0
? 17?? = -289
? ?? = -17
?1 = 0
? |
1 5 -1
7 3 -3
?? 1 -17
| = 0
? 1(-51 + 3) - 5(-119 + 3?? ) - 1(7 - 3?? ) = 0
? -48 + 595 - 15?? - 7 + 3?? = 0
? 12?? = 540
?? = 45
?? + 5?? - ?? = 1
4?? + 3?? - 3?? = 7
24?? + ?? - 17?? = 45
Let ?? = 1
?? + 5?? = 1 + ?? ] × 4
4?? + 3?? = 7 + 3??
4x + 20y = 4 + 4?? -17y = 3 - ??
y =
?? - 3
17
, x = 1 + ?? -
5?? - 15
17
=
32 - 12?? 17
7 =
?? - 3
17
+
32 + 12?? 17
+ ?? = 77
7 =
30?? + 29
17
= 77
3 = ?? = 42
?? = 3,20,37
Q2: If the system of linear equations :
?? + ?? + ?? ?? = ??
?? ?? + ?? ?? + ???? = ?? + ??
-?? - ?? ?? + ?? ?? = ?? ??
where ?? , ?? ? ?? , has infinitely many solutions, then ?? ?? + ?? ?? is equal to :
JEE Main 2025 (Online) 22nd January Evening Shift
Options:
A. 12
B. 9
C. 22
D. 16
Ans: D
Solution:
We begin with the system:
?? + ?? + 2?? = 6
2?? + 3?? + ???? = ?? + 1
-?? - 3?? + ???? = 2??
Step 1. Solve the first equation for ?? :
?? = 6 - ?? - 2?? .
Step 2. Substitute ?? = 6 - ?? - 2?? into the second equation:
2(6 - ?? - 2?? ) + 3?? + ???? = ?? + 1.
Expanding and simplifying:
12 - 2?? - 4?? + 3?? + ???? = ?? + 1 ? ?? + (?? - 4)?? = ?? - 11.
Call this Equation (I).
Step 3. Substitute ?? = 6 - ?? - 2?? into the third equation:
-(6 - ?? - 2?? ) - 3?? + ???? = 2?? .
Expanding and simplifying:
-6 + ?? + 2?? - 3?? + ???? = 2?? ? -2?? + (?? + 2)?? = 2?? + 6.
Call this Equation (II).
Step 4. For the system to have infinitely many solutions, the two equations in ?? and ?? must be
dependent-that is, one must be a constant multiple of the other. Assume there exists a constant
?? such that
-2 = ?? · 1 ? ?? = -2.
Apply this to the coefficient of ?? and the constant term.
For the ?? -coefficient in Equations (I) and (II):
?? + 2 = ?? (?? - 4) = -2(?? - 4) = -2?? + 8.
Thus,
?? = -2?? + 6.
For the constant term:
2?? + 6 = ?? (?? - 11) = -2(?? - 11) = -2?? + 22.
Substitute ?? = -2?? + 6 into this equation:
2(-2?? + 6) + 6 = -2?? + 22 ? -4?? + 12 + 6 = -2?? + 22.
Simplify:
-4?? + 18 = -2?? + 22.
Solve for ?? :
-4?? + 18 + 4?? = -2?? + 22 + 4?? ? 18 = 2?? + 22,
2?? = 18 - 22 = -4 ? ?? = -2.
Substitute ?? = -2 into ?? = -2?? + 6 :
?? = -2(-2) + 6 = 4 + 6 = 10.
Step 5. We now compute
7?? + 3?? = 7(-2) + 3(10) = -14 + 30 = 16.
Thus, the value of 7?? + 3?? is
16.
Q3: If the system of linear equations
?? ?? + ?? + ???? = ??
?? ?? + ???? - ?? = -??
?? + ?? ?? + ?? = ??
has infinitely many solutions, then the value of ???? ?? - ?? ?? is :
JEE Main 2025 (Online) 2nd April Morning Shift
Options:
A. 31
B. 37
C. 43
D. 49
Ans: A
Solution:
3?? + ?? + ???? = 3
2?? + ???? - ?? = -3
?? + 2?? + ?? = 4
has infinite solution
? ? = 0, ?
1
= ?
2
= ?
3
? = 0 ? |
3 1 ?? 2 ?? -1
1 2 1
| = 0
?
2
= 0 ? |
3 3 ?? 2 -3 -1
1 4 1
| = 0
? 3(-3 + 4) - 3(2 + 1) + ?? (8 + 3) = 0
? 3 - 9 + 11?? = 0
? ?? =
6
11
?
3
= 0 ? |
3 1 3
2 ?? -3
1 2 4
| = 0
? 3(4?? + 6) - 1(8 + 3) + 3(4 - ?? ) = 0
12?? + 18 - 11 + 12 - 3?? = 0
9?? = -19
?? =
-19
9
? 22?? - 9?? = 31
Q4: If the system of equations
?? ?? + ???? + ?? ?? = ??
?? ?? + ?? ?? - ?? = ??
?? ?? + ?? ?? + ???? = ??
has infinitely many solutions, then (?? ?? + ?? ?? ) is equal to :
JEE Main 2025 (Online) 2nd April Evening Shift
Options:
A. 30
B. 26
C. 22
D. 18
Ans: B
Solution:
2?? + ???? + 3?? = 5
3?? + 2?? - ?? = 7
4?? + 5?? + ???? = 9
For infinite solutions ? ? = 0 = ?
1
= ?
2
= ?
3
? = |
2 ?? 3
3 2 -1
4 5 ?? | = 0
? -4?? - 3???? + 4?? + 31 = 0
?
1
= |
5 ?? 3
7 2 -1
9 5 ?? | = 0 ? -9?? - 7???? + 10?? + 76 = 0
?
2
= |
2 3 5
3 -1 7
4 ?? 9
| = 0 ? ?? + 5 = 0 ? ?? = -5
?
3
= |
2 ?? 5
3 2 7
4 5 9
| = 0 ? ?? + 1 = 0 ? ?? = -1
? For infinite solution ?? = -5 and ?? = -1
Now ?? 2
+ ?? 2
= 25 + 1
= 26
Q5: Let the system of equations :
?? ?? + ?? ?? + ?? ?? = ??
?? ?? + ?? ?? - ?? ?? = ??
???? ?? + ?? ?? - (?? + ?? )?? = ???? - ??
have infinitely many solutions. Then the radius of the circle centred at ( ?? , ?? ) and
touching the line ?? ?? = ?? ?? is :
JEE Main 2025 (Online) 7th April Morning Shift
Options:
A.
7
5
B.
21
5
C. 7
D.
17
5
Ans: A
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