JEE Exam > JEE Notes > Physics Main & Advanced > JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments
JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Q1: The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature ?? = ?? ?? . Another car approaches him from behind with a uniform speed of ???? ???? /???? . When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' ?? '. The value of ?????? ?? is _ _ _ _ ?? /?? ?? . JEE Main 2025 (Online) 22nd January Morning Shift Ans: 8 Solution: Given, R = 2 m, So, f = 1 m (as ?? = ?? 2 ) ?? 0 = 90 km / hr = 90 × 1000 3600 = 25 m / s ?? 0 is uniform, so ?? 0 = 0 ?? = - 24 ?? 1 ?? + 1 ?? = 1 ?? ? 1 ?? + 1 - 24 = 1 1 ? 1 ?? = 1 + 1 24 = 25 24 ? ?? = 24 25 ?? ?? = - ?? ?? by differentiating mirror formula, Page 2 JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Q1: The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature ?? = ?? ?? . Another car approaches him from behind with a uniform speed of ???? ???? /???? . When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' ?? '. The value of ?????? ?? is _ _ _ _ ?? /?? ?? . JEE Main 2025 (Online) 22nd January Morning Shift Ans: 8 Solution: Given, R = 2 m, So, f = 1 m (as ?? = ?? 2 ) ?? 0 = 90 km / hr = 90 × 1000 3600 = 25 m / s ?? 0 is uniform, so ?? 0 = 0 ?? = - 24 ?? 1 ?? + 1 ?? = 1 ?? ? 1 ?? + 1 - 24 = 1 1 ? 1 ?? = 1 + 1 24 = 25 24 ? ?? = 24 25 ?? ?? = - ?? ?? by differentiating mirror formula, - 1 ?? 2 ???? ???? - 1 ?? 2 ???? ???? = 0 ? - 1 ?? 2 ?? ?? - 1 ?? 2 ?? 0 = 0 ( 1 ) ? ?? ?? = - ?? 2 ?? 2 ?? 0 = - 24 2 25 2 ? ?? ?? = - 1 25 m / s by differentiating (1) w.r.t. time, - 1 ?? 2 ?? ?? + 2 ?? 3 ?? ?? 2 - 1 ?? 2 ?? 0 + 2 ?? 3 ?? 0 2 = 0 ?? ?? = 2 ?? ?? ?? 2 + 2 ?? 2 ?? 3 ?? 0 2 = 2 24 1 25 2 + 2 - 24 3 24 2 25 2 25 2 = 1 12 [ 1 25 - 1 ] = 1 12 × - 24 25 = - 2 25 ? 100 ?? ?? = - 2 25 × 100 = 8 m / s 2 Q2: Two light beams fall on a transparent material block at point 1 and 2 with angle ?? ?? and ?? ?? , respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and ?? , ?? = ?? v ?? ???? and ?? ?? = ?? ?? = ?? ?? ?? - ?? ? ( ?? ?? ?? ?? ?? ). where refractive index of the block ?? ?? > refractive index of the outside medium ?? ?? , then the thickness of the block is _ _ _ _ cm . JEE Main 2025 (Online) 29th January Morning Shift Ans: 6 Solution: Page 3 JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Q1: The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature ?? = ?? ?? . Another car approaches him from behind with a uniform speed of ???? ???? /???? . When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' ?? '. The value of ?????? ?? is _ _ _ _ ?? /?? ?? . JEE Main 2025 (Online) 22nd January Morning Shift Ans: 8 Solution: Given, R = 2 m, So, f = 1 m (as ?? = ?? 2 ) ?? 0 = 90 km / hr = 90 × 1000 3600 = 25 m / s ?? 0 is uniform, so ?? 0 = 0 ?? = - 24 ?? 1 ?? + 1 ?? = 1 ?? ? 1 ?? + 1 - 24 = 1 1 ? 1 ?? = 1 + 1 24 = 25 24 ? ?? = 24 25 ?? ?? = - ?? ?? by differentiating mirror formula, - 1 ?? 2 ???? ???? - 1 ?? 2 ???? ???? = 0 ? - 1 ?? 2 ?? ?? - 1 ?? 2 ?? 0 = 0 ( 1 ) ? ?? ?? = - ?? 2 ?? 2 ?? 0 = - 24 2 25 2 ? ?? ?? = - 1 25 m / s by differentiating (1) w.r.t. time, - 1 ?? 2 ?? ?? + 2 ?? 3 ?? ?? 2 - 1 ?? 2 ?? 0 + 2 ?? 3 ?? 0 2 = 0 ?? ?? = 2 ?? ?? ?? 2 + 2 ?? 2 ?? 3 ?? 0 2 = 2 24 1 25 2 + 2 - 24 3 24 2 25 2 25 2 = 1 12 [ 1 25 - 1 ] = 1 12 × - 24 25 = - 2 25 ? 100 ?? ?? = - 2 25 × 100 = 8 m / s 2 Q2: Two light beams fall on a transparent material block at point 1 and 2 with angle ?? ?? and ?? ?? , respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and ?? , ?? = ?? v ?? ???? and ?? ?? = ?? ?? = ?? ?? ?? - ?? ? ( ?? ?? ?? ?? ?? ). where refractive index of the block ?? ?? > refractive index of the outside medium ?? ?? , then the thickness of the block is _ _ _ _ cm . JEE Main 2025 (Online) 29th January Morning Shift Ans: 6 Solution: n 1 s i n ? ( 90 - ?? 1 ) = n 2 sin ? ?? 3 n 1 c o s ? ?? 1 = n 2 sin ? ?? 3 n 1 n 2 2 n 1 = n 2 sin ? ?? 3 1 2 = sin ? ?? 3 , ?? 3 = 30 tan ? 30 = d 2 ( t ) t = d v 3 2 = 4 v 3 × v 3 2 cm = 6 cm Q3: A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to ???? ° . The refractive index of the prism material is v ?? . The angle of incidence (in degrees) is _ _ _ _ JEE Main 2025 (Online) 2nd April Evening Shift Ans: 45 Solution: To find the angle of incidence when a ray of light experiences minimum deviation in a prism, we use the formula for the refractive index ?? : ?? = sin ? ( ?? + ?? ?? 2 ) sin ? ( ?? 2 ) Given: The angle of the prism, ?? = 60 ° The refractive index of the prism material, ?? = v 2 Minimum deviation, ?? ?? = 30 ° At minimum deviation, the angle of incidence ?? equals the angle of emergence ?? . Therefore, the Page 4 JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Q1: The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature ?? = ?? ?? . Another car approaches him from behind with a uniform speed of ???? ???? /???? . When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' ?? '. The value of ?????? ?? is _ _ _ _ ?? /?? ?? . JEE Main 2025 (Online) 22nd January Morning Shift Ans: 8 Solution: Given, R = 2 m, So, f = 1 m (as ?? = ?? 2 ) ?? 0 = 90 km / hr = 90 × 1000 3600 = 25 m / s ?? 0 is uniform, so ?? 0 = 0 ?? = - 24 ?? 1 ?? + 1 ?? = 1 ?? ? 1 ?? + 1 - 24 = 1 1 ? 1 ?? = 1 + 1 24 = 25 24 ? ?? = 24 25 ?? ?? = - ?? ?? by differentiating mirror formula, - 1 ?? 2 ???? ???? - 1 ?? 2 ???? ???? = 0 ? - 1 ?? 2 ?? ?? - 1 ?? 2 ?? 0 = 0 ( 1 ) ? ?? ?? = - ?? 2 ?? 2 ?? 0 = - 24 2 25 2 ? ?? ?? = - 1 25 m / s by differentiating (1) w.r.t. time, - 1 ?? 2 ?? ?? + 2 ?? 3 ?? ?? 2 - 1 ?? 2 ?? 0 + 2 ?? 3 ?? 0 2 = 0 ?? ?? = 2 ?? ?? ?? 2 + 2 ?? 2 ?? 3 ?? 0 2 = 2 24 1 25 2 + 2 - 24 3 24 2 25 2 25 2 = 1 12 [ 1 25 - 1 ] = 1 12 × - 24 25 = - 2 25 ? 100 ?? ?? = - 2 25 × 100 = 8 m / s 2 Q2: Two light beams fall on a transparent material block at point 1 and 2 with angle ?? ?? and ?? ?? , respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and ?? , ?? = ?? v ?? ???? and ?? ?? = ?? ?? = ?? ?? ?? - ?? ? ( ?? ?? ?? ?? ?? ). where refractive index of the block ?? ?? > refractive index of the outside medium ?? ?? , then the thickness of the block is _ _ _ _ cm . JEE Main 2025 (Online) 29th January Morning Shift Ans: 6 Solution: n 1 s i n ? ( 90 - ?? 1 ) = n 2 sin ? ?? 3 n 1 c o s ? ?? 1 = n 2 sin ? ?? 3 n 1 n 2 2 n 1 = n 2 sin ? ?? 3 1 2 = sin ? ?? 3 , ?? 3 = 30 tan ? 30 = d 2 ( t ) t = d v 3 2 = 4 v 3 × v 3 2 cm = 6 cm Q3: A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to ???? ° . The refractive index of the prism material is v ?? . The angle of incidence (in degrees) is _ _ _ _ JEE Main 2025 (Online) 2nd April Evening Shift Ans: 45 Solution: To find the angle of incidence when a ray of light experiences minimum deviation in a prism, we use the formula for the refractive index ?? : ?? = sin ? ( ?? + ?? ?? 2 ) sin ? ( ?? 2 ) Given: The angle of the prism, ?? = 60 ° The refractive index of the prism material, ?? = v 2 Minimum deviation, ?? ?? = 30 ° At minimum deviation, the angle of incidence ?? equals the angle of emergence ?? . Therefore, the relation between the angle of minimum deviation and the angle of the prism is represented as: ?? ?? = 2 ?? - ?? Solving for ?? : ?? ?? = 2 ?? - ?? ? 30 ° = 2 ?? - 60 ° ? 2 ?? = 90 ° ? ?? = 45 ° Q4: Light from a point source in air falls on a spherical glass surface (refractive index, ?? = ?? . ?? and radius of curvature = ???? ???? ). The image is formed at a distance of 200 cm from the glass surface inside the glass. The magnitude of distance of the light source from the glass surface is _ _ _ _ m. JEE Main 2025 (Online) 3rd April Evening Shift Ans: 4 Solution: ?? 2 v - ?? 1 u = ?? 2 - ?? 1 R 1 . 5 200 - 1 - x = 1 . 5 - 1 50 1 x = 1 100 - 3 400 x = 400 cm x = 4 m Q5: Distance between object and its image (magnified by - ?? ?? ) is ???? ???? . The focal length of the mirror used is ( ?? ?? ) ???? ,where magnitude of value of ?? is _ _ _ _ . JEE Main 2025 (Online) 4th April Morning Shift Ans: 45 Solution: ?? = - 1 3 Page 5 JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Q1: The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature ?? = ?? ?? . Another car approaches him from behind with a uniform speed of ???? ???? /???? . When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' ?? '. The value of ?????? ?? is _ _ _ _ ?? /?? ?? . JEE Main 2025 (Online) 22nd January Morning Shift Ans: 8 Solution: Given, R = 2 m, So, f = 1 m (as ?? = ?? 2 ) ?? 0 = 90 km / hr = 90 × 1000 3600 = 25 m / s ?? 0 is uniform, so ?? 0 = 0 ?? = - 24 ?? 1 ?? + 1 ?? = 1 ?? ? 1 ?? + 1 - 24 = 1 1 ? 1 ?? = 1 + 1 24 = 25 24 ? ?? = 24 25 ?? ?? = - ?? ?? by differentiating mirror formula, - 1 ?? 2 ???? ???? - 1 ?? 2 ???? ???? = 0 ? - 1 ?? 2 ?? ?? - 1 ?? 2 ?? 0 = 0 ( 1 ) ? ?? ?? = - ?? 2 ?? 2 ?? 0 = - 24 2 25 2 ? ?? ?? = - 1 25 m / s by differentiating (1) w.r.t. time, - 1 ?? 2 ?? ?? + 2 ?? 3 ?? ?? 2 - 1 ?? 2 ?? 0 + 2 ?? 3 ?? 0 2 = 0 ?? ?? = 2 ?? ?? ?? 2 + 2 ?? 2 ?? 3 ?? 0 2 = 2 24 1 25 2 + 2 - 24 3 24 2 25 2 25 2 = 1 12 [ 1 25 - 1 ] = 1 12 × - 24 25 = - 2 25 ? 100 ?? ?? = - 2 25 × 100 = 8 m / s 2 Q2: Two light beams fall on a transparent material block at point 1 and 2 with angle ?? ?? and ?? ?? , respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and ?? , ?? = ?? v ?? ???? and ?? ?? = ?? ?? = ?? ?? ?? - ?? ? ( ?? ?? ?? ?? ?? ). where refractive index of the block ?? ?? > refractive index of the outside medium ?? ?? , then the thickness of the block is _ _ _ _ cm . JEE Main 2025 (Online) 29th January Morning Shift Ans: 6 Solution: n 1 s i n ? ( 90 - ?? 1 ) = n 2 sin ? ?? 3 n 1 c o s ? ?? 1 = n 2 sin ? ?? 3 n 1 n 2 2 n 1 = n 2 sin ? ?? 3 1 2 = sin ? ?? 3 , ?? 3 = 30 tan ? 30 = d 2 ( t ) t = d v 3 2 = 4 v 3 × v 3 2 cm = 6 cm Q3: A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to ???? ° . The refractive index of the prism material is v ?? . The angle of incidence (in degrees) is _ _ _ _ JEE Main 2025 (Online) 2nd April Evening Shift Ans: 45 Solution: To find the angle of incidence when a ray of light experiences minimum deviation in a prism, we use the formula for the refractive index ?? : ?? = sin ? ( ?? + ?? ?? 2 ) sin ? ( ?? 2 ) Given: The angle of the prism, ?? = 60 ° The refractive index of the prism material, ?? = v 2 Minimum deviation, ?? ?? = 30 ° At minimum deviation, the angle of incidence ?? equals the angle of emergence ?? . Therefore, the relation between the angle of minimum deviation and the angle of the prism is represented as: ?? ?? = 2 ?? - ?? Solving for ?? : ?? ?? = 2 ?? - ?? ? 30 ° = 2 ?? - 60 ° ? 2 ?? = 90 ° ? ?? = 45 ° Q4: Light from a point source in air falls on a spherical glass surface (refractive index, ?? = ?? . ?? and radius of curvature = ???? ???? ). The image is formed at a distance of 200 cm from the glass surface inside the glass. The magnitude of distance of the light source from the glass surface is _ _ _ _ m. JEE Main 2025 (Online) 3rd April Evening Shift Ans: 4 Solution: ?? 2 v - ?? 1 u = ?? 2 - ?? 1 R 1 . 5 200 - 1 - x = 1 . 5 - 1 50 1 x = 1 100 - 3 400 x = 400 cm x = 4 m Q5: Distance between object and its image (magnified by - ?? ?? ) is ???? ???? . The focal length of the mirror used is ( ?? ?? ) ???? ,where magnitude of value of ?? is _ _ _ _ . JEE Main 2025 (Online) 4th April Morning Shift Ans: 45 Solution: ?? = - 1 3 - - ?? - ?? = - 1 3 ? ?? = ?? 3 Distance b / w object and image : ?? - ?? = 30 ?? - ?? 3 = 30 ? ? ?? = 45 ? ?? = 15 1 ?? = 1 ?? + 1 ?? = - 1 15 - 1 45 ? ? ?? = 45 4 ?? = 45 Q6: A container contains a liquid with refractive index of ?? . ?? up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm . The value of H is _ _ _ _ cm . (Consider liquids are immisible) JEE Main 2025 (Online) 7th April Morning Shift Ans: 80 Solution:Read More
FAQs on JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments
| 1. What is the principle of reflection in ray optics? |  |
Ans.The principle of reflection states that when a ray of light strikes a reflective surface, the angle of incidence is equal to the angle of reflection. This means if a light ray hits a surface at an angle θ₁ (angle of incidence), it will reflect off at the same angle θ₂ (angle of reflection), measured from the normal (a line perpendicular to the surface at the point of incidence).
| 2. How do lenses form images and what are the types of lenses? | |
Ans.Lenses form images through the refraction of light. There are two main types of lenses: convex (converging) lenses, which bulge outward and cause parallel rays of light to converge at a focal point; and concave (diverging) lenses, which curve inward and cause parallel rays to diverge as if they originated from a focal point behind the lens. The nature of the image formed (real or virtual, upright or inverted) depends on the position of the object relative to the focal length of the lens.
| 3. What is the role of the human eye in optics and how does it function? | |
Ans.The human eye functions as a complex optical instrument that focuses light to create images. It contains several key components: the cornea, which refracts incoming light; the lens, which further adjusts the focus; and the retina, which detects light and converts it into electrical signals sent to the brain. The eye adjusts its focus through a process known as accommodation, where the lens changes shape to focus on objects at various distances.
| 4. What are the characteristics of images formed by concave and convex mirrors? | |
Ans.Images formed by concave mirrors can be real or virtual, depending on the object's position relative to the focal point. Real images are inverted and can be projected on a screen, while virtual images are upright and cannot be projected. In contrast, convex mirrors always produce virtual images that are upright and smaller than the object, regardless of the object's distance from the mirror.
| 5. How is total internal reflection utilized in optical fibers? | |
Ans.Total internal reflection is a phenomenon that occurs when a light ray traveling in a denser medium hits the boundary with a less dense medium at an angle greater than the critical angle. In optical fibers, light is guided through the fiber core by repeatedly undergoing total internal reflection at the core-cladding boundary, allowing for efficient transmission of light signals over long distances with minimal loss.
About this Document
4.77/5 Rating
Apr 25, 2026 Last updated
Document Description: JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments for JEE 2026 is part of Physics for JEE Main & Advanced preparation. The notes and questions for JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments have been prepared according to the JEE exam syllabus. Information about JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments covers topics like and JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments Example, for JEE 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments.
Introduction of JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments in English is available as part of our Physics for JEE Main & Advanced for JEE & JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments in Hindi for Physics for JEE Main & Advanced course. Download more important topics related with notes, lectures and mock test series for JEE Exam by signing up for free. JEE: JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments
Description
JEE Main Previous Year Questions (2025): Ray Optics & Optical Instruments of Physics is important for the exam. Get access to all the questions with solutions asked in past years of JEE exam. Download it from EduRev.
Information about JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments
In this doc you can find the meaning of JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments defined & explained in the simplest way possible. Besides explaining types of JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments theory, EduRev gives you an ample number of questions to practice JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments tests, examples and also practice JEE tests
Related Searches
pdf , ppt, Summary, Previous Year Questions with Solutions, MCQs, Free, past year papers, Viva Questions, Exam, Sample Paper, JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments, study material, video lectures, Extra Questions, Objective type Questions, JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments, shortcuts and tricks, JEE Main Previous Year Questions (2025): Ray Optics and Optical Instruments, Important questions, Semester Notes, mock tests for examination, practice quizzes;