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JEE Advanced Numericals: Friction & Circular Motion

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1  
CIRCULAR MOTION 
 
Paragraph for Question Nos. 1 and 2 
 A frame of reference that is accelerated with respect to an inertial frame of reference is called a  
non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis 
with a constant angular velocity ? is an example of a non-inertial frame of reference. The relationship 
between the force 
rot
F
?
 experienced by a particle of mass m moving on the rotating disc and the force 
in
F
?
 
experienced by the particle in an inertial frame of reference is 
( )
( )
rot in rot
F F 2m m r = + ? ×? + ? × ×?
??
? ? ?? ?
, 
 where 
rot
?
?
 is the velocity of the particle in the rotating frame of reference and r
?
 is the position vector of 
the particle with respect to the centre of the disc. 
 Now consider a smooth slot along a diameter of a disc of radius R rotating 
counter-clockwise with a constant angular speed ? about its vertical axis 
through its center. We assign a coordinate system with the origin at the 
centre of the disc, the x-axis along the slot, the y-axis perpendicular to the 
slot and the z-axis along the rotation axis 
( )
ˆ
k ?= ?
?
. A small block of  
mass m is gently placed in the slot at 
( )
ˆ
r R /2 i =
?
 at t = 0 and is constrained 
to move only along the slot. 
1. The distance r of the block at time t is :    
 (A) 
( )
2t 2t
R
ee
4
? -?
+ (B) 
R
cos2 t
2
? (C) 
R
cos t
2
? (D) 
( )
tt
R
e e
4
? -?
+ 
2. The net reaction of the disc on the block is :    
 (A) 
2
ˆ ˆ
m R cos tj mgk - ? ?- (B) 
2
ˆ ˆ
m Rsin tj mgk ? ?- 
 (C) 
( )
2 t t
1
ˆ ˆ
m R e e j mgk
2
? -?
? - + (D) 
( )
2 2t 2t
1
ˆ ˆ
m R e e j mgk
2
? -?
? - + 
 
?
R/2
R
m
Page 2


 
    
 
 
   
1  
CIRCULAR MOTION 
 
Paragraph for Question Nos. 1 and 2 
 A frame of reference that is accelerated with respect to an inertial frame of reference is called a  
non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis 
with a constant angular velocity ? is an example of a non-inertial frame of reference. The relationship 
between the force 
rot
F
?
 experienced by a particle of mass m moving on the rotating disc and the force 
in
F
?
 
experienced by the particle in an inertial frame of reference is 
( )
( )
rot in rot
F F 2m m r = + ? ×? + ? × ×?
??
? ? ?? ?
, 
 where 
rot
?
?
 is the velocity of the particle in the rotating frame of reference and r
?
 is the position vector of 
the particle with respect to the centre of the disc. 
 Now consider a smooth slot along a diameter of a disc of radius R rotating 
counter-clockwise with a constant angular speed ? about its vertical axis 
through its center. We assign a coordinate system with the origin at the 
centre of the disc, the x-axis along the slot, the y-axis perpendicular to the 
slot and the z-axis along the rotation axis 
( )
ˆ
k ?= ?
?
. A small block of  
mass m is gently placed in the slot at 
( )
ˆ
r R /2 i =
?
 at t = 0 and is constrained 
to move only along the slot. 
1. The distance r of the block at time t is :    
 (A) 
( )
2t 2t
R
ee
4
? -?
+ (B) 
R
cos2 t
2
? (C) 
R
cos t
2
? (D) 
( )
tt
R
e e
4
? -?
+ 
2. The net reaction of the disc on the block is :    
 (A) 
2
ˆ ˆ
m R cos tj mgk - ? ?- (B) 
2
ˆ ˆ
m Rsin tj mgk ? ?- 
 (C) 
( )
2 t t
1
ˆ ˆ
m R e e j mgk
2
? -?
? - + (D) 
( )
2 2t 2t
1
ˆ ˆ
m R e e j mgk
2
? -?
? - + 
 
?
R/2
R
m
 
  
    
 
   
 
2 
 
SOLUTIONS 
 
1. Ans. (D) 
Sol. Force on block along slot = m ?
2
r = ma  
= 
vdv
m
dr
??
??
??
   ? 
vr
2
0 R/2
vdv rdr = ?
??
 
22 2 2
22
v R R dr
r vr
2 2 4 4 dt
??
?
= - ?=? - =
??
??
 
 
rt
2
R/4 0 2
dr
dt
R
r
4
? =?
-
??
 
2 2 2
2
R R R
r r R /2
4 44
nn t
RR
22
? ? ? ?
? ? ? ? +- + -
? ? ? ?
-=?
? ? ? ?
? ? ? ?
? ? ? ?
??
2
2t
RR
rr e
42
?
?+ - = 
 
22
2 2t 2 t
RR R
r e r 2r e
44 2
??
? - = +- 
 
( )
22
2t
tt
t
RR
e
R
44
r e e
4 Re
?
? -?
?
+
?= = + 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
2. Ans. (C) 
Sol. 
 
mg
N
1
N
2
2m(V' ×
rot
?)
 
 
1
ˆ
N mgk =
?
 
 
( )
2 rot
ˆ
N 2m V' j = × ?
?
?
 
 
( )
t t
R
ˆ
2m e e j
4
? -?
???
= - ?
??
??
 
 
( )
2 t t
1
ˆ
m Re e j
2
? -?
= ?- 
 Total reaction on block = 
12
NN +
??
 
 
( )
2 t t
1
ˆ ˆ
m R e e j mgk
2
? -?
= ? - + 
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FAQs on JEE Advanced Numericals: Friction & Circular Motion

1. What is the concept of friction and its importance in circular motion?
Ans. Friction is the resistive force that opposes the relative motion between two surfaces in contact. In circular motion, friction plays a crucial role in providing the necessary centripetal force that keeps an object moving in a circular path. Without sufficient friction, an object would slide off its circular path. For example, in a car turning around a curve, friction between the tires and the road allows the car to maintain its circular trajectory.
2. How is the maximum static friction calculated, and why is it significant in circular motion?
Ans. The maximum static friction (f_s,max) can be calculated using the formula f_s,max = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force. This is significant in circular motion because it determines the maximum speed an object can have while navigating a curve without slipping. If the required centripetal force exceeds the maximum static friction, the object will lose traction and slide outward.
3. What is the difference between static and kinetic friction in the context of circular motion?
Ans. Static friction occurs when an object is at rest relative to the surface, while kinetic friction applies when the object is in motion. In circular motion, static friction is crucial when an object is just starting to move in a circular path, as it prevents slipping. Once the object is in motion, kinetic friction comes into play, which is typically less than static friction, affecting the object's ability to maintain its circular trajectory under varying speeds.
4. How does the radius of a circular path influence the frictional force required for an object in motion?
Ans. The radius of the circular path directly influences the required centripetal force and, consequently, the frictional force. For a given speed, a smaller radius requires a greater centripetal force to maintain circular motion. This means that the frictional force must also be greater to prevent slipping. Thus, as the radius decreases, the demand for friction increases, making it critical for maintaining motion without loss of control.
5. What role does the coefficient of friction play in determining the motion of an object in circular motion?
Ans. The coefficient of friction (μ) quantifies the amount of frictional force between two surfaces. In circular motion, it helps determine the maximum speed at which an object can travel without slipping. A higher coefficient of friction means that more frictional force is available to counteract the required centripetal force, allowing for higher speeds on a circular path. Conversely, a lower coefficient limits the speed and may lead to loss of traction.

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