Page 1
Age
Problems
Page 2
Age
Problems
I n t r o d u c t i o n
Age problems involve setting up and solving equations based on relationships
between individuals' ages.
Practicing these problems enhances problem-solving and interpretation skills,
which are crucial for competitive exams like SBI PO, SBI Clerk, IBPS PO, IBPS
Clerk, and IBPS RRB.
These problems cover various scenarios, including age differences, ratios,
and past/present ages, providing comprehensive preparation.
Page 3
Age
Problems
I n t r o d u c t i o n
Age problems involve setting up and solving equations based on relationships
between individuals' ages.
Practicing these problems enhances problem-solving and interpretation skills,
which are crucial for competitive exams like SBI PO, SBI Clerk, IBPS PO, IBPS
Clerk, and IBPS RRB.
These problems cover various scenarios, including age differences, ratios,
and past/present ages, providing comprehensive preparation.
Problem 1:
Rajeev's age after 15 years will be 5 times his age 5 years back. What is
the present age of Rajeev?
S o l u t i o n : Let Rajeev's present age be x years. Then, Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeev's present age = 10 years.
Page 4
Age
Problems
I n t r o d u c t i o n
Age problems involve setting up and solving equations based on relationships
between individuals' ages.
Practicing these problems enhances problem-solving and interpretation skills,
which are crucial for competitive exams like SBI PO, SBI Clerk, IBPS PO, IBPS
Clerk, and IBPS RRB.
These problems cover various scenarios, including age differences, ratios,
and past/present ages, providing comprehensive preparation.
Problem 1:
Rajeev's age after 15 years will be 5 times his age 5 years back. What is
the present age of Rajeev?
S o l u t i o n : Let Rajeev's present age be x years. Then, Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeev's present age = 10 years.
Problem 2:
The ages of two persons differ by 16 years. If 6 years ago, the elder
one is 3 times as old as the younger one, find their present ages.
Solution: Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
Therefore 3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.
Page 5
Age
Problems
I n t r o d u c t i o n
Age problems involve setting up and solving equations based on relationships
between individuals' ages.
Practicing these problems enhances problem-solving and interpretation skills,
which are crucial for competitive exams like SBI PO, SBI Clerk, IBPS PO, IBPS
Clerk, and IBPS RRB.
These problems cover various scenarios, including age differences, ratios,
and past/present ages, providing comprehensive preparation.
Problem 1:
Rajeev's age after 15 years will be 5 times his age 5 years back. What is
the present age of Rajeev?
S o l u t i o n : Let Rajeev's present age be x years. Then, Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeev's present age = 10 years.
Problem 2:
The ages of two persons differ by 16 years. If 6 years ago, the elder
one is 3 times as old as the younger one, find their present ages.
Solution: Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
Therefore 3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.
Problem 3:
The product of the ages of Ankit and Nikita is 240. If twice the age of
Nikita is more than Ankit's age by 4 years, what is Nikita's age?
S o l u t i o n : Let Ankit's age be x years. Then, Nikita's age = 240/x years.
2 * (240 /x ) 3 x = 4
480 3 x² = 4x
x² + 4x 3 480 = 0
( x+24)(x-20) = 0
x = 20.
Hence, Nikita's age = 240/x = 240/20 years = 12 years.
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