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Class 12 Physics: CBSE Marking Scheme (2025-26)
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Page 1
CHEMISTRY CODE - 043
MARKING SCHEME
CLASS XII (2025-26)
Time: 3 hours Max. Marks: 70
GENERAL INSTRUCTIONS:
Read the following instructions carefully.
1. There are 33 questions in this question paper with internal choice.
2. SECTION A consists of 16 multiple-choice questions carrying 1 mark each.
3. SECTION B consists of 5 short answer questions carrying 2 marks each.
4. SECTION C consists of 7 short answer questions carrying 3 marks each.
5. SECTION D consists of 2 case-based questions carrying 4 marks each.
6. SECTION E consists of 3 long answer questions carrying 5 marks each.
7. All questions are compulsory.
8. Use of log tables and calculators is not allowed.
Section-A
1 C. Ozonolysis of CH3CH2C(CH3)=CHCH3
1
2 C. B= Butan-2-ol, C= Butanol
CH3CH2CH2CH2Cl
NaOH +Ethanol
. CH3CH2CH=CH2
CH3CH2CH=CH2 CH3CH2CH(OH)CH2
CH3CH2CH=CH2 CH3CH2CH2CHOH
1
3 C. chloride 1
(i) B 2H 6.
(ii)H 2O 2, OH
H 2O, H
+
Page 2
CHEMISTRY CODE - 043
MARKING SCHEME
CLASS XII (2025-26)
Time: 3 hours Max. Marks: 70
GENERAL INSTRUCTIONS:
Read the following instructions carefully.
1. There are 33 questions in this question paper with internal choice.
2. SECTION A consists of 16 multiple-choice questions carrying 1 mark each.
3. SECTION B consists of 5 short answer questions carrying 2 marks each.
4. SECTION C consists of 7 short answer questions carrying 3 marks each.
5. SECTION D consists of 2 case-based questions carrying 4 marks each.
6. SECTION E consists of 3 long answer questions carrying 5 marks each.
7. All questions are compulsory.
8. Use of log tables and calculators is not allowed.
Section-A
1 C. Ozonolysis of CH3CH2C(CH3)=CHCH3
1
2 C. B= Butan-2-ol, C= Butanol
CH3CH2CH2CH2Cl
NaOH +Ethanol
. CH3CH2CH=CH2
CH3CH2CH=CH2 CH3CH2CH(OH)CH2
CH3CH2CH=CH2 CH3CH2CH2CHOH
1
3 C. chloride 1
(i) B 2H 6.
(ii)H 2O 2, OH
H 2O, H
+
The formula of coordination complex, the ions outside the square
bracket are called counter ions.
4 A. A> B>C
A is primary, B is secondary amine, C is tertiary amine.Primary amines
are having higher boiling point as compared to secondary and tertiary
amines.
1
5 C. 0.73
m =
?? 2
????
2
x
1000
?? 1
m =
70
????
2
x
1000
700
M =
?? 2
????
2
x
1000
?? Here, V =
?? 1
+?? 2
?? =
770
1.5
M =
70
????
2
x
1000 ?? 1.5
770
?? ?? =
770
700 ?? 1.5
= 0.73
1
6 D. A-(iv), B-(iii), C-(ii), D-(i)
1
7 B. sp
2
hybrid.
The –OH group has replaced –H of benzene ring. All
carbons of benzene are sp
2
hybrid.
1
8 C. Beta D – fructose
1
9 C. both lanthanoids and actinoids
1
10 C. Either 1 or 3
?
?? ?? CH3COOH = ?
?? ?? HCl + ?
?? ?? CH3COOK - ?
?? ?? KCl
1
Page 3
CHEMISTRY CODE - 043
MARKING SCHEME
CLASS XII (2025-26)
Time: 3 hours Max. Marks: 70
GENERAL INSTRUCTIONS:
Read the following instructions carefully.
1. There are 33 questions in this question paper with internal choice.
2. SECTION A consists of 16 multiple-choice questions carrying 1 mark each.
3. SECTION B consists of 5 short answer questions carrying 2 marks each.
4. SECTION C consists of 7 short answer questions carrying 3 marks each.
5. SECTION D consists of 2 case-based questions carrying 4 marks each.
6. SECTION E consists of 3 long answer questions carrying 5 marks each.
7. All questions are compulsory.
8. Use of log tables and calculators is not allowed.
Section-A
1 C. Ozonolysis of CH3CH2C(CH3)=CHCH3
1
2 C. B= Butan-2-ol, C= Butanol
CH3CH2CH2CH2Cl
NaOH +Ethanol
. CH3CH2CH=CH2
CH3CH2CH=CH2 CH3CH2CH(OH)CH2
CH3CH2CH=CH2 CH3CH2CH2CHOH
1
3 C. chloride 1
(i) B 2H 6.
(ii)H 2O 2, OH
H 2O, H
+
The formula of coordination complex, the ions outside the square
bracket are called counter ions.
4 A. A> B>C
A is primary, B is secondary amine, C is tertiary amine.Primary amines
are having higher boiling point as compared to secondary and tertiary
amines.
1
5 C. 0.73
m =
?? 2
????
2
x
1000
?? 1
m =
70
????
2
x
1000
700
M =
?? 2
????
2
x
1000
?? Here, V =
?? 1
+?? 2
?? =
770
1.5
M =
70
????
2
x
1000 ?? 1.5
770
?? ?? =
770
700 ?? 1.5
= 0.73
1
6 D. A-(iv), B-(iii), C-(ii), D-(i)
1
7 B. sp
2
hybrid.
The –OH group has replaced –H of benzene ring. All
carbons of benzene are sp
2
hybrid.
1
8 C. Beta D – fructose
1
9 C. both lanthanoids and actinoids
1
10 C. Either 1 or 3
?
?? ?? CH3COOH = ?
?? ?? HCl + ?
?? ?? CH3COOK - ?
?? ?? KCl
1
?
?? ?? CH3COOH = 1/2 ?
?? ?? H2SO4 + ?
?? ?? CH3COONa – 1/2 ?
?? ?? Na2SO4
11 A. (i) and (ii)
Aldehydes and ketones react with 2,4 dinitrophenylhydrazine to give a
yellow/orange ppt of 2,4 dintirophenylhydrazone
1
12 (a) B. (iv) and (ii)
(b)
1
13 D. A is false but R is true
Primary aliphatic amines react with nitrous acid to form aliphatic
diazonium salts which being unstable, liberate nitrogen gas
1
14 B. Both A and R are true, and R is not the correct explanation of A.
If osmotic pressure of the solutions that flow in the blood stream is not
same as that of the blood, exosmosis or endosmosis will take place.
1
15 A. Both A and R are true, and R is the correct explanation of A.
In starch, the major component is 80-85% of amylopectin is insoluble
in water. Hence starch is not completely soluble in water and form
colloidal solution.
1
16
C. A is true but R is false.
A primary cell becomes dead after use, it cannot be recharged.
1
17 Option A
I. The volume will be less than 100 ml. The intermolecular forces
between phenol and aniline is stronger than phenol-phenol and aniline-
aniline which results in decrease in volume.
II. Salt lowers the freezing point of water ie. it leads to depression in
freezing point. This will delay the melting of ice.
OR
Option B
I. Precipitate of BaSO4 will not appear as osmosis involves movement
of solvent molecules and not solute.
1
1
1
Page 4
CHEMISTRY CODE - 043
MARKING SCHEME
CLASS XII (2025-26)
Time: 3 hours Max. Marks: 70
GENERAL INSTRUCTIONS:
Read the following instructions carefully.
1. There are 33 questions in this question paper with internal choice.
2. SECTION A consists of 16 multiple-choice questions carrying 1 mark each.
3. SECTION B consists of 5 short answer questions carrying 2 marks each.
4. SECTION C consists of 7 short answer questions carrying 3 marks each.
5. SECTION D consists of 2 case-based questions carrying 4 marks each.
6. SECTION E consists of 3 long answer questions carrying 5 marks each.
7. All questions are compulsory.
8. Use of log tables and calculators is not allowed.
Section-A
1 C. Ozonolysis of CH3CH2C(CH3)=CHCH3
1
2 C. B= Butan-2-ol, C= Butanol
CH3CH2CH2CH2Cl
NaOH +Ethanol
. CH3CH2CH=CH2
CH3CH2CH=CH2 CH3CH2CH(OH)CH2
CH3CH2CH=CH2 CH3CH2CH2CHOH
1
3 C. chloride 1
(i) B 2H 6.
(ii)H 2O 2, OH
H 2O, H
+
The formula of coordination complex, the ions outside the square
bracket are called counter ions.
4 A. A> B>C
A is primary, B is secondary amine, C is tertiary amine.Primary amines
are having higher boiling point as compared to secondary and tertiary
amines.
1
5 C. 0.73
m =
?? 2
????
2
x
1000
?? 1
m =
70
????
2
x
1000
700
M =
?? 2
????
2
x
1000
?? Here, V =
?? 1
+?? 2
?? =
770
1.5
M =
70
????
2
x
1000 ?? 1.5
770
?? ?? =
770
700 ?? 1.5
= 0.73
1
6 D. A-(iv), B-(iii), C-(ii), D-(i)
1
7 B. sp
2
hybrid.
The –OH group has replaced –H of benzene ring. All
carbons of benzene are sp
2
hybrid.
1
8 C. Beta D – fructose
1
9 C. both lanthanoids and actinoids
1
10 C. Either 1 or 3
?
?? ?? CH3COOH = ?
?? ?? HCl + ?
?? ?? CH3COOK - ?
?? ?? KCl
1
?
?? ?? CH3COOH = 1/2 ?
?? ?? H2SO4 + ?
?? ?? CH3COONa – 1/2 ?
?? ?? Na2SO4
11 A. (i) and (ii)
Aldehydes and ketones react with 2,4 dinitrophenylhydrazine to give a
yellow/orange ppt of 2,4 dintirophenylhydrazone
1
12 (a) B. (iv) and (ii)
(b)
1
13 D. A is false but R is true
Primary aliphatic amines react with nitrous acid to form aliphatic
diazonium salts which being unstable, liberate nitrogen gas
1
14 B. Both A and R are true, and R is not the correct explanation of A.
If osmotic pressure of the solutions that flow in the blood stream is not
same as that of the blood, exosmosis or endosmosis will take place.
1
15 A. Both A and R are true, and R is the correct explanation of A.
In starch, the major component is 80-85% of amylopectin is insoluble
in water. Hence starch is not completely soluble in water and form
colloidal solution.
1
16
C. A is true but R is false.
A primary cell becomes dead after use, it cannot be recharged.
1
17 Option A
I. The volume will be less than 100 ml. The intermolecular forces
between phenol and aniline is stronger than phenol-phenol and aniline-
aniline which results in decrease in volume.
II. Salt lowers the freezing point of water ie. it leads to depression in
freezing point. This will delay the melting of ice.
OR
Option B
I. Precipitate of BaSO4 will not appear as osmosis involves movement
of solvent molecules and not solute.
1
1
1
II. Sugar being non-volatile solute, lowers the vapour pressure above
the solution. This leads to elevation in boiling point.
1
18 I. Ea for backward reaction = 40 kJ/mol, ?H= 10 kJ/mol
II. Catalyst will increase the rate of reaction as the activation energy
required to form intermediate activated complex between reactant and
catalyst is lower than the activation energy required for forming
complex without catalyst.
(for visually challenged learners)
I. The minimum energy required to form the intermediate activated
complex, is known as activation energy (Ea). Activation energy is the
least possible energy required to start a chemical reaction. The
activation energy doesn’t change with change in temperature.
II. Catalyst will increase the rate of reaction as the activation energy
required to form intermediate activated complex between reactant and
catalyst is lower than the activation energy required for forming complex
without catalyst.
1
1
1
1
19 I
II.
C6H5CH2Cl + KCN C6H5CH2CN
LiAlH
4 C6H5CH2CH2NH2
1
1
20 I. [Ag(H2O)2 ][Ag(Cl)2 ]
II. [Ni(OH)2(PPh3)2 ]
1
1
Page 5
CHEMISTRY CODE - 043
MARKING SCHEME
CLASS XII (2025-26)
Time: 3 hours Max. Marks: 70
GENERAL INSTRUCTIONS:
Read the following instructions carefully.
1. There are 33 questions in this question paper with internal choice.
2. SECTION A consists of 16 multiple-choice questions carrying 1 mark each.
3. SECTION B consists of 5 short answer questions carrying 2 marks each.
4. SECTION C consists of 7 short answer questions carrying 3 marks each.
5. SECTION D consists of 2 case-based questions carrying 4 marks each.
6. SECTION E consists of 3 long answer questions carrying 5 marks each.
7. All questions are compulsory.
8. Use of log tables and calculators is not allowed.
Section-A
1 C. Ozonolysis of CH3CH2C(CH3)=CHCH3
1
2 C. B= Butan-2-ol, C= Butanol
CH3CH2CH2CH2Cl
NaOH +Ethanol
. CH3CH2CH=CH2
CH3CH2CH=CH2 CH3CH2CH(OH)CH2
CH3CH2CH=CH2 CH3CH2CH2CHOH
1
3 C. chloride 1
(i) B 2H 6.
(ii)H 2O 2, OH
H 2O, H
+
The formula of coordination complex, the ions outside the square
bracket are called counter ions.
4 A. A> B>C
A is primary, B is secondary amine, C is tertiary amine.Primary amines
are having higher boiling point as compared to secondary and tertiary
amines.
1
5 C. 0.73
m =
?? 2
????
2
x
1000
?? 1
m =
70
????
2
x
1000
700
M =
?? 2
????
2
x
1000
?? Here, V =
?? 1
+?? 2
?? =
770
1.5
M =
70
????
2
x
1000 ?? 1.5
770
?? ?? =
770
700 ?? 1.5
= 0.73
1
6 D. A-(iv), B-(iii), C-(ii), D-(i)
1
7 B. sp
2
hybrid.
The –OH group has replaced –H of benzene ring. All
carbons of benzene are sp
2
hybrid.
1
8 C. Beta D – fructose
1
9 C. both lanthanoids and actinoids
1
10 C. Either 1 or 3
?
?? ?? CH3COOH = ?
?? ?? HCl + ?
?? ?? CH3COOK - ?
?? ?? KCl
1
?
?? ?? CH3COOH = 1/2 ?
?? ?? H2SO4 + ?
?? ?? CH3COONa – 1/2 ?
?? ?? Na2SO4
11 A. (i) and (ii)
Aldehydes and ketones react with 2,4 dinitrophenylhydrazine to give a
yellow/orange ppt of 2,4 dintirophenylhydrazone
1
12 (a) B. (iv) and (ii)
(b)
1
13 D. A is false but R is true
Primary aliphatic amines react with nitrous acid to form aliphatic
diazonium salts which being unstable, liberate nitrogen gas
1
14 B. Both A and R are true, and R is not the correct explanation of A.
If osmotic pressure of the solutions that flow in the blood stream is not
same as that of the blood, exosmosis or endosmosis will take place.
1
15 A. Both A and R are true, and R is the correct explanation of A.
In starch, the major component is 80-85% of amylopectin is insoluble
in water. Hence starch is not completely soluble in water and form
colloidal solution.
1
16
C. A is true but R is false.
A primary cell becomes dead after use, it cannot be recharged.
1
17 Option A
I. The volume will be less than 100 ml. The intermolecular forces
between phenol and aniline is stronger than phenol-phenol and aniline-
aniline which results in decrease in volume.
II. Salt lowers the freezing point of water ie. it leads to depression in
freezing point. This will delay the melting of ice.
OR
Option B
I. Precipitate of BaSO4 will not appear as osmosis involves movement
of solvent molecules and not solute.
1
1
1
II. Sugar being non-volatile solute, lowers the vapour pressure above
the solution. This leads to elevation in boiling point.
1
18 I. Ea for backward reaction = 40 kJ/mol, ?H= 10 kJ/mol
II. Catalyst will increase the rate of reaction as the activation energy
required to form intermediate activated complex between reactant and
catalyst is lower than the activation energy required for forming
complex without catalyst.
(for visually challenged learners)
I. The minimum energy required to form the intermediate activated
complex, is known as activation energy (Ea). Activation energy is the
least possible energy required to start a chemical reaction. The
activation energy doesn’t change with change in temperature.
II. Catalyst will increase the rate of reaction as the activation energy
required to form intermediate activated complex between reactant and
catalyst is lower than the activation energy required for forming complex
without catalyst.
1
1
1
1
19 I
II.
C6H5CH2Cl + KCN C6H5CH2CN
LiAlH
4 C6H5CH2CH2NH2
1
1
20 I. [Ag(H2O)2 ][Ag(Cl)2 ]
II. [Ni(OH)2(PPh3)2 ]
1
1
21
1
1
22 ?? ?? ?? = 23.8 mm of Hg
?? = 1molal ,1mol of solute in1000g of water
1mol
B
n ?
1000
55.5mol
18
A
n??
2
2
2
1 0 0
1 0.7 0.7 1.4
MgCl Mg Cl
??
??
?
?? = (?? - 1)/(?? - 1) n=3
? ? 0.7 2 1 i??
= 1.4 + 1 = 2.4
?? ?? ?? - ?? ?? ?? ?? ?? = ?? ?? ?? ?? ?? + ?? ??
23.8 1
2.4
23.8 56.5
Ps ?
?
2.4
23.8 1
56.5
Ps
??
??
??
??
22.9mm of Hg Ps ?
½
½
½
½
½
½
23
I. ?? ???????? = ?? ???????? ?? –
2.303 ????
2?? log
[????
2+
]
[ ????
2+
]
1
Read MoreFAQs on Class 12 Physics: CBSE Marking Scheme (2025-26)
| 1. What is the structure of the Class 12 Physics exam according to the CBSE marking scheme? |  |
Ans. The Class 12 Physics exam structured by CBSE typically consists of two main sections: Section A, which includes objective-type questions such as multiple-choice questions, and Section B, which contains descriptive-type questions. The total marks for the exam are divided among these sections, with an emphasis on practical application and conceptual understanding.
| 2. How are practicals assessed in the Class 12 Physics exam? | |
Ans. Practicals are assessed based on a variety of factors including the accuracy of observations, the ability to conduct experiments, and the clarity of recorded results. Students are required to perform experiments and demonstrate their understanding of concepts through practical work, which contributes a significant portion of the overall marks in the subject.
| 3. What are the key topics covered in the Class 12 Physics syllabus? | |
Ans. The key topics in the Class 12 Physics syllabus include electrostatics, current electricity, magnetic effects of current, electromagnetic induction, optics, dual nature of radiation and matter, atoms and nuclei, and electronic devices. Each topic is designed to build on foundational knowledge while introducing advanced concepts relevant to the field of physics.
| 4. How important is the conceptual understanding of physics for the Class 12 exam? | |
Ans. Conceptual understanding is crucial for success in the Class 12 Physics exam. The questions often test not just rote memorisation but the application of concepts in various scenarios. A strong grasp of the underlying principles allows students to effectively tackle numerical problems and theoretical questions alike, thereby improving their overall performance.
| 5. What preparation strategies should students adopt for the Class 12 Physics exam? | |
Ans. Students should adopt a multifaceted preparation strategy that includes regular revision of concepts, solving previous years' question papers, and conducting practical experiments to reinforce theoretical knowledge. Additionally, forming study groups for discussion and collaborative learning can help clarify doubts and enhance understanding of complex topics, leading to better exam readiness.
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