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Goyal Brothers Textbook Solutions: Nuclear Physics

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Nuclear Physics 
 
Exercise-1 
Question 1. 
Give at least two differences between a chemical change and nuclear change. 
Answer: 
Chemical change 
1. Change in number of orbital electrons takes place. 
2. Requires energy of few eV for a chemical reaction to take place. 
3. Number of atoms of each kind is conserved in reactants and products 
Nuclear change 
1. Change in number of nucleons takes place. 
2. Nuclear change require much higher energy of the order of 10
6
 times as compared 
to chemical change. 
3. Atomic number and mass number is conserved. 
Question 2. 
State Rutherford and Soddy’s Laws of natural radioactive decay for 
(1) alpha emission 
(2) beta emission. 
Answer: 
(1) Rutherford and Soddy’s Law of Alpha Emission : “When a radio-active nuclide ejects 
on alpha particle (a) i.e. 
4
2H, its mass number decreases by 4 and atomic number 
decreases by 2 such that the position of daughter nuclide is two places behind in the 
predictable as compared to the parent nuclide ? 
 
(2) Rutherford and Soddy’s Law of Beta Emission : “When a radio-active nuclide ejects 
a beta particle, its mass number remain Unaffected but Atomic Number Increases by 
one such that the position of the daughter nuclide is one place Ahead in the periodic 
table as compared to the parent nuclei.” The daughter product is Isobar. 
 
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Nuclear Physics 
 
Exercise-1 
Question 1. 
Give at least two differences between a chemical change and nuclear change. 
Answer: 
Chemical change 
1. Change in number of orbital electrons takes place. 
2. Requires energy of few eV for a chemical reaction to take place. 
3. Number of atoms of each kind is conserved in reactants and products 
Nuclear change 
1. Change in number of nucleons takes place. 
2. Nuclear change require much higher energy of the order of 10
6
 times as compared 
to chemical change. 
3. Atomic number and mass number is conserved. 
Question 2. 
State Rutherford and Soddy’s Laws of natural radioactive decay for 
(1) alpha emission 
(2) beta emission. 
Answer: 
(1) Rutherford and Soddy’s Law of Alpha Emission : “When a radio-active nuclide ejects 
on alpha particle (a) i.e. 
4
2H, its mass number decreases by 4 and atomic number 
decreases by 2 such that the position of daughter nuclide is two places behind in the 
predictable as compared to the parent nuclide ? 
 
(2) Rutherford and Soddy’s Law of Beta Emission : “When a radio-active nuclide ejects 
a beta particle, its mass number remain Unaffected but Atomic Number Increases by 
one such that the position of the daughter nuclide is one place Ahead in the periodic 
table as compared to the parent nuclei.” The daughter product is Isobar. 
 
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Question 3. 
Thorium isotope 
223
90Th undergoes two successive ß-decays. Find the mass number and 
atom C number after the decay. Also represent the above decays in the form of a 
nuclear equation. 
Answer: 
After first p decay mass number remains same i.e. 223 but Atomic number increases by 
1 and becomes 91 
 
Two successive P radiations cannot take place. He a radiation takes place which does 
not change mass number or atomic number. 
Now second ß decay 
 
mass number remains 223 atomic number becomes 92. 
Question 4. 
How is the ionising and penetrating powers of a, ß and ? radiations compared with each 
other ? 
Answer: 
Comparison of Ionising power of a, ß,? Heavier particle has high ionising power. 
a ? 10,000 times of a and 100 times of ß 
P ? 100 times of a 
? Maximum ionising power a, minimum ionising power ?. 
Comparison of Penetrating power of a, ß and ? 
Light particle has maximum speed hence maximum penetrating power. 
a has very large penetrating power up to a few hundred meter in air. 
a has small penetrating power (being very heavy) 3 to 8 cm in air 
ß- has large penerating power up to few meter in air a < ß < ?. 
Question 5. 
When does the nucleus of an atom tend to be radioactive? 
Answer: 
Nucleus of an atom become radio-active when increase in nuclear force. 
PACE WITH INCREASE IN THE REPULSIVE FORCE : 
i.e.when there are too many neutrons compared to protons or too many protons 
compared to neutrons in the nucleus of atom. Or The nucleus of the atom becomes 
radioactive if it is a radio-isotope, i.e. number of neutrons in the nucleus exceeds the 
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Nuclear Physics 
 
Exercise-1 
Question 1. 
Give at least two differences between a chemical change and nuclear change. 
Answer: 
Chemical change 
1. Change in number of orbital electrons takes place. 
2. Requires energy of few eV for a chemical reaction to take place. 
3. Number of atoms of each kind is conserved in reactants and products 
Nuclear change 
1. Change in number of nucleons takes place. 
2. Nuclear change require much higher energy of the order of 10
6
 times as compared 
to chemical change. 
3. Atomic number and mass number is conserved. 
Question 2. 
State Rutherford and Soddy’s Laws of natural radioactive decay for 
(1) alpha emission 
(2) beta emission. 
Answer: 
(1) Rutherford and Soddy’s Law of Alpha Emission : “When a radio-active nuclide ejects 
on alpha particle (a) i.e. 
4
2H, its mass number decreases by 4 and atomic number 
decreases by 2 such that the position of daughter nuclide is two places behind in the 
predictable as compared to the parent nuclide ? 
 
(2) Rutherford and Soddy’s Law of Beta Emission : “When a radio-active nuclide ejects 
a beta particle, its mass number remain Unaffected but Atomic Number Increases by 
one such that the position of the daughter nuclide is one place Ahead in the periodic 
table as compared to the parent nuclei.” The daughter product is Isobar. 
 
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Question 3. 
Thorium isotope 
223
90Th undergoes two successive ß-decays. Find the mass number and 
atom C number after the decay. Also represent the above decays in the form of a 
nuclear equation. 
Answer: 
After first p decay mass number remains same i.e. 223 but Atomic number increases by 
1 and becomes 91 
 
Two successive P radiations cannot take place. He a radiation takes place which does 
not change mass number or atomic number. 
Now second ß decay 
 
mass number remains 223 atomic number becomes 92. 
Question 4. 
How is the ionising and penetrating powers of a, ß and ? radiations compared with each 
other ? 
Answer: 
Comparison of Ionising power of a, ß,? Heavier particle has high ionising power. 
a ? 10,000 times of a and 100 times of ß 
P ? 100 times of a 
? Maximum ionising power a, minimum ionising power ?. 
Comparison of Penetrating power of a, ß and ? 
Light particle has maximum speed hence maximum penetrating power. 
a has very large penetrating power up to a few hundred meter in air. 
a has small penetrating power (being very heavy) 3 to 8 cm in air 
ß- has large penerating power up to few meter in air a < ß < ?. 
Question 5. 
When does the nucleus of an atom tend to be radioactive? 
Answer: 
Nucleus of an atom become radio-active when increase in nuclear force. 
PACE WITH INCREASE IN THE REPULSIVE FORCE : 
i.e.when there are too many neutrons compared to protons or too many protons 
compared to neutrons in the nucleus of atom. Or The nucleus of the atom becomes 
radioactive if it is a radio-isotope, i.e. number of neutrons in the nucleus exceeds the 
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number of protons inside it. 
For example : 
 
Question 6. 
Radioactive sodium 
24
11Na changes to stable 
24
12Th Which particle does it eject ? 
Answer: 
P-particle  (
0
-1e ) 
? There is no change in mass number but atomic number of daughter nucleus 
magnesium increases by one. 
Question 7. 
A radioactive element 
A
zX loses two successive ß-particles and then an alpha particle, 
such that the resulting nuclide 
P
QY  is Calculate the values of P and Q. 
Answer: 
 
When 
A
zX loses first ß-particle atomic number of daughter nucleus Y increases by one 
and mass number remains the same 
 
When 
A
z+1X  loses another ß-particle changes to daughter nucleus Z and atomic number 
again increases by one and mass number still remains the same A. 
 
Question 8. 
(a) An imaginary radioactive particle 
235
92X decays to form elements X 1, X 2, X 3, X 4, X 5 and 
X 6 by ejecting 2 beta particles, followed by an alpha particle and again 2 beta particles 
followed by an alpha particle. Represent the above in the form of nuclear equations. 
What is the mass number of X 6 ? 
(b) List the isotopes and isobars formed in the above nuclear reactions. 
Answer: 
(a) 
235
92X when a ß particle is emitter mass number does not change but atomic number 
increases by 1 (isobar) 
? When 2 successive ß particles decay mass number does not change (isobar) but 
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Nuclear Physics 
 
Exercise-1 
Question 1. 
Give at least two differences between a chemical change and nuclear change. 
Answer: 
Chemical change 
1. Change in number of orbital electrons takes place. 
2. Requires energy of few eV for a chemical reaction to take place. 
3. Number of atoms of each kind is conserved in reactants and products 
Nuclear change 
1. Change in number of nucleons takes place. 
2. Nuclear change require much higher energy of the order of 10
6
 times as compared 
to chemical change. 
3. Atomic number and mass number is conserved. 
Question 2. 
State Rutherford and Soddy’s Laws of natural radioactive decay for 
(1) alpha emission 
(2) beta emission. 
Answer: 
(1) Rutherford and Soddy’s Law of Alpha Emission : “When a radio-active nuclide ejects 
on alpha particle (a) i.e. 
4
2H, its mass number decreases by 4 and atomic number 
decreases by 2 such that the position of daughter nuclide is two places behind in the 
predictable as compared to the parent nuclide ? 
 
(2) Rutherford and Soddy’s Law of Beta Emission : “When a radio-active nuclide ejects 
a beta particle, its mass number remain Unaffected but Atomic Number Increases by 
one such that the position of the daughter nuclide is one place Ahead in the periodic 
table as compared to the parent nuclei.” The daughter product is Isobar. 
 
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Question 3. 
Thorium isotope 
223
90Th undergoes two successive ß-decays. Find the mass number and 
atom C number after the decay. Also represent the above decays in the form of a 
nuclear equation. 
Answer: 
After first p decay mass number remains same i.e. 223 but Atomic number increases by 
1 and becomes 91 
 
Two successive P radiations cannot take place. He a radiation takes place which does 
not change mass number or atomic number. 
Now second ß decay 
 
mass number remains 223 atomic number becomes 92. 
Question 4. 
How is the ionising and penetrating powers of a, ß and ? radiations compared with each 
other ? 
Answer: 
Comparison of Ionising power of a, ß,? Heavier particle has high ionising power. 
a ? 10,000 times of a and 100 times of ß 
P ? 100 times of a 
? Maximum ionising power a, minimum ionising power ?. 
Comparison of Penetrating power of a, ß and ? 
Light particle has maximum speed hence maximum penetrating power. 
a has very large penetrating power up to a few hundred meter in air. 
a has small penetrating power (being very heavy) 3 to 8 cm in air 
ß- has large penerating power up to few meter in air a < ß < ?. 
Question 5. 
When does the nucleus of an atom tend to be radioactive? 
Answer: 
Nucleus of an atom become radio-active when increase in nuclear force. 
PACE WITH INCREASE IN THE REPULSIVE FORCE : 
i.e.when there are too many neutrons compared to protons or too many protons 
compared to neutrons in the nucleus of atom. Or The nucleus of the atom becomes 
radioactive if it is a radio-isotope, i.e. number of neutrons in the nucleus exceeds the 
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number of protons inside it. 
For example : 
 
Question 6. 
Radioactive sodium 
24
11Na changes to stable 
24
12Th Which particle does it eject ? 
Answer: 
P-particle  (
0
-1e ) 
? There is no change in mass number but atomic number of daughter nucleus 
magnesium increases by one. 
Question 7. 
A radioactive element 
A
zX loses two successive ß-particles and then an alpha particle, 
such that the resulting nuclide 
P
QY  is Calculate the values of P and Q. 
Answer: 
 
When 
A
zX loses first ß-particle atomic number of daughter nucleus Y increases by one 
and mass number remains the same 
 
When 
A
z+1X  loses another ß-particle changes to daughter nucleus Z and atomic number 
again increases by one and mass number still remains the same A. 
 
Question 8. 
(a) An imaginary radioactive particle 
235
92X decays to form elements X 1, X 2, X 3, X 4, X 5 and 
X 6 by ejecting 2 beta particles, followed by an alpha particle and again 2 beta particles 
followed by an alpha particle. Represent the above in the form of nuclear equations. 
What is the mass number of X 6 ? 
(b) List the isotopes and isobars formed in the above nuclear reactions. 
Answer: 
(a) 
235
92X when a ß particle is emitter mass number does not change but atomic number 
increases by 1 (isobar) 
? When 2 successive ß particles decay mass number does not change (isobar) but 
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atomic number increases by 2. 
Then a-particle decays, mass number decreases by 4 and atomic number decreases by 
2. 
Ultimately when 2 ß particles decays and la-particle decays 
 
This means to change 
235
92X to 
235
92X 1 here, atomic number remains same but mass 
number 
decreases by 4 
? In 6 steps [X ? X 1 ? X 2 ? X 3 ?X 4 ?X 5 ?X 5] 
Atomic number remains same but mass number decreases by 
6 x 4 = 24 
 
(b) After every ß decay isobar is formed and after a-decay isotope is formed 
? Total 12 isobars and 6 isotopes are formed. 
Question 9. 
Give one example of nuclear fission. 
Answer: 
Nuclear power station is example of nuclear fission. Controlled chain reaction takes 
place and electricity is produced. 
Question 10. 
Indicate the missing particle in the following reaction : 
 
Answer: 
 
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Nuclear Physics 
 
Exercise-1 
Question 1. 
Give at least two differences between a chemical change and nuclear change. 
Answer: 
Chemical change 
1. Change in number of orbital electrons takes place. 
2. Requires energy of few eV for a chemical reaction to take place. 
3. Number of atoms of each kind is conserved in reactants and products 
Nuclear change 
1. Change in number of nucleons takes place. 
2. Nuclear change require much higher energy of the order of 10
6
 times as compared 
to chemical change. 
3. Atomic number and mass number is conserved. 
Question 2. 
State Rutherford and Soddy’s Laws of natural radioactive decay for 
(1) alpha emission 
(2) beta emission. 
Answer: 
(1) Rutherford and Soddy’s Law of Alpha Emission : “When a radio-active nuclide ejects 
on alpha particle (a) i.e. 
4
2H, its mass number decreases by 4 and atomic number 
decreases by 2 such that the position of daughter nuclide is two places behind in the 
predictable as compared to the parent nuclide ? 
 
(2) Rutherford and Soddy’s Law of Beta Emission : “When a radio-active nuclide ejects 
a beta particle, its mass number remain Unaffected but Atomic Number Increases by 
one such that the position of the daughter nuclide is one place Ahead in the periodic 
table as compared to the parent nuclei.” The daughter product is Isobar. 
 
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https://www.ncertbooksolutions.com
 
Question 3. 
Thorium isotope 
223
90Th undergoes two successive ß-decays. Find the mass number and 
atom C number after the decay. Also represent the above decays in the form of a 
nuclear equation. 
Answer: 
After first p decay mass number remains same i.e. 223 but Atomic number increases by 
1 and becomes 91 
 
Two successive P radiations cannot take place. He a radiation takes place which does 
not change mass number or atomic number. 
Now second ß decay 
 
mass number remains 223 atomic number becomes 92. 
Question 4. 
How is the ionising and penetrating powers of a, ß and ? radiations compared with each 
other ? 
Answer: 
Comparison of Ionising power of a, ß,? Heavier particle has high ionising power. 
a ? 10,000 times of a and 100 times of ß 
P ? 100 times of a 
? Maximum ionising power a, minimum ionising power ?. 
Comparison of Penetrating power of a, ß and ? 
Light particle has maximum speed hence maximum penetrating power. 
a has very large penetrating power up to a few hundred meter in air. 
a has small penetrating power (being very heavy) 3 to 8 cm in air 
ß- has large penerating power up to few meter in air a < ß < ?. 
Question 5. 
When does the nucleus of an atom tend to be radioactive? 
Answer: 
Nucleus of an atom become radio-active when increase in nuclear force. 
PACE WITH INCREASE IN THE REPULSIVE FORCE : 
i.e.when there are too many neutrons compared to protons or too many protons 
compared to neutrons in the nucleus of atom. Or The nucleus of the atom becomes 
radioactive if it is a radio-isotope, i.e. number of neutrons in the nucleus exceeds the 
Downloaded from https://www.ncertbooksolutions.com/
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number of protons inside it. 
For example : 
 
Question 6. 
Radioactive sodium 
24
11Na changes to stable 
24
12Th Which particle does it eject ? 
Answer: 
P-particle  (
0
-1e ) 
? There is no change in mass number but atomic number of daughter nucleus 
magnesium increases by one. 
Question 7. 
A radioactive element 
A
zX loses two successive ß-particles and then an alpha particle, 
such that the resulting nuclide 
P
QY  is Calculate the values of P and Q. 
Answer: 
 
When 
A
zX loses first ß-particle atomic number of daughter nucleus Y increases by one 
and mass number remains the same 
 
When 
A
z+1X  loses another ß-particle changes to daughter nucleus Z and atomic number 
again increases by one and mass number still remains the same A. 
 
Question 8. 
(a) An imaginary radioactive particle 
235
92X decays to form elements X 1, X 2, X 3, X 4, X 5 and 
X 6 by ejecting 2 beta particles, followed by an alpha particle and again 2 beta particles 
followed by an alpha particle. Represent the above in the form of nuclear equations. 
What is the mass number of X 6 ? 
(b) List the isotopes and isobars formed in the above nuclear reactions. 
Answer: 
(a) 
235
92X when a ß particle is emitter mass number does not change but atomic number 
increases by 1 (isobar) 
? When 2 successive ß particles decay mass number does not change (isobar) but 
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atomic number increases by 2. 
Then a-particle decays, mass number decreases by 4 and atomic number decreases by 
2. 
Ultimately when 2 ß particles decays and la-particle decays 
 
This means to change 
235
92X to 
235
92X 1 here, atomic number remains same but mass 
number 
decreases by 4 
? In 6 steps [X ? X 1 ? X 2 ? X 3 ?X 4 ?X 5 ?X 5] 
Atomic number remains same but mass number decreases by 
6 x 4 = 24 
 
(b) After every ß decay isobar is formed and after a-decay isotope is formed 
? Total 12 isobars and 6 isotopes are formed. 
Question 9. 
Give one example of nuclear fission. 
Answer: 
Nuclear power station is example of nuclear fission. Controlled chain reaction takes 
place and electricity is produced. 
Question 10. 
Indicate the missing particle in the following reaction : 
 
Answer: 
 
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Question 11. 
Complete the statement given below : 
Splitting of nucleus into two nearly lighter nuclei is called 
Answer: 
Splitting of nucleus into two nearly lighter nuclei is called nuclear fission. 
Question 12. 
Name the fuel generally used in nuclear reactors. 
Answer: 
Enriched Uranium 
235
92U is used as fuel in nuclear reactor. 
Question 13. 
Give one example of a controlled and uncontrolled nuclear fission reaction. 
Answer: 
Example of:      
1. Controlled nuclear fission reaction is to generate electricity in nuclear thermal 
plant. 
2. Uncontrolled nuclear fission reaction is production of ATOM BOMB. 
Question 14. 
Name the isotopes of an element which are used in fusion 
Answer: 
ISOTOPES of ELEMENT HYDROGEN are : 
1
1H protium 
2
1H deuterium 
3
1H Tritium 
Question 15. 
What is meant by nuclear chain reaction ? What happens, if this reaction goes out of 
control ? 
Answer: 
NUCLEAR CHAIN REACTION : A piece of URANIUM consists of millions of uranium 
atoms. When a slow moving neutron is bombarded, it produces three neutrons, if these 
neutrons are utilised to break further uranium atoms, 9 neutrons are produced and in 
this way a kind of chain reaction takes place with release of large amount of energy and 
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