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CPT Section D, Quantitative Aptitude, Chapter 13
Prof(Dr.) P .R.Vittal
Page 2
CPT Section D, Quantitative Aptitude, Chapter 13
Prof(Dr.) P .R.Vittal
Page 3
CPT Section D, Quantitative Aptitude, Chapter 13
Prof(Dr.) P .R.Vittal
(a)2/9
(b)1/4
(c)4/9
(d)1/3
Answer: a
Answer :
Sample space
S={[1,3],[2,4],[3,5],[4,6],[3,1],[4,2],[5,3],
[6,4]}
P(difference is 2 )=8/36 = 2/9
Answer : (a)
Page 4
CPT Section D, Quantitative Aptitude, Chapter 13
Prof(Dr.) P .R.Vittal
(a)2/9
(b)1/4
(c)4/9
(d)1/3
Answer: a
Answer :
Sample space
S={[1,3],[2,4],[3,5],[4,6],[3,1],[4,2],[5,3],
[6,4]}
P(difference is 2 )=8/36 = 2/9
Answer : (a)
(a)3/10
(b)2 /5
(c)1/5
(d)1/4
Answer:c
Solution
:p(A)=1/2,p(A’)=1/2,p(B)=3/5,p(
B’)=2/5
P(neither of them solves the
problem)=p(A’)p(B’)=(1/2).(2/5)
=1/5
Answer: (c)
Page 5
CPT Section D, Quantitative Aptitude, Chapter 13
Prof(Dr.) P .R.Vittal
(a)2/9
(b)1/4
(c)4/9
(d)1/3
Answer: a
Answer :
Sample space
S={[1,3],[2,4],[3,5],[4,6],[3,1],[4,2],[5,3],
[6,4]}
P(difference is 2 )=8/36 = 2/9
Answer : (a)
(a)3/10
(b)2 /5
(c)1/5
(d)1/4
Answer:c
Solution
:p(A)=1/2,p(A’)=1/2,p(B)=3/5,p(
B’)=2/5
P(neither of them solves the
problem)=p(A’)p(B’)=(1/2).(2/5)
=1/5
Answer: (c)
a)2 /5
(b)1/5
(c)3/5
(d)3/11
Answer: d
Solution :Since the total probability is 1,
p(A)+p(B)+p(C)=1. Hence we have
2p(B)+p(B)+(2/3)(p(B)=1
P(B)=3/11
Answer: (d)
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FAQs on MCQ - Probability - Quantitative Aptitude for CA Foundation
| 1. What is probability and how is it relevant to the CA Foundation exam? |  |
Ans. Probability is a branch of mathematics that deals with the likelihood of events occurring. In the context of the CA Foundation exam, understanding probability is crucial as it is a topic covered in the syllabus. Questions related to probability can be asked in various subjects such as Mathematics or Statistics, and having a strong grasp of probability concepts will help you solve these questions accurately.
| 2. What are the basic principles of probability? | |
Ans. The basic principles of probability are:
1. The probability of any event lies between 0 and 1, inclusive.
2. The sum of the probabilities of all possible outcomes in a sample space is equal to 1.
3. The probability of the complement of an event is equal to 1 minus the probability of the event.
4. The probability of two mutually exclusive events occurring is equal to the sum of their individual probabilities.
Understanding these principles will help you in calculating probabilities and solving probability-related questions in the CA Foundation exam.
| 3. How can I calculate the probability of an event? | |
Ans. The probability of an event can be calculated using the formula:
Probability of an event = Number of favorable outcomes / Total number of possible outcomes
To apply this formula, you need to determine the number of favorable outcomes and the total number of possible outcomes. By dividing the number of favorable outcomes by the total number of possible outcomes, you can obtain the probability of the event.
| 4. What is the difference between independent and dependent events in probability? | |
Ans. In probability, independent events are those where the occurrence or non-occurrence of one event does not affect the occurrence or non-occurrence of another event. For example, if you flip a coin twice, the outcome of the first flip does not impact the outcome of the second flip.
On the other hand, dependent events are those where the occurrence or non-occurrence of one event affects the occurrence or non-occurrence of another event. For example, drawing cards from a deck without replacement, where the probability of drawing a certain card changes after each draw.
Understanding the difference between independent and dependent events is important as it helps in determining the probability of multiple events occurring together.
| 5. Can you provide an example of a probability calculation in the context of the CA Foundation exam? | |
Ans. Sure! Let's consider an example: In a class of 30 students, 15 are boys and 15 are girls. If a student is selected at random, what is the probability of selecting a girl?
Number of favorable outcomes = 15 (number of girls)
Total number of possible outcomes = 30 (total number of students)
Probability of selecting a girl = 15/30 = 0.5
Therefore, the probability of selecting a girl in this scenario is 0.5 or 50%.
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