An X - ray tube is operated at a constant potential difference and it is required to get X - ray of wavelength not less then 0. 2 nano-metres. Then the potential difference in kilo-volts is [ h = 6.63 x 10-34 J − sec ; e = 1.6 x 10-19 C ; c = 3x 108 m s-1 ]
  • a)
    24. 8
  • b)
    12. 4
  • c)
    6. 2
  • d)
    3.1
Correct answer is option 'C'. Can you explain this answer?
Related Test: VITEEE Physics Test - 3

JEE Question

Genius
Nov 07, 2020
Just apply the formula !


V= hc/λe, where λ is wavelength= 2×10-¹⁰


put the value of h, c, λ & e, you will get the correct answer.

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