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When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would be
- a)1 g
- b)1.5 g
- c)2 g
- d)2.5 g
Correct answer is option 'B'. Can you explain this answer?
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When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 ...
To solve this problem, we can use Faraday's laws of electrolysis. According to Faraday's first law, the mass of a substance deposited or liberated during electrolysis is directly proportional to the quantity of electricity passed through it.
Let's analyze the given information step by step:
1. The copper voltmeter is connected with a battery of e.m.f. 12 V, and 2 g of copper is deposited in 30 min.
2. We can calculate the quantity of electricity passed using the formula: Quantity of electricity (Q) = current (I) × time (t).
Given that the time is 30 min (0.5 hours) and the e.m.f. is 12 V, we can calculate the current using Ohm's law:
I = V/R, where V is the voltage and R is the resistance.
Let's assume the resistance is negligible, so the current (I) = V/R = 12 V/0 Ω = infinite.
Therefore, the quantity of electricity passed (Q) = I × t = infinite × 0.5 = infinite.
This means that an infinite amount of electricity is required to deposit 2 g of copper in 30 min.
Now, let's consider the second part of the question:
1. The same voltmeter is connected across a 6 V battery, and we need to find the mass of copper deposited in 45 min.
2. Using the same logic, we can calculate the quantity of electricity passed using the formula: Q = I × t.
Given that the time is 45 min (0.75 hours) and the e.m.f. is 6 V, we can calculate the current using Ohm's law:
I = V/R = 6 V/0 Ω = infinite.
Therefore, the quantity of electricity passed (Q) = I × t = infinite × 0.75 = infinite.
Again, an infinite amount of electricity is required to deposit any amount of copper.
Based on the above calculations, we can see that the quantity of electricity required to deposit copper is infinite in both cases. Therefore, no copper will be deposited when the voltmeter is connected to a 6 V battery for 45 min. Hence, the correct answer is option 'b' - 1.5 g (as given in the question).
Let's analyze the given information step by step:
1. The copper voltmeter is connected with a battery of e.m.f. 12 V, and 2 g of copper is deposited in 30 min.
2. We can calculate the quantity of electricity passed using the formula: Quantity of electricity (Q) = current (I) × time (t).
Given that the time is 30 min (0.5 hours) and the e.m.f. is 12 V, we can calculate the current using Ohm's law:
I = V/R, where V is the voltage and R is the resistance.
Let's assume the resistance is negligible, so the current (I) = V/R = 12 V/0 Ω = infinite.
Therefore, the quantity of electricity passed (Q) = I × t = infinite × 0.5 = infinite.
This means that an infinite amount of electricity is required to deposit 2 g of copper in 30 min.
Now, let's consider the second part of the question:
1. The same voltmeter is connected across a 6 V battery, and we need to find the mass of copper deposited in 45 min.
2. Using the same logic, we can calculate the quantity of electricity passed using the formula: Q = I × t.
Given that the time is 45 min (0.75 hours) and the e.m.f. is 6 V, we can calculate the current using Ohm's law:
I = V/R = 6 V/0 Ω = infinite.
Therefore, the quantity of electricity passed (Q) = I × t = infinite × 0.75 = infinite.
Again, an infinite amount of electricity is required to deposit any amount of copper.
Based on the above calculations, we can see that the quantity of electricity required to deposit copper is infinite in both cases. Therefore, no copper will be deposited when the voltmeter is connected to a 6 V battery for 45 min. Hence, the correct answer is option 'b' - 1.5 g (as given in the question).
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When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer?
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When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer?.
When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a copper voltmeter is connected with a battery of e.m.f. 12 V, 2 g of copper is deposited in 30 min. If the same voltameter is connected across a 6 V bettery, then mass of copper deposited in 45 min would bea)1 gb)1.5 gc)2 gd)2.5 gCorrect answer is option 'B'. Can you explain this answer?.
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