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When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.
Then x1 : x2 will be:
Then x1 : x2 will be:
- a)1: √2
- b)√2: 1
- c)1: √3
- d)1: 2√3
Correct answer is option 'C'. Can you explain this answer?
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When an object is shot from the bottom of a long smooth inclined plane...
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When an object is shot from the bottom of a long smooth inclined plane...
Degrees to the horizontal, it will move up the inclined plane to a certain height before coming back down due to gravity. The distance it travels up the inclined plane and the height it reaches depend on the initial velocity of the object and the angle and length of the inclined plane.
To determine the distance the object travels up the inclined plane, we can use the formula:
distance = (initial velocity^2 x sin(2*angle))/g
where g is the acceleration due to gravity (9.81 m/s^2).
To determine the height the object reaches, we can use the formula:
height = (initial velocity^2 x sin^2(angle))/(2g)
where g is again the acceleration due to gravity.
For example, if the initial velocity of the object is 10 m/s and the inclined plane is 20 meters long, the distance the object travels up the inclined plane would be:
distance = (10^2 x sin(2*60))/9.81 = 10.19 meters
The height the object reaches would be:
height = (10^2 x sin^2(60))/(2 x 9.81) = 5.10 meters
Therefore, the object would travel up the inclined plane for 10.19 meters and reach a height of 5.10 meters before coming back down due to gravity.
To determine the distance the object travels up the inclined plane, we can use the formula:
distance = (initial velocity^2 x sin(2*angle))/g
where g is the acceleration due to gravity (9.81 m/s^2).
To determine the height the object reaches, we can use the formula:
height = (initial velocity^2 x sin^2(angle))/(2g)
where g is again the acceleration due to gravity.
For example, if the initial velocity of the object is 10 m/s and the inclined plane is 20 meters long, the distance the object travels up the inclined plane would be:
distance = (10^2 x sin(2*60))/9.81 = 10.19 meters
The height the object reaches would be:
height = (10^2 x sin^2(60))/(2 x 9.81) = 5.10 meters
Therefore, the object would travel up the inclined plane for 10.19 meters and reach a height of 5.10 meters before coming back down due to gravity.
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When an object is shot from the bottom of a long smooth inclined plane...
S1/S2=gsin30/gsin60=1/√3
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When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.Then x1 : x2 will be:a)1:√2b)√2: 1c)1:√3d)1: 2√3Correct answer is option 'C'. Can you explain this answer?
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When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.Then x1 : x2 will be:a)1:√2b)√2: 1c)1:√3d)1: 2√3Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.Then x1 : x2 will be:a)1:√2b)√2: 1c)1:√3d)1: 2√3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance.Then x1 : x2 will be:a)1:√2b)√2: 1c)1:√3d)1: 2√3Correct answer is option 'C'. Can you explain this answer?.
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