For a normal eye, the cornea of eye provides aconverging power of 40D and the leastconverging power of the eye lens behind thecornea is 20D. Using this information, thedistance between the retina and the eye lens ofthe eye can be estimated to be [NEET 2013]
  • a)
    2.5 cm
  • b)
    1.67 cm
  • c)
    1.5 cm
  • d)
    5 cm
Correct answer is option 'A'. Can you explain this answer?

Class 12 Question

Lakshmi Bharia answered May 27, 2020
Here, P1 = 40D
P2 = 20D
f eq =?

P eq = P1+ P2
= 40+20
=60D

f eq = 100/ P eq =. 100/60 = 1.67 cm.

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