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The area of an equilateral triangle of side 14 cm is
  • a)
    49√3 cm2
  • b)
    56√3 cm2
  • c)
    58√3 cm
  • d)
    18 cm2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The area of an equilateral triangle of side 14 cm isa)49√3 cm2b)...
Side=14cm
area of equilateral triangle=(√3/4)×a^2 where a=side
using this formula,
(√3/4) × 14 ×14=49√3 cm^2
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Community Answer
The area of an equilateral triangle of side 14 cm isa)49√3 cm2b)...
We can see that If we split equilateral triangle in half,we are left with two equilateral congorent triangle.thus ,one of the legs of the triangle is 1/2s ,and the hypotenuse is s. we can use the Pythagorean theorem or the properties of 30degree-60 degree -90 degree triangles to determine that the height of the triangle is under root 3 upon 2 s .if we want to determine the area of the entire triangle , we know that a=1/2bh . we also know that the base is s and height is under root 3 upon 2s ,so we can plug those into the area equation to see the following for an equilateral triangle a=halfbh =half s (under root 3 upon 2s )=s2 under root 3 upon 4 .since,in your case, s=14 the area of triangle is 14squre under root 3 upon 4= 196 under root3 upon 4 =49 under root 3.
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