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In a region with a uniform electric field, the number of lines of force per unit area is E. If a spherical metallic condcutor is placed in the area, the field inside the conductor will be
  • a)
    zero
  • b)
    E
  • c)
    more than E
  • d)
    less than E
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a region with a uniform electric field, the number of lines of forc...
There is no field inside a metallic conductor  E = 0
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In a region with a uniform electric field, the number of lines of forc...
Explanation:
There are several key points to consider in the explanation of why the electric field inside a spherical conductor placed in a uniform electric field is zero:

Gauss's Law:
- According to Gauss's Law, the net electric field inside a conductor at electrostatic equilibrium is zero.
- This means that when a conductor is placed in a uniform electric field, the electric field inside the conductor will be zero.

Distribution of Charges:
- When a conductor is placed in an electric field, the free charges in the conductor will rearrange themselves in such a way that the electric field inside the conductor cancels out the external electric field.
- This redistribution of charges results in an induced electric field inside the conductor that opposes the external electric field.

Electrostatic Equilibrium:
- In electrostatic equilibrium, the charges on the surface of the conductor will redistribute themselves in such a way that the electric field inside the conductor is zero.
- This ensures that there is no net movement of charges within the conductor, and the system is at equilibrium.
Therefore, when a spherical conductor is placed in a uniform electric field, the electric field inside the conductor will be zero.
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In a region with a uniform electric field, the number of lines of force per unit area is E. If a spherical metallic condcutor is placed in the area, the field inside the conductor will bea)zerob)Ec)more than Ed)less than ECorrect answer is option 'A'. Can you explain this answer?
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