Tiw stone are poject from the top of a tower 100m high each with the velocity of 20m/s. One is pojected vertically upwards and another vertically downwards. Calculate the time each stone takes to reach the ground and the velocity with which it strikes the ground.?

Class 9 Question

Shrish Raj answered 4 weeks ago
PLZ FIRST CORRECT THE SPELLINGS

Stone projected vertically upward


height upto which it goes above(h) can be calculated as
v^2=u^2+2aS
v=0{final speed will be zero at the top}, a= negative{against gravity}
u^2=2aS
20�20= 2�10� h
h=20
total height from which it fall in the end= 100+20
=120
height travelled = ut + 1/2gt^2
120= 0+1/2�10t^2
t^2=24
t=2√6sec
v^2=u^2 +2a(total height)
v^2=0+ 2�10�120
v=20√6


stone projected vertically downward

v^2=u^2+2aH
v^2=20�20+ 2�10�100
=400+2000
=2400
v=20√6
v=u+gt
20√6=20+10t
2√6-2=t

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