A child was born on 13th January 1976 which was a Tuesday. What day of the week will be the child‘s birth day in the year 1986?
  • a)
    Sunday
  • b)
    Friday
  • c)
    Saturday
  • d)
    Monday
Correct answer is option 'D'. Can you explain this answer?

CLAT Question

Mahathi Chitluri
Sep 18, 2019

Anushka Somepalli
Sep 22, 2019
Bcz every year the same date we increase +1 and if it is leap year we increase +2 then finally the answer is monday

Kunal Vats
Sep 18, 2019
2 years(2 days)+ 1 leap year have(2days) = 4 odd days.
so, 1976- 1979= 4 odd days.
1979 - 1982= 4odd days.
1982 -1985= 4 odd days.
1985 - 1986= 1 odd day.
total odd days = 4+4+4+1 = 13/7= 6 odd days.
=6 odd days. Birthday = Tuesday +6days = Monday.

Smita Singh
Aug 04, 2020
As year 1976 is a leap year. Similarly, 1980, 1984 are two leap year. Hence, 13th January 1986 will be Monday.

Because, the date it falls is one day behind next year.

1986 is a leap year and every leap year has one day back against the given date

Ashish Gaming
2 weeks ago
A, sabse pahle man lo 1986 ko 1985 fir, 1985 ko tor do 1600+300+85 ... fir odd day sbka nikalo.... 1600=0
300=1
85=85/4= 21 leap year×2 + 85-21=64
=107
then divide 107/7 , remainder=2 + 13 jan =15 days
so 15 days will be monday

King Soni
Aug 27, 2020
Saturday or sunday

Nisha
Oct 10, 2020
The answer is D because the day increases by +1 every year and +2 for leap year and in between 1976 and 1986 it contains two leap years so we will add +1 for every year and extra +2 for leap year. so START adding days in Tuesday for +12 days so the answer is Monday!

Jisna Joseph
Nov 13, 2020
13 th jan 1976 - Tus
1976 -1986[11 days difference ]
and and also 2 days (because of the leap day in feb )
so the total days are 13 (11+2=13)
2weeks = 14 days
difference= 13days
ie, 13 th jan 1976= Tus
To find 13 th jan 1986=14-13=1 day
= Tus- 1= monday
so the ans is monday

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