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A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?
- a)32 kmph
- b)16 kmph
- c)12 kmph
- d)48 kmph
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A journey of 192 km takes 2 hours less by a fast train than by a slow ...
Solve this question using the values given in the options. Option (d) can be seen to fit the situation
given by the problem as it gives us the following chain of thought:
If the average speed of the faster train is 48 kmph, the average speed of the slower train would be
32 kmph. In this case, the time taken by the faster train (192/48 = 4 hours) is 2 hours lesser than
the time taken by the slower train (192/32 = 6 hours). This satisfies the condition given in the
problem and hence option (d) is correct.
given by the problem as it gives us the following chain of thought:
If the average speed of the faster train is 48 kmph, the average speed of the slower train would be
32 kmph. In this case, the time taken by the faster train (192/48 = 4 hours) is 2 hours lesser than
the time taken by the slower train (192/32 = 6 hours). This satisfies the condition given in the
problem and hence option (d) is correct.
Most Upvoted Answer
A journey of 192 km takes 2 hours less by a fast train than by a slow ...
Given:
Total distance = 192 km
Time taken by fast train = Time taken by slow train - 2 hours
Average speed of slow train = Average speed of fast train - 16 kmph
To find:
Average speed of fast train
Solution:
Let the speed of slow train be x kmph
Then, the speed of fast train = (x + 16) kmph
We know that,
Time = Distance/Speed
Time taken by slow train = 192/x hours
Time taken by fast train = 192/(x+16) hours
According to the given condition,
Time taken by fast train = Time taken by slow train - 2 hours
192/(x+16) = 192/x - 2
Multiplying both sides by x(x+16),
192x - 2x(x+16) = 192(x+16)
Simplifying the above equation,
192x - 2x^2 - 32x - 3072 = 0
2x^2 - 160x + 3072 = 0
x^2 - 80x + 1536 = 0
x = 32 or 48
As the average speed of slow train cannot be greater than the average speed of fast train, x = 32 kmph
Therefore, the average speed of fast train = x + 16 = 32 + 16 = 48 kmph
Hence, the correct option is (d) 48 kmph.
Total distance = 192 km
Time taken by fast train = Time taken by slow train - 2 hours
Average speed of slow train = Average speed of fast train - 16 kmph
To find:
Average speed of fast train
Solution:
Let the speed of slow train be x kmph
Then, the speed of fast train = (x + 16) kmph
We know that,
Time = Distance/Speed
Time taken by slow train = 192/x hours
Time taken by fast train = 192/(x+16) hours
According to the given condition,
Time taken by fast train = Time taken by slow train - 2 hours
192/(x+16) = 192/x - 2
Multiplying both sides by x(x+16),
192x - 2x(x+16) = 192(x+16)
Simplifying the above equation,
192x - 2x^2 - 32x - 3072 = 0
2x^2 - 160x + 3072 = 0
x^2 - 80x + 1536 = 0
x = 32 or 48
As the average speed of slow train cannot be greater than the average speed of fast train, x = 32 kmph
Therefore, the average speed of fast train = x + 16 = 32 + 16 = 48 kmph
Hence, the correct option is (d) 48 kmph.
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A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer?
Question Description
A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer?.
A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train?a)32 kmphb)16 kmphc)12 kmphd)48 kmphCorrect answer is option 'D'. Can you explain this answer?.
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