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In how many ways 4 men and 4 women can be seated in a row so that men and women are alternate?
  • a)
    28
  • b)
    36
  • c)
    4!.4!
  • d)
    2.4!.4!
Correct answer is option 'D'. Can you explain this answer?
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To solve this problem, we can use the concept of permutations.

Step 1: Identify the number of ways to arrange the men and women separately
Since there are 4 men and 4 women, we can arrange them amongst themselves in 4! ways. This means that there are 4! ways to arrange the men and 4! ways to arrange the women.

Step 2: Determine the number of ways to arrange the men and women alternately
To arrange the men and women alternately, we need to consider them as a single unit. Therefore, we have 2 units - one unit consisting of the 4 men and the other unit consisting of the 4 women.

Step 3: Find the number of ways to arrange the 2 units
Since there are 2 units, we can arrange them in 2! ways.

Step 4: Multiply the results from Step 1, Step 2, and Step 3
To find the total number of ways to arrange the men and women alternately, we need to multiply the number of ways to arrange the men, women, and the units together. Therefore, the total number of ways is given by:
4! * 4! * 2!

Simplifying this expression, we get:
4! = 4*3*2*1 = 24
2! = 2*1 = 2

Multiplying these values, we get:
24 * 24 * 2 = 1152

Therefore, the correct answer is option D) 2.4!.4!, which is equal to 1152.
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In how many ways 4 men and 4 women can be seated in a row so that men and women are alternate?a)28b)36c)4!.4!d)2.4!.4!Correct answer is option 'D'. Can you explain this answer?
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