A stone with mass 1kgis whirled in a horizontal circle of radius 1mwith a period of revolution equal to 1s. What value of orbital angular momentum quantum no.ldescribes this motion? (in 1034)Correct answer is '5.96'. Can you explain this answer?

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A stone with mass 1kg is whirled in a horizontal circle of radius 1m with a period of revolution equal to 1s. What value of orbital angular momentum quantum no. l describes this motion? (in 10³⁴)

Correct answer is '5.96'. Can you explain this answer?

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A stone with mass 1kgis whirled in a horizontal circle of radius 1mwit...

The speed of the stone in its orbit is

Angular momentum = mvr = 1kg × 6.28 m/s × 1m
= 6.28 kg m²/s

For classical objects the quantum numbers are excessively big

The correct answer is: 5.96

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A stone with mass 1kgis whirled in a horizontal circle of radius 1mwith a period of revolution equal to 1s. What value of orbital angular momentum quantum no.ldescribes this motion? (in 1034)Correct answer is '5.96'. Can you explain this answer?

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