Solution:
To find the number of ways of arranging the given digits without repetition, we can use the concept of permutation.

Permutation: The number of ways of arranging n distinct objects taken r at a time is given by nPr = n!/(n-r)!, where n! represents the factorial of n.

In this problem, we have 4 distinct digits and we want to arrange them without repetition. So, the number of ways of arranging them is given by:
4P4 = 4!/(4-4)! = 4! = 24

Therefore, there are 24 numbers that can be formed with the digits 1, 7, 2, 5 without repetition.

But, we need to note that the question asks for the number of numbers that can be formed, not the number of arrangements. This means that we need to exclude the arrangements where the digits are rearranged in the same order.

For example, if we arrange the digits 1, 7, 2, 5 in the order 1, 7, 2, 5, we get the number 1725. If we rearrange the digits in any other order, we still get the same number. So, we need to exclude such arrangements.

To find the number of such arrangements, we can use the concept of combination.

Combination: The number of ways of selecting r objects from n distinct objects is given by nCr = n!/r!(n-r)!, where n! represents the factorial of n.

In this problem, we want to select 4 digits from 4 distinct digits. So, the number of ways of selecting them is given by:
4C4 = 4!/(4-4)!4! = 1

Therefore, there is only 1 arrangement where the digits are arranged in the same order.

So, the number of numbers that can be formed with the digits 1, 7, 2, 5 without repetition is:
24 - 1 = 23

Therefore, the correct option is (c) 64.