As per the given data, ⇒ a – b = 3 Squaring on both sides, we get ⇒ a^{2} + b^{2} - 2ab = 9 ⇒ 29 – 2ab = 9 ⇒ 29 – 9 = 2ab ⇒ 20 = 2ab ⇒ ab = 10 We know that (a + b)^{2} = a^{2} + b^{2} + 2ab ⇒ (a + b)^{2} = 29 + 2(10) = 49 ⇒ a + b = √49 = ±7
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