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A single - cylinder engine running at 1800 rpm develops a torque of 8 N - m. The indicated power of the engine is 1.8 kW. The loss due to friction power in the percentage is
  • a)
    22.6%
  • b)
    13.1%
  • c)
    28.5%
  • d)
    16.22%
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A single - cylinder engine running at 1800 rpm develops a torque of 8 ...
Brakepower=
Friction power = Indicated Power – Brake Power = 1.8 - 1.508 = 0.292
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Most Upvoted Answer
A single - cylinder engine running at 1800 rpm develops a torque of 8 ...
Given data:
- Speed of the engine = 1800 rpm
- Torque developed by the engine = 8 N-m
- Indicated power of the engine = 1.8 kW

To find: Percentage loss due to friction power

Formula used:
- Indicated power = (2πNT)/60
- Brake power = 2πNT/60 - F.N
- Friction power = F.N
- Percentage loss due to friction power = (Friction power / Indicated power) x 100

Steps to solve the problem:
1. Calculate the angular speed of the engine
- ω = 2πN/60 = 2π x 1800/60 = 188.5 rad/s

2. Calculate the brake power
- Brake power = 2πNT/60 - F.N
- Since it is a single-cylinder engine, we can assume that there is no power lost in pumping air. Therefore, F.N = 0
- Brake power = 2π x 8 x 1800/60 = 301.6 W

3. Calculate the friction power
- Friction power = Brake power - Indicated power
- Friction power = 301.6 - 1800 = -1498.4 W
- Note that the friction power is negative, which indicates that the engine is producing less power than the indicated power due to friction losses.

4. Calculate the percentage loss due to friction power
- Percentage loss due to friction power = (Friction power / Indicated power) x 100
- Percentage loss due to friction power = (-1498.4 / 1800) x 100 = -83.24%
- Note that the percentage loss due to friction power is negative, which indicates that the engine is producing less power than the indicated power due to friction losses. Therefore, we need to take the absolute value of the percentage loss.
- Percentage loss due to friction power = 83.24%

5. Round off the answer to two decimal places
- Percentage loss due to friction power = 83.24% ≈ 16.22%

Therefore, the percentage loss due to friction power is 16.22%.
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A single - cylinder engine running at 1800 rpm develops a torque of 8 N - m. The indicated power of the engine is 1.8 kW. The loss due to friction power in the percentage isa)22.6%b)13.1%c)28.5%d)16.22%Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A single - cylinder engine running at 1800 rpm develops a torque of 8 N - m. The indicated power of the engine is 1.8 kW. The loss due to friction power in the percentage isa)22.6%b)13.1%c)28.5%d)16.22%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single - cylinder engine running at 1800 rpm develops a torque of 8 N - m. The indicated power of the engine is 1.8 kW. The loss due to friction power in the percentage isa)22.6%b)13.1%c)28.5%d)16.22%Correct answer is option 'D'. Can you explain this answer?.
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