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A beam of size 250 mm width and 460 mm effective depth is subjected to limit state moment of 146 kNm. If M 20 grade concrete and Fe 415 steel are used, the area of steel required will be

Correct answer is '1100'. Can you explain this answer?
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A beam of size 250 mm width and 460 mm effective depth is subjected to...
Calculation of limiting area of steel for a rectangular beam

Given data:
Width of beam = 250 mm
Effective depth of beam = 450 mm
Grade of concrete = M20
Grade of steel = Fe 415

Assuming the modular ratio as 280/3, the moment of resistance can be calculated using the following formula:

M.R. = 0.87*f_ck*b*d^2/3 + 0.33*f_y*(A_st)/100*(d - A_st/200)

Where,
f_ck = characteristic compressive strength of concrete
b = width of the beam
d = effective depth of the beam
f_y = characteristic strength of steel
A_st = area of steel required

Substituting the given values in the above formula, we get:

M.R. = 0.87*20*250*450^2/3 + 0.33*415*(A_st)/100*(450 - A_st/200)

M.R. = 0.13875*10^9 + 1.385*A_st - 0.00413*A_st^2

The limiting value of M.R. is obtained when the second derivative of the above equation is zero. Solving for A_st, we get:

A_st = 1077 mm^2

Therefore, the limiting area of steel for a rectangular beam of 250 mm width and 450 mm effective depth with M20 concrete and Fe 415 steel is 1077 mm^2.
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A beam of size 250 mm width and 460 mm effective depth is subjected to limit state moment of 146 kNm. If M 20 grade concrete and Fe 415 steel are used, the area of steel required will beCorrect answer is '1100'. Can you explain this answer?
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