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A four-stroke petrol engine at full load delivers 50 kW. It requires 8.5 kW to rotate it without load at the same speed. Find its mechanical efficiency (in %) at half load.
  • a)
    65
  • b)
    75
  • c)
    80
  • d)
    50
Correct answer is option 'B'. Can you explain this answer?
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A four-stroke petrol engine at full load delivers 50 kW. It requires 8...
Mechanical efficiency at half load =        
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A four-stroke petrol engine at full load delivers 50 kW. It requires 8...
Given data:
Full load power, P1 = 50 kW
Power required to rotate without load, P2 = 8.5 kW
Load at which mechanical efficiency is to be determined, P = 25 kW (half load)

Mechanical efficiency of the engine is given by the ratio of output power to input power.

Mechanical Efficiency = Output Power / Input Power

Output Power = P
Input Power = P + Power required to rotate without load = P + P2

Substituting the given values, we get:
Output Power = 25 kW
Input Power = 25 kW + 8.5 kW = 33.5 kW

Mechanical Efficiency = (Output Power / Input Power) x 100%
Mechanical Efficiency = (25 kW / 33.5 kW) x 100%
Mechanical Efficiency = 74.63% (approx)

Therefore, the mechanical efficiency of the engine at half load is 75% (option B).
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