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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are –0.76,–0.23 and –0.44 V respectively.
The reaction X+Y2+ →X2++Y will be spontaneous when :
  • a)
    X = Ni, Y = Fe
  • b)
    X = Ni, Y = Zn
  • c)
    X= Fe, Y = Zn
  • d)
    X= Zn, Y = Ni
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are...
For a spontaneous reaction DG must be –ve
Since ΔG = – nFE°
Hence for ΔG to be -ve ΔE° has to be positive. Which is possible when X = Zn, Y = Ni
Zn + Ni++ →  Zn++ + Ni
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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are –0.76,–0.23 and –0.44 V respectively.The reaction X+Y2+ →X2++Y will be spontaneous when :a)X = Ni, Y = Feb)X = Ni, Y = Znc)X= Fe, Y = Znd)X= Zn, Y = NiCorrect answer is option 'D'. Can you explain this answer?
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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are –0.76,–0.23 and –0.44 V respectively.The reaction X+Y2+ →X2++Y will be spontaneous when :a)X = Ni, Y = Feb)X = Ni, Y = Znc)X= Fe, Y = Znd)X= Zn, Y = NiCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are –0.76,–0.23 and –0.44 V respectively.The reaction X+Y2+ →X2++Y will be spontaneous when :a)X = Ni, Y = Feb)X = Ni, Y = Znc)X= Fe, Y = Znd)X= Zn, Y = NiCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard reduction potentials for Zn2+/Zn, Ni2+/Ni and Fe2+/Fe are –0.76,–0.23 and –0.44 V respectively.The reaction X+Y2+ →X2++Y will be spontaneous when :a)X = Ni, Y = Feb)X = Ni, Y = Znc)X= Fe, Y = Znd)X= Zn, Y = NiCorrect answer is option 'D'. Can you explain this answer?.
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