80 Answers

Sudhanshu Yadav
answered
Jul 28, 2020

Given,

AB work together in=10 days

therefore, in 1 day they work =1/10part

A along can do same work in = 15 days

therefore, in 15 day A can work =1/15 part

hence B can do same work in=??

AB work =A+B

1/10 =1/15+B

1/10-1/15 =B

3-2/30 =B

1/30. =B

In 1 day B can do his work=1/30part

therefore B complete his work in 30 days

AB work together in=10 days

therefore, in 1 day they work =1/10part

A along can do same work in = 15 days

therefore, in 15 day A can work =1/15 part

hence B can do same work in=??

AB work =A+B

1/10 =1/15+B

1/10-1/15 =B

3-2/30 =B

1/30. =B

In 1 day B can do his work=1/30part

therefore B complete his work in 30 days

Noor Mohammed
answered
May 09, 2020

A+B's complete work =10 ,there for A+B ,s complete in one day=1/10 ,A alone can do the in 1=1/15 , equitation 1/10+1/15=3-2/30 =1/30=30

Kusum Lata
answered
May 13, 2020

Sol: A and B together work in 10 days

(A+B)'s one day work = 1/10 part

A's one day work = 1/15 part

work done by B in a day =

= 1/10- 1/15

= 3-2/30

= 1/30 part

Ans: Alone work done by B is 30 days

(A+B)'s one day work = 1/10 part

A's one day work = 1/15 part

work done by B in a day =

= 1/10- 1/15

= 3-2/30

= 1/30 part

Ans: Alone work done by B is 30 days

Haasini Guntuka
answered
Mar 27, 2020

(a+b) 1 day = 1/10

a alone = 1/15

b =?

b= 1/10 - 1/15

b =1/10*3-1/15*3 (eqvivalent)

b = 3/30-2/30

b= 1/30

So,

b alone would take 30 days

a alone = 1/15

b =?

b= 1/10 - 1/15

b =1/10*3-1/15*3 (eqvivalent)

b = 3/30-2/30

b= 1/30

So,

b alone would take 30 days

Ananya Kumar
answered
Jul 23, 2020

(A+B) complete their work in 10 days

(A+B) 1 day's work = 1/10

A's 1 day work = 1/15

B's 1 day work = 1/10 - 1/15

Â»Â»Â» 1/10 Ã— 3/3 = 3/30

1/15 Ã— 2/2 = 2/30

â€ºâ€ºâ€º 3-2/30 = 1/30

B completes his work in 30 days.

(A+B) 1 day's work = 1/10

A's 1 day work = 1/15

B's 1 day work = 1/10 - 1/15

Â»Â»Â» 1/10 Ã— 3/3 = 3/30

1/15 Ã— 2/2 = 2/30

â€ºâ€ºâ€º 3-2/30 = 1/30

B completes his work in 30 days.

Seema Rani
answered
Apr 29, 2020

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Kritika Jain
answered
Aug 24, 2020

(A+B+C)'s one days's work=

10

1

â€‹

So (A+B+C)'s 4 day's work=

10

4

â€‹

=

5

2

â€‹

Remaining part of the work=1âˆ’

5

2

â€‹

=

5

3

â€‹

âˆµ

5

3

â€‹

part of the work done by (B+C)= 10 days

âˆ´ 1 work done by (B+C)=

5

3

â€‹

10

â€‹

=

3

50

â€‹

Days

âˆ´A alone work=

10

1

â€‹

âˆ’

50

3

â€‹

=

25

1

â€‹

Hence A alone complete the work in 25 days.

10

1

â€‹

So (A+B+C)'s 4 day's work=

10

4

â€‹

=

5

2

â€‹

Remaining part of the work=1âˆ’

5

2

â€‹

=

5

3

â€‹

âˆµ

5

3

â€‹

part of the work done by (B+C)= 10 days

âˆ´ 1 work done by (B+C)=

5

3

â€‹

10

â€‹

=

3

50

â€‹

Days

âˆ´A alone work=

10

1

â€‹

âˆ’

50

3

â€‹

=

25

1

â€‹

Hence A alone complete the work in 25 days.

Nithin Rakoti
answered
Jun 17, 2020

We can conclude the answer as 30days

B can do the work in 30 days

B can do the work in 30 days

Shlok Mishra
answered
Jul 31, 2020

A and B one day work= 1/10

A's one day work= 1/15

B's one day work= 1/10 - 1/15

= 3 - 2/30

= 1/30

# B can do that work in 30 Days.

A's one day work= 1/15

B's one day work= 1/10 - 1/15

= 3 - 2/30

= 1/30

# B can do that work in 30 Days.

Saanvitha Reddy
answered
Aug 18, 2020

n 10 days A + B can so = 1 work

In 1 day A+B can do = 1/10 work

In 15 days A can do = 1 work

In 1 day A can do = 1/15 work

Let in x days B can do = 1 work

so in 1day B can do 1/x work

In 1 day A+B can do = 1/10 work

1/15 + 1/x = 1/10

1/x = 1/10 - 1/15

1/x = 1/30

x = 30

Hence B can finish the work in 30 days

Prachi Sagar
answered
Aug 23, 2020

(A+B)Complete their work in 10 days.

(A+B)1 day's work =1/10

A's1 day work=1/15

3-2/30=1/30

B complete his work in 30 days

(A+B)1 day's work =1/10

A's1 day work=1/15

3-2/30=1/30

B complete his work in 30 days

Aman Kumar
answered
Aug 23, 2020

A and B can do a piece of work in 10 days.

Therefore A and B together can do 1/10 of work in one day.

A + B = 1/10â€¦Eq..1

A alone can complete this work in 15 days. Thus A alone can do this work in 1/15.

Substituting the value of work done by A in Eq..1

A + B = 1/10

1/15 + B = 1/10

B = 1/10 - 1/15

B = (3 - 2)/30

B = 1/30

Thus, B can accomplish 1/30 of work in one day.

Accordingly, B alone could complete this work in 30 days.

Answer B alone could complete this work in 30 days

Therefore A and B together can do 1/10 of work in one day.

A + B = 1/10â€¦Eq..1

A alone can complete this work in 15 days. Thus A alone can do this work in 1/15.

Substituting the value of work done by A in Eq..1

A + B = 1/10

1/15 + B = 1/10

B = 1/10 - 1/15

B = (3 - 2)/30

B = 1/30

Thus, B can accomplish 1/30 of work in one day.

Accordingly, B alone could complete this work in 30 days.

Answer B alone could complete this work in 30 days

Mayank Raj
answered
Aug 24, 2020

If A and B take 10 days to complete 1 work

so A and B take 1 day to complete 1/10 work

A alone take 15 days to complete 1 work

so A take 1 days to complete 1/15 work

so B take 1 day to complete 1/10-1/15=1/30

if 1/30 work B can do in 1 day

so 1 work complete in 1Ã·1/30=30 days

so A and B take 1 day to complete 1/10 work

A alone take 15 days to complete 1 work

so A take 1 days to complete 1/15 work

so B take 1 day to complete 1/10-1/15=1/30

if 1/30 work B can do in 1 day

so 1 work complete in 1Ã·1/30=30 days

Shivansh Tiwari
answered
Jul 31, 2020

A and B together do the work in 10 days

it means A's+B's one day work = 1/10

given that A alone can do work in 15 days

it means A's one day work= 1/15

so B's one day work= 1/10 - 1/15 = 1/30

B's one day work=1/30

so time taken by B to complete whole work will be 30 days

it means A's+B's one day work = 1/10

given that A alone can do work in 15 days

it means A's one day work= 1/15

so B's one day work= 1/10 - 1/15 = 1/30

B's one day work=1/30

so time taken by B to complete whole work will be 30 days