The ratio of the present age of father to that of son is 7:2. After 10 years their ages will be in the ratio of 9:4. The present ages of the father is

- a)35 years
- b)40 years
- c)30 years
- d)25 years

Correct answer is option 'A'. Can you explain this answer?

Related Test: Test: Ratio And Proportion, Indices, Logarithms - 1

By
Vaishnavi Mane
·
2 weeks ago ·CA Foundation

2 Answers

NANDINI WALIA
answered
Feb 21, 2020

Let father age be X and son age be Y. Then

X/Y = 7/2

2X = 7Y ..... (1)

After ten years ,

(X+10)/(Y+10) = 9/4

4(X+10) = 9(Y+10)

4X + 40 = 9Y + 90

4X = 9Y + 50

2×2X = 9Y + 50

putting the value to 2X by equation 1

2×7Y = 9Y + 50

14Y = 9Y + 50

5Y = 50

Y = 10

Son age is 10 years .

putting the value of Y in equation 1

2X = 7Y

X = 7/2Y

X = 7/2×10

X = 70/2

X = 35

Father age is 35.

X/Y = 7/2

2X = 7Y ..... (1)

After ten years ,

(X+10)/(Y+10) = 9/4

4(X+10) = 9(Y+10)

4X + 40 = 9Y + 90

4X = 9Y + 50

2×2X = 9Y + 50

putting the value to 2X by equation 1

2×7Y = 9Y + 50

14Y = 9Y + 50

5Y = 50

Y = 10

Son age is 10 years .

putting the value of Y in equation 1

2X = 7Y

X = 7/2Y

X = 7/2×10

X = 70/2

X = 35

Father age is 35.

Jaya Chatterjee
answered
Feb 06, 2020

Let father age be X and son age be Y. Then

X/Y = 7/2

2X = 7Y ..... (1)

After ten years ,

(X+10)/(Y+10) = 9/4

4(X+10) = 9(Y+10)

4X + 40 = 9Y + 90

4X = 9Y + 50

2Ã—2X = 9Y + 50

putting the value to 2X by equation 1

2Ã—7Y = 9Y + 50

14Y = 9Y + 50

5Y = 50

Y = 10

Son age is 10 years .

putting the value of Y in equation 1

2X = 7Y

X = 7/2Y

X = 7/2Ã—10

X = 70/2

X = 35

Father age is 35.

X/Y = 7/2

2X = 7Y ..... (1)

After ten years ,

(X+10)/(Y+10) = 9/4

4(X+10) = 9(Y+10)

4X + 40 = 9Y + 90

4X = 9Y + 50

2Ã—2X = 9Y + 50

putting the value to 2X by equation 1

2Ã—7Y = 9Y + 50

14Y = 9Y + 50

5Y = 50

Y = 10

Son age is 10 years .

putting the value of Y in equation 1

2X = 7Y

X = 7/2Y

X = 7/2Ã—10

X = 70/2

X = 35

Father age is 35.

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