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A, B, C and D are four consecutive odd numbers and their average is 42. What is the product of B and D?
  • a)
    1860
  • b)
    1890
  • c)
    1845
  • d)
    1677
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A, B, C and D are four consecutive odd numbers and their average is 42...
Work done by A and B in 12 days is
12[112*5/4]=12*5/120=.5
As diff. Is same so average should lie between B and C so B is 41 & C is 43 so D must be 45 as we have to find the product of B and D so it would be 1845
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Community Answer
A, B, C and D are four consecutive odd numbers and their average is 42...
To solve this problem, we need to find the values of A, B, C, and D, and then calculate the product of B and D.

Let's assume that A is the first odd number in the sequence. Since the numbers are consecutive odd numbers, we can represent the other numbers as A + 2, A + 4, and A + 6.

We know that the average of these four numbers is 42. The average is calculated by adding all the numbers and dividing the sum by the number of terms. In this case, the sum of the four numbers is A + (A + 2) + (A + 4) + (A + 6).

So, the equation to find the average is:
(A + (A + 2) + (A + 4) + (A + 6)) / 4 = 42

Simplifying the equation, we have:
4A + 12 = 168

Subtracting 12 from both sides, we get:
4A = 156

Dividing both sides by 4, we get:
A = 39

Now that we have the value of A, we can find the other numbers in the sequence:
B = A + 2 = 39 + 2 = 41
C = A + 4 = 39 + 4 = 43
D = A + 6 = 39 + 6 = 45

Finally, we can calculate the product of B and D:
B * D = 41 * 45 = 1845

Therefore, the answer is option C) 1845.
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