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# then g(x) hasa)local maxima at x = 1 + ln 2 and local minima at x = eb)local maxima at x = 1 and local minima at x = 2c)no local maximad)no local minimaCorrect answer is option 'A,B'. Can you explain this answer? Related Test: Multiple Correct MCQ Of Applications Of Derivatives, Past Year Questions JEE Advance, Class 12, Maths

## JEE Question Chander Bhan Oct 15, 2020   ∴ g ''(1 + ln 2) =-2 and g ''(e) = 1⇒ g (x) has local max. at x = 1 + ln 2 and local min. at x = e. Also graph of g '(x) suggests, g (x) has local max. at x = 1 and local min. at x = 2 Ashish Khanda Jan 22, 2021
Correct is A and B

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