Six pipes are fitted to a water tank. Some of these are inlet pipes an...
Given information:
- Six pipes are fitted to a water tank.
- Some of these are inlet pipes and the others outlet pipes.
- Each inlet pipe can fill the tank in 9 hrs and each outlet pipe can empty the tank in 6 hrs.
- On opening all the pipes, an empty tank is filled in 9 hrs.
To find:
- How many inlet pipes are there?
Approach:
- Let the number of inlet pipes be x.
- Total pipes are 6, so the number of outlet pipes will be 6-x.
- Inlet pipe fills the tank in 9 hrs, so in 1 hour, it fills 1/9th part of the tank.
- Outlet pipe empties the tank in 6 hrs, so in 1 hour, it empties 1/6th part of the tank.
- On opening all the pipes, an empty tank is filled in 9 hrs, so the net filling rate is 1/9 - 1/6 = 1/18.
Calculation:
- Considering x inlet pipes, the net filling rate will be x/9 - (6-x)/6 = (2x-27)/18.
- As per the given condition, the net filling rate is 1/18, i.e., (2x-27)/18 = 1/18.
- Solving this equation, we get 2x - 27 = 1, i.e., x = 14/2 = 7.
Conclusion:
- The number of inlet pipes is 7-x = 7-7 = 0.
- So, there are no inlet pipes.
- The correct option is (B) 4 inlet pipes, which is not possible as per the given conditions.
- Hence, there is no correct option among the given choices.
Six pipes are fitted to a water tank. Some of these are inlet pipes an...