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2.25N force is acting on 15×10-4C charage placed at a point in a uniform electric field.so intensity of this electric field is?
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2.25N force is acting on 15×10-4C charage placed at a point in a unifo...
Since, E= F/q
(Given) F= 2.25 N
q = 15×10^-4 C
-->E = 2.25/ 15×10^-4
=1500 N/C
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2.25N force is acting on 15×10-4C charage placed at a point in a uniform electric field.so intensity of this electric field is?
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