Civil Engineering (CE) Exam  >  Civil Engineering (CE) Questions  >  Traffic flow equation for a section of road i... Start Learning for Free
Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow is
  • a)
    4572 vph
  • b)
    2286 vph
  • c)
    1143 vph
  • d)
    572 vph
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Traffic flow equation for a section of road is u = 80 - 0.7 K where &l...
Traffic flow equation:
u = 80 - 0.7k
Since flow, q = u · k = 80 k - 0.7 k2
This question is part of UPSC exam. View all Civil Engineering (CE) courses
Most Upvoted Answer
Traffic flow equation for a section of road is u = 80 - 0.7 K where &l...
U is the speed in km/h and K is the traffic density in vehicles per km.

This equation represents the relationship between traffic speed and traffic density. As traffic density increases, the speed of traffic decreases. The maximum speed (u) that can be achieved on the road is 80 km/h when there are no vehicles (K=0). As traffic density increases, the speed decreases at a rate of 0.7 km/h per additional vehicle per km.

This equation can be used to model traffic flow and predict the impact of changes in traffic density on traffic speed. It is important to note that this equation represents an idealized scenario and does not take into account other factors that can impact traffic flow, such as road conditions, weather, and driver behavior.
Explore Courses for Civil Engineering (CE) exam

Similar Civil Engineering (CE) Doubts

Top Courses for Civil Engineering (CE)

Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer?
Question Description
Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Traffic flow equation for a section of road is u = 80 - 0.7 K where ‘u’ is the speed in kmph and ‘K’ is the density in vpkm (vehicles per km). The maximum expected flow isa)4572 vphb)2286 vphc)1143 vphd)572 vphCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev