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Suppose T(n) = 2T(n/2) + n, T(0) = T(1) = 1 Which one of the following is FALSE?
  • a)
    T(n) = 0(n2)
  • b)
  • c)
    T(n) - Ω(n2)
  • d)
    T(n) = O(nlogn)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Suppose T(n) = 2T(n/2) + n, T(0) = T(1) = 1 Which one of the following...
T(0)= T(1) = 1 
T(n) = 2T(n/2) + n
T(n) be computed as follows:
[T(n) can also proved by Master Theorem]
if  then it is also 0(n logn) and O(n2) but it is not Ω(n2).
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Most Upvoted Answer
Suppose T(n) = 2T(n/2) + n, T(0) = T(1) = 1 Which one of the following...
T(0)= T(1) = 1 
T(n) = 2T(n/2) + n
T(n) be computed as follows:
[T(n) can also proved by Master Theorem]
if  then it is also 0(n logn) and O(n2) but it is not Ω(n2).
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Community Answer
Suppose T(n) = 2T(n/2) + n, T(0) = T(1) = 1 Which one of the following...
T(0)= T(1) = 1 
T(n) = 2T(n/2) + n
T(n) be computed as follows:
[T(n) can also proved by Master Theorem]
if  then it is also 0(n logn) and O(n2) but it is not Ω(n2).
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