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In photoelectric emission process from a metal of work function 1.8 eV, the
kinetic energy of most energetic electrons is 0.5 eV. The corresponding stopping
potential is
kinetic energy of most energetic electrons is 0.5 eV. The corresponding stopping
potential is
- a)2.3 V
- b)1.8 V
- c)1.3 V
- d)0.5 V
Correct answer is option 'D'. Can you explain this answer?
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In photoelectric emission process from a metal of work function 1.8 eV...
Photoelectric Emission Process from a Metal
In the photoelectric effect, when light of suitable frequency or energy is incident on a metal surface, electrons are emitted from the metal. This phenomenon is known as photoelectric emission. The energy required to remove an electron from the metal is called the work function.
The work function of a metal is the minimum amount of energy required to release an electron from the surface of the metal. It is denoted by the symbol Φ (phi) and is measured in electron volts (eV).
Kinetic Energy of Most Energetic Electrons
In the given question, it is mentioned that the work function of the metal is 1.8 eV and the kinetic energy of the most energetic electrons is 0.5 eV.
The kinetic energy (KE) of an electron is given by the equation:
KE = hf - Φ
Where:
- KE is the kinetic energy of the electron
- h is the Planck's constant (6.626 x 10^-34 J.s or 4.136 x 10^-15 eV.s)
- f is the frequency of the incident light
- Φ is the work function of the metal
Since the work function is the minimum amount of energy required to release an electron, the kinetic energy of the most energetic electrons will be the difference between the energy of the incident photons and the work function.
Therefore, we can rewrite the equation as:
KE = hf - Φ
0.5 eV = hf - 1.8 eV
Calculating the Stopping Potential
The stopping potential (V) is the minimum potential required to stop the emission of photoelectrons. It can be calculated using the equation:
V = KE/e
Where:
- V is the stopping potential
- KE is the kinetic energy of the electron
- e is the elementary charge (1.6 x 10^-19 C or 1 eV)
Substituting the given values, we can calculate the stopping potential:
V = 0.5 eV / 1 eV
V = 0.5 V
Therefore, the correct answer is option 'D' - 0.5 V.
In the photoelectric effect, when light of suitable frequency or energy is incident on a metal surface, electrons are emitted from the metal. This phenomenon is known as photoelectric emission. The energy required to remove an electron from the metal is called the work function.
The work function of a metal is the minimum amount of energy required to release an electron from the surface of the metal. It is denoted by the symbol Φ (phi) and is measured in electron volts (eV).
Kinetic Energy of Most Energetic Electrons
In the given question, it is mentioned that the work function of the metal is 1.8 eV and the kinetic energy of the most energetic electrons is 0.5 eV.
The kinetic energy (KE) of an electron is given by the equation:
KE = hf - Φ
Where:
- KE is the kinetic energy of the electron
- h is the Planck's constant (6.626 x 10^-34 J.s or 4.136 x 10^-15 eV.s)
- f is the frequency of the incident light
- Φ is the work function of the metal
Since the work function is the minimum amount of energy required to release an electron, the kinetic energy of the most energetic electrons will be the difference between the energy of the incident photons and the work function.
Therefore, we can rewrite the equation as:
KE = hf - Φ
0.5 eV = hf - 1.8 eV
Calculating the Stopping Potential
The stopping potential (V) is the minimum potential required to stop the emission of photoelectrons. It can be calculated using the equation:
V = KE/e
Where:
- V is the stopping potential
- KE is the kinetic energy of the electron
- e is the elementary charge (1.6 x 10^-19 C or 1 eV)
Substituting the given values, we can calculate the stopping potential:
V = 0.5 eV / 1 eV
V = 0.5 V
Therefore, the correct answer is option 'D' - 0.5 V.
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In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer?
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In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer?.
In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In photoelectric emission process from a metal of work function 1.8 eV, thekinetic energy of most energetic electrons is 0.5 eV. The corresponding stoppingpotential isa)2.3 Vb)1.8 Vc)1.3 Vd)0.5 VCorrect answer is option 'D'. Can you explain this answer?.
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