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If the average daily water consumption of a city is 24000 cum, the peak hourly demand (of the maximum day) will be
- a)1000 cum/hr
- b)1500 cum/hr
- c)1800 cum/hr
- d)2700 cum/hr
Correct answer is option 'D'. Can you explain this answer?
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If the average daily water consumption of a city is 24000 cum, the pea...
Maximum hourly consumption of the maximum day i.e. peak demand
Most Upvoted Answer
If the average daily water consumption of a city is 24000 cum, the pea...
Given data:
- Average daily water consumption of a city = 24000 cum
To find:
- Peak hourly demand (of the maximum day)
Solution:
To find the peak hourly demand, we need to consider the maximum day when the demand is at its highest.
Let's assume that the demand on the maximum day is x cum/hr.
We know that the average daily water consumption is 24000 cum. Therefore, the total water consumption on the maximum day will be 24000 cum.
We also know that the demand is at its peak for one hour on the maximum day. Therefore, the total water consumed in that one hour will be equal to the peak hourly demand, which is x cum/hr.
Now, we can set up the following equation to solve for x:
Total water consumed on the maximum day = Peak hourly demand × Number of hours in the day
24000 cum = x cum/hr × 24 hr
x = 24000/24
x = 1000 cum/hr
Therefore, the peak hourly demand on the maximum day is 1000 cum/hr.
However, the correct answer given in the options is D, which is 2700 cum/hr. This answer is incorrect as it does not match with the calculation above. It is possible that there is an error in the options provided.
Conclusion:
- The peak hourly demand (of the maximum day) for an average daily water consumption of 24000 cum is 1000 cum/hr.
- Average daily water consumption of a city = 24000 cum
To find:
- Peak hourly demand (of the maximum day)
Solution:
To find the peak hourly demand, we need to consider the maximum day when the demand is at its highest.
Let's assume that the demand on the maximum day is x cum/hr.
We know that the average daily water consumption is 24000 cum. Therefore, the total water consumption on the maximum day will be 24000 cum.
We also know that the demand is at its peak for one hour on the maximum day. Therefore, the total water consumed in that one hour will be equal to the peak hourly demand, which is x cum/hr.
Now, we can set up the following equation to solve for x:
Total water consumed on the maximum day = Peak hourly demand × Number of hours in the day
24000 cum = x cum/hr × 24 hr
x = 24000/24
x = 1000 cum/hr
Therefore, the peak hourly demand on the maximum day is 1000 cum/hr.
However, the correct answer given in the options is D, which is 2700 cum/hr. This answer is incorrect as it does not match with the calculation above. It is possible that there is an error in the options provided.
Conclusion:
- The peak hourly demand (of the maximum day) for an average daily water consumption of 24000 cum is 1000 cum/hr.
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If the average daily water consumption of a city is 24000 cum, the peak hourly demand (of the maximum day) will bea)1000 cum/hrb)1500 cum/hrc)1800 cum/hrd)2700 cum/hrCorrect answer is option 'D'. Can you explain this answer?
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