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If the nominal shear stress (ζv) at a section does not exceed the permissible shear stress (τc)
- a)minimum shear reinforcement is still provided
- b)shear reinforcement is provided to resist the nominal shear stress
- c)no shear reinforcement is provided
- d)shear reinforcement is provided for the difference of the two
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If the nominal shear stress (ζv) at a section does not exceed the...
If the calculated shear stress ( ζv ) is
(i) less than allowable shear stress (ζc) but more than 0.5ζc, the minimum shear reinforcement in the form of stirrups shall be provided such that,
(i) less than allowable shear stress (ζc) but more than 0.5ζc, the minimum shear reinforcement in the form of stirrups shall be provided such that,
(ii) more than ζc, shear reinforcement shall be provided in the form of vertical stirrups or bent up bars with stirrups or inclined stirrups to resist
Hence option (A) is correct
To learn basics about stress click on the link given below:
Most Upvoted Answer
If the nominal shear stress (ζv) at a section does not exceed the...
Τ) on a material is given in pounds per square inch (psi) and the material's thickness (t) is given in inches, then the formula to calculate the shear force (F) required to shear the material is:
F = τ * A
where A is the area of the material being sheared, given by:
A = t * w
where w is the width of the material. Therefore, the general formula for calculating the shear force required to shear a rectangular material is:
F = τ * t * w
For example, if a material has a nominal shear stress of 10,000 psi and a thickness of 0.5 inches, and the width of the material is 2 inches, then the shear force required to shear the material would be:
F = 10,000 psi * 0.5 in * 2 in
F = 5,000 pounds
Therefore, a force of 5,000 pounds would be required to shear this material under these conditions.
F = τ * A
where A is the area of the material being sheared, given by:
A = t * w
where w is the width of the material. Therefore, the general formula for calculating the shear force required to shear a rectangular material is:
F = τ * t * w
For example, if a material has a nominal shear stress of 10,000 psi and a thickness of 0.5 inches, and the width of the material is 2 inches, then the shear force required to shear the material would be:
F = 10,000 psi * 0.5 in * 2 in
F = 5,000 pounds
Therefore, a force of 5,000 pounds would be required to shear this material under these conditions.
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Question Description
If the nominal shear stress (ζv) at a section does not exceed the permissible shear stress (τc)a)minimum shear reinforcement is still providedb)shear reinforcement is provided to resist the nominal shear stressc)no shear reinforcement is providedd)shear reinforcement is provided for the difference of the twoCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2026 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If the nominal shear stress (ζv) at a section does not exceed the permissible shear stress (τc)a)minimum shear reinforcement is still providedb)shear reinforcement is provided to resist the nominal shear stressc)no shear reinforcement is providedd)shear reinforcement is provided for the difference of the twoCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the nominal shear stress (ζv) at a section does not exceed the permissible shear stress (τc)a)minimum shear reinforcement is still providedb)shear reinforcement is provided to resist the nominal shear stressc)no shear reinforcement is providedd)shear reinforcement is provided for the difference of the twoCorrect answer is option 'A'. Can you explain this answer?.
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