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A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?
- a)12 km
- b)23 km
- c)45 km
- d)65 km
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level...
lets us consider t1 = time taken on level road. t2 = uphill. t3 = down hill; the distance traveled uphill and down hill same so t2*3 = 6*t3; => t2 = 2t3;---> (1) total time = 2*t1 + t2 + t3 = 6 hours ---> (2) 2t1+3t3 = 6 -->(3) total distance = 2*(4t1) + 3*t2+ 6*t3 ---> (4) substitute (1) in (4) 8t1 + 12t3 => 4(2t1+3t3) then from (3) the total distance will become 4*6= 24 => one way distance = 12km
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Community Answer
A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level...
Given information:
- Start time = 3 pm
- End time = 9 pm
- Speed on level ground = 4 km/hr
- Speed uphill = 3 km/hr
- Speed downhill = 6 km/hr
To find: Distance covered on one way
Approach:
Let's assume that the man walked the same distance on level ground, uphill and downhill.
Let's say, he walked for x hours on level ground, y hours uphill and z hours downhill.
Total time taken = 9 pm - 3 pm = 6 hours
We can write the following equation based on the given information:
x + y + z = 6 ----- (1)
Distance covered on level ground = 4x km
Distance covered uphill = 3y km
Distance covered downhill = 6z km
Total distance covered = Distance on level ground + Distance uphill + Distance downhill
Total distance covered = 4x + 3y + 6z ----- (2)
Now, we need another equation to solve for x, y and z. Let's use the fact that the man reaches home at the end.
Distance covered in the first 3 hours = 3 x 4 = 12 km
Distance covered in the last 3 hours = 4 x (6 - 3) = 12 km
Using equation (2), we can say:
4x + 3y + 6z = 12 + 12
4x + 3y + 6z = 24 ----- (3)
We have 3 equations and 3 variables. We can solve them simultaneously.
Solving equations (1), (2) and (3), we get:
x = 2 hours
y = 1 hour
z = 1 hour
Therefore, distance covered on level ground = 4x = 4 x 2 = 8 km (on one way)
Total distance covered = 8 + 3 + 6 = 17 km (on one way)
Since we need to find distance covered on one way, the answer is 8 km.
Hence, option A is the correct answer.
- Start time = 3 pm
- End time = 9 pm
- Speed on level ground = 4 km/hr
- Speed uphill = 3 km/hr
- Speed downhill = 6 km/hr
To find: Distance covered on one way
Approach:
Let's assume that the man walked the same distance on level ground, uphill and downhill.
Let's say, he walked for x hours on level ground, y hours uphill and z hours downhill.
Total time taken = 9 pm - 3 pm = 6 hours
We can write the following equation based on the given information:
x + y + z = 6 ----- (1)
Distance covered on level ground = 4x km
Distance covered uphill = 3y km
Distance covered downhill = 6z km
Total distance covered = Distance on level ground + Distance uphill + Distance downhill
Total distance covered = 4x + 3y + 6z ----- (2)
Now, we need another equation to solve for x, y and z. Let's use the fact that the man reaches home at the end.
Distance covered in the first 3 hours = 3 x 4 = 12 km
Distance covered in the last 3 hours = 4 x (6 - 3) = 12 km
Using equation (2), we can say:
4x + 3y + 6z = 12 + 12
4x + 3y + 6z = 24 ----- (3)
We have 3 equations and 3 variables. We can solve them simultaneously.
Solving equations (1), (2) and (3), we get:
x = 2 hours
y = 1 hour
z = 1 hour
Therefore, distance covered on level ground = 4x = 4 x 2 = 8 km (on one way)
Total distance covered = 8 + 3 + 6 = 17 km (on one way)
Since we need to find distance covered on one way, the answer is 8 km.
Hence, option A is the correct answer.
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Question Description
A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?a)12 km b)23 km c)45 km d)65 kmCorrect answer is option 'A'. Can you explain this answer? for Quant 2026 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?a)12 km b)23 km c)45 km d)65 kmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?a)12 km b)23 km c)45 km d)65 kmCorrect answer is option 'A'. Can you explain this answer?.
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